\(\displaystyle \frac{2}{3}+\frac{1}2{}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{2}{3}\times\frac{2}{2}=\frac{4}{6}\)

\(\displaystyle \frac{1}{2}\times\frac{}3{3}=\frac{3}{6}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{4}{6}+\frac{3}{6}=\frac{7}{6}\)

\(\displaystyle \frac{7}{6}=1\frac{1}{6}\) because \(\displaystyle 6\) can go into \(\displaystyle 7\) one time with \(\displaystyle \frac{1}{6}\) left over. 

\(\displaystyle \frac{1}{4}+\frac{4}{8}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{1}{4}\times\frac{2}{2}=\frac{2}{8}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{2}{8}+\frac{4}{8}=\frac{6}{8}\)

\(\displaystyle \frac{6}{8}\div\frac{2}{2}=\frac{3}{4}\)

\(\displaystyle \frac{4}6{+\frac{3}{8}}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{4}{6}\times\frac{4}{4}=\frac{16}{24}\)

\(\displaystyle \frac{3}{8}\times\frac{3}{3}=\frac{9}{24}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{16}{24}+\frac{9}{24}=\frac{25}{24}\)

\(\displaystyle \frac{25}{24}=1\frac{1}{24}\) because \(\displaystyle 24\) can go into \(\displaystyle 25\) one time with \(\displaystyle 1\) left over. 

\(\displaystyle \frac{7}8{+\frac{2}{4}}\)

In order to solve this problem, we first have to find common denominators. \(\displaystyle \frac{2}{4}\times\frac{2}{2}=\frac{4}{8}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{7}{8}+\frac{4}{8}=\frac{11}{8}\)

\(\displaystyle \frac{11}{8}=1\frac{3}{8}\) because \(\displaystyle 8\) can go into \(\displaystyle 11\) one time with \(\displaystyle 3\) left over. 

\(\displaystyle \frac{3}{5}+\frac{1}3\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{3}5{} \times\frac{3}{3}=\frac{9}{15}\)

\(\displaystyle \frac{1}{3}\times\frac{5}{5}=\frac{5}{15}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{9}{15}+\frac{5}{15}=\frac{14}{15}\)

\(\displaystyle \frac{3}{10}+\frac{1}{2}\)

In order to solve this problem, we first need to make common denominators. 

\(\displaystyle \frac{1}{2}\times\frac{5}{5}=\frac{5}{10}\)

Now that we have common denominators, we can add the fractions. Remember, when we add fractions, the denominator stays the same, we only add the numerator. 

 \(\displaystyle \frac{3}{10 }+\frac{5}{10}=\frac{8}{10}\)

\(\displaystyle \frac{8}{10}\) can be reduced be dividing both sides by \(\displaystyle 2\).

\(\displaystyle \frac{8}{10} \div\frac{2}{2}=\frac{4}{5}\)

\(\displaystyle \frac{1}{8}+\frac{1}{3}\)

In order to solve this problem, we first need to make common denominators. 

\(\displaystyle \frac{1}{8}\times\frac{3}{3}=\frac{3}{24}\)

\(\displaystyle \frac{1}{3}\times\frac{8}{8}=\frac{8}{24}\)

Now that we have common denominators, we can add the fractions. Remember, when we add fractions, the denominator stays the same, we only add the numerator. 

\(\displaystyle \frac{3}{24}+\frac{8}{24}=\frac{11}{24}\)

\(\displaystyle \frac{3}{8}+\frac{1}{4}\)

In order to solve this problem, we first need to make common denominators. 

\(\displaystyle \frac{1}{4}\times\frac{2}{2}=\frac{2}{8}\)

Now that we have common denominators, we can add the fractions. Remember, when we add fractions, the denominator stays the same, we only add the numerator. 

\(\displaystyle \frac{3}{8}+\frac{2}8{=\frac{5}{8}}\)

\(\displaystyle \small \frac{1}{7}+\frac{4}{14}\)

In order to solve this problem, we first need to make common denominators. 

\(\displaystyle \frac{1}{7}\times\frac{2}{2}=\frac{2}{14}\)

Now that we have common denominators, we can add the fractions. Remember, when we add fractions, the denominator stays the same, we only add the numerator. 

\(\displaystyle \small \frac{2}{14}+\frac{4}{14}=\frac{6}{14}\)

\(\displaystyle \small \frac{6}{14}\) can be reduced by dividing \(\displaystyle \small 2\) by both sides. 

\(\displaystyle \small \frac{6}{14}\div\frac{2}{2}=\frac{3}{7}\)

\(\displaystyle \frac{1}{3}+\frac{1}2{}\)

In order to solve this problem, we first need to make common denominators. 

\(\displaystyle \frac{1}3{\times\frac{2}{2}=\frac{2}{6}}\)

\(\displaystyle \frac{1}{2}\times\frac{3}{3}=\frac{3}{6}\)

Now that we have common denominators, we can add the fractions. Remember, when we add fractions, the denominator stays the same, we only add the numerator. 

\(\displaystyle \frac{2}{6}+\frac{3}{6}=\frac{5}{6}\)