All PSAT Math Resources
Example Questions
Example Question #1 : Right Triangles
and is a right angle.
Which angle or angles must be complementary to ?
I)
II)
III)
IV)
V)
II only
I only
II and V only
I and III only
IV only
II and V only
is a right angle, and, since corresponding angles of similar triangles are congruent, so is . A right angle cannot be part of a complementary pair so both can be eliminated.
can be eliminated, since it is congruent to ; congruent angles are not necessarily complementary.
Since is right angle, is a right triangle, and and are its acute angles. That makes complementary to . Since is congruent to , it is also complementary to .
The correct response is II and V only.
Example Question #1 : How To Find If Right Triangles Are Similar
Refer to the above figure. Given that , give the perimeter of .
By the Pythagorean Theorem,
The similarity ratio of to is
,
which is subsequently the ratio of the perimeter of to that of .
The perimeter of is
,
so the perimeter of can be found using this ratio:
Example Question #2 : How To Find If Right Triangles Are Similar
Note: Figure NOT drawn to scale.
Refer to the above figure. Given that , give the area of .
The correct answer is not among the other responses.
By the Pythagorean Theorem,
The similarity ratio of to is
,
This can be used to find :
The area of is therefore
Example Question #2 : How To Find If Right Triangles Are Similar
Note: Figures NOT drawn to scale.
Refer to the above figure. Given that , evaluate .
By the Pythagorean Theorem, since is the hypotenuse of a right triangle with legs 6 and 8, its measure is
.
The similarity ratio of to is
.
Likewise,
Example Question #1 : How To Find The Length Of The Side Of A Right Triangle
A right triangle has one side equal to 5 and its hypotenuse equal to 14. Its third side is equal to:
14.87
12
9
13.07
171
13.07
The Pythagorean Theorem gives us a2 + b2 = c2 for a right triangle, where c is the hypotenuse and a and b are the smaller sides. Here a is equal to 5 and c is equal to 14, so b2 = 142 – 52 = 171. Therefore b is equal to the square root of 171 or approximately 13.07.
Example Question #1 : How To Find The Length Of The Side Of A Right Triangle
Which of the following could NOT be the lengths of the sides of a right triangle?
5, 12, 13
12, 16, 20
8, 15, 17
5, 7, 10
14, 48, 50
5, 7, 10
We use the Pythagorean Theorem and we calculate that 25 + 49 is not equal to 100.
All of the other answer choices observe the theorem a2 + b2 = c2
Example Question #1 : How To Find The Length Of The Side Of A Right Triangle
Which set of sides could make a right triangle?
6, 7, 8
4, 6, 9
9, 12, 15
10, 12, 16
9, 12, 15
By virtue of the Pythagorean Theorem, in a right triangle the sum of the squares of the smaller two sides equals the square of the largest side. Only 9, 12, and 15 fit this rule.
Example Question #11 : How To Find The Length Of The Side Of A Right Triangle
A right triangle with a base of 12 and hypotenuse of 15 is shown below. Find x.
4
3.5
5
4.5
5.5
4
Using the Pythagorean Theorem, the height of the right triangle is found to be = √(〖15〗2 –〖12〗2) = 9, so x=9 – 5=4
Example Question #131 : Plane Geometry
A right triangle has sides of 36 and 39(hypotenuse). Find the length of the third side
42
12 √6
33√2
15
33
15
use the pythagorean theorem:
a2 + b2 = c2 ; a and b are sides, c is the hypotenuse
a2 + 1296 = 1521
a2 = 225
a = 15
Example Question #1 : How To Find The Length Of The Side Of A Right Triangle
Bob the Helicopter is at 30,000 ft. above sea level, and as viewed on a map his airport is 40,000 ft. away. If Bob travels in a straight line to his airport at 250 feet per second, how many minutes will it take him to arrive?
4 hours and 0 minutes
3 minutes and 20 seconds
3 minutes and 50 seconds
2 hours and 30 minutes
1 hour and 45 minutes
3 minutes and 20 seconds
Draw a right triangle with a height of 30,000 ft. and a base of 40,000 ft. The hypotenuse, or distance travelled, is then 50,000ft using the Pythagorean Theorem. Then dividing distance by speed will give us time, which is 200 seconds, or 3 minutes and 20 seconds.
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