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High School Math : Geometry

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Example Questions

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Example Question #1 : How To Find The Area Of A Polygon

Find the area of the shaded region:

Possible Answers:

$24 \pi\ m^2$

$26 \pi\ m^2$

$28 \pi\ m^2$

$30 \pi\ m^2$

$32 \pi\ m^2$

Correct answer:

$28 \pi\ m^2$

Explanation:

The formula for the area of the shaded region is

$A = A_{large circle}-A_{small circle}= \pi r_{large}^2 - \pi r_{small}^2,$

where is the radius of the circle.

Plugging in our values, we get:

$A = \pi (8\ m)^2 - \pi (6\ m)^2$

$A = 28 \pi\ m^2$

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Example Question #2 : How To Find The Area Of A Polygon

Find the area of the following octagon:

Possible Answers:

$200\sqrt{2}+288\ m^2$

$280\sqrt{2}+288\ m^2$

$280\sqrt{2}+280\ m^2$

$288\sqrt{2}+280\ m^2$

$288\sqrt{2}+288\ m^2$

Correct answer:

$288\sqrt{2}+288\ m^2$

Explanation:

The formula for the area of a regular octagon is:

$A = \frac{1}{2}(perimeter)(apothem)$

Plugging in our values, we get:

$A = \frac{1}{2}(96\ m)(6\sqrt{2}\ m+6\ m)$

$A = 288\sqrt{2}+288\ m^2$

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Example Question #1 : How To Find The Area Of A Polygon

Find the area of a rectangle with a base of (x + 3) and a width of (x - 3) in terms of .

Possible Answers:

none of the other answers

$x^{2 } - 3x - 9$

$x^{2 } + 9$

$x^{2} - 9$

$x^{2}$

Correct answer:

$x^{2} - 9$

Explanation:

This problem simply becomes a matter of FOILing (first outer inner last)

The area of the shape is Base times Height.

So, multiplying (x + 3) and (x - 3) using FOIL, we get an area of $x^{2} - 9$

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Example Question #1 : How To Find The Area Of A Polygon

Find the area of a square whose diagonal is .

Possible Answers:

none of these answers

144

Correct answer:

Explanation:

If the diagonal of a square is , we can use the pythagorean theorem to solve for the length of the sides.

= length of side of the square

Doing so, we get $2x^{2} = 144$

$x = \sqrt{72}$

To find the area of the square, we square , resulting in .

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Example Question #11 : Geometry

What is the magnitude of the interior angle of a regular nonagon?

Possible Answers:

135^o

144^o

140^o

129^o

Correct answer:

140^o

Explanation:

The equation to calculate the magnitude of an interior angle is $\frac{180(n-2)}{n}=int\ angle$ , where is equal to the number of sides.

For our question, n=9 .

$int\ angle= \frac{180(9-2)}{9}=\frac{(180)(7)}{9}=140^o$

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Example Question #2 : How To Find An Angle In A Polygon

What is the interior angle measure of any regular heptagon?

Possible Answers:

130.2

128.6

125.8

135

Correct answer:

128.6

Explanation:

To find the angle of any regular polygon you find the number of sides, . In this example, n=7 .

You then subtract 2 from the number of sides yielding 5.

Take 5 and multiply it by 180 degrees to yield the total number of degrees in the regular heptagon. 5*180=900

Then to find one individual angle we divide 900 by the total number of angles, 7.

$\frac{900}{7}=128.6$

The answer is 128.6 .

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Example Question #1 : How To Find An Angle In A Polygon

A regular polygon with sides has exterior angles that measure $1.5^{\circ }$ each. How many sides does the polygon have?

Possible Answers:

120

180

This figure cannot exist.

150

240

Correct answer:

240

Explanation:

The sum of the exterior angles of any polygon, one per vertex, is $360 ^{\circ }$ . As each angle measures $1.5^{\circ }$ , just divide 360 by 1.5 to get the number of angles.

$360 \div 1.5=240$

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Example Question #11 : Geometry

What is the interior angle measure of any regular nonagon?

Possible Answers:

$160^{\circ}$

$140^{\circ}$

$200^{\circ}$

$120^{\circ}$

Correct answer:

$140^{\circ}$

Explanation:

To find the angle of any regular polygon you find the number of sides , which in this example is .

You then subtract from the number of sides yielding .

Take and multiply it by 180 degrees to yield a total number of degrees in the regular nonagon.

7*180=1260

Then to find one individual angle we divide 1260 by the total number of angles .

$\frac{1260}{9}=140$

The answer is 140 .

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Example Question #1 : How To Find An Angle In A Polygon

What is the measure of one exterior angle of a regular seventeen-sided polygon (nearest tenth of a degree)?

Possible Answers:

$10.6^{\circ }$

$21.2^{\circ }$

$25.2 ^{\circ }$

$34.0 ^{\circ }$

$15.9^{\circ }$

Correct answer:

$21.2^{\circ }$

Explanation:

The sum of the measures of the exterior angles of any polygon, one per vertex, is $360^{\circ}$ . In a regular polygon, all of these angles are congruent, so divide 360 by 17 to get the measure of one exterior angle:

$360 \div 17 \approx 21.2^{\circ }$

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Example Question #6 : How To Find An Angle In A Polygon

What is the measure of one exterior angle of a regular twenty-three-sided polygon (nearest tenth of a degree)?

Possible Answers:

$7.8^{\circ }$

$28.8^{\circ }$

$15.7 ^{\circ }$

$31.3^{\circ }$

$14.4^{\circ }$

Correct answer:

$15.7 ^{\circ }$

Explanation:

The sum of the measures of the exterior angles of any polygon, one per vertex, is $360^{\circ}$ . In a regular polygon, all of these angles are congruent, so divide 360 by 23 to get the measure of one exterior angle:

$360 \div 23 \approx 15.7 ^{\circ }$

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High School Math : Geometry

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #1 : How To Find The Area Of A Polygon

Example Question #2 : How To Find The Area Of A Polygon

Example Question #1 : How To Find The Area Of A Polygon

Example Question #1 : How To Find The Area Of A Polygon

Example Question #11 : Geometry

Example Question #2 : How To Find An Angle In A Polygon

Example Question #1 : How To Find An Angle In A Polygon

Example Question #11 : Geometry

Example Question #1 : How To Find An Angle In A Polygon

Example Question #6 : How To Find An Angle In A Polygon

All High School Math Resources

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