All High School Math Resources
Example Questions
Example Question #1 : Pyramids
What is the sum of the number of vertices, edges, and faces of a square pyramid?
A square pyramid has one square base and four triangular sides.
Vertices (where two or more edges come together): 5. There are four vertices on the base (one at each corner of the square) and a fifth at the top of the pyramid.
Edges (where two faces come together): 8. There are four edges on the base (one along each side) and four more along the sides of the triangular faces extending from the corners of the base to the top vertex.
Faces (planar surfaces): 5. The base is one face, and there are four triangular faces that form the top of the pyramid.
Total
Example Question #2 : How To Find The Volume Of A Pyramid
An architect wants to make a square pyramid and fill it with 12,000 cubic feet of sand. If the base of the pyramid is 30 feet on each side, how tall does he need to make it?
Volume of Pyramid = 1/3 * Area of Base * Height
12,000 ft3 = 1/3 * 30ft * 30ft * H
12,000 = 300 * H
H = 12,000 / 300 = 40
H = 40 ft
Example Question #1 : Pyramids
The volume of a 6-foot-tall square pyramid is 8 cubic feet. How long are the sides of the base?
Volume of a pyramid is
Thus:
Area of the base is .
Therefore, each side is .
Example Question #1 : Pyramids
What is the surface are of a pyramid with a square base length of 15 and a slant height (the height from the midpoint of one of the side lengths to the top of the pyramid) of 12?
To find the surface area of a pyramid we must add the areas of all five of the shapes creating the pyramid together.
We have four triangles that all have the same area and a square that supports the pyramid.
To find the area of the square we take the side length of 15 and square it
The area of the square is .
To find the area of the triangle we must use the equation for the area of a triangle which is
Plug in the slant height 12 as the height of the triangle and use the side length of the square 15 as the base in our equation to get
The area of each triangle is .
We then multiply the area of each triangle by 4 to find the area of all four triangles .
The four triangles have a surface area of .
We add the surface area of the four triangles with the area of the square to get the answer for the surface area of the pyramid which is .
The answer is .
Example Question #75 : Solid Geometry
Find the surface area of the following pyramid.
The formula for the surface area of a pyramid is:
Where is the length of the slant height, is the width of the base, and is the length of the base
In order to determine the areas of the triangle, you will need to use the Pythagorean Theorem to find the slant height:
Plugging in our values, we get:
Example Question #75 : Solid Geometry
Find the surface area of the following pyramid.
The formula for the surface area of a pyramid is:
Where is the length of the base, is the width of the base, and is the slant height
Use the Pythagorean Theorem to find the length of the slant height:
Plugging in our values, we get:
Example Question #1 : Pyramids
What is the surface area of a square pyramid with a base side equal to 4 and a slant length equal to 6?
The surface area of of a square pyramid can be determined using the following equation:
Example Question #611 : Geometry
What is the surface area of a square pyramid with a height of 12 in and a base side length of 10 in?
The surface area of a square pyramid can be broken into the area of the square base and the areas of the four triangluar sides. The area of a square is given by:
The area of a triangle is:
The given height of 12 in is from the vertex to the center of the base. We need to calculate the slant height of the triangular face by using the Pythagorean Theorem:
where and (half the base side) resulting in a slant height of 13 in.
So, the area of the triangle is:
There are four triangular sides totaling for the sides.
The total surface area is thus , including all four sides and the base.
Example Question #81 : Solid Geometry
The length of a box is 3 times the width. Which of the following gives the length (L inches) in terms of the width (W inches) of the box?
L = 3/W
L = ½ (3W)
L = 3W
L = W + 3
L = 3W
When reading word problems, there are certain clues that help interpret what is going on. The word “is” generally means “=” and the word “times” means it will be multiplied by something. Therefore, “the length of a box is 3 times the width” gives you the answer: L = 3 x W, or L = 3W.
Example Question #1 : Prisms
The width of a box, in inches, is 5 inches less than three times its length. Which of the following equations gives the width, W inches, in terms of the length, L inches, of the box?
W=5-3L
W=5L-3
W=3-5L
W=3L-5
W=3L-5
We notice the width is “5 inches less than three times its width,” so we express W as being three times its width (3L) and 5 inches less than that is 3L minus 5. In this case, W is the dependent and L is the independent variable.
W = 3L - 5