We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

SSAT Middle Level Math : Quadrilaterals

Study concepts, example questions & explanations for SSAT Middle Level Math

Create An Account

All SSAT Middle Level Math Resources

10 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 5 6 7 8 9 … 13 14 Next →

Example Question #1 : How To Find The Perimeter Of The Rectangle

Rectangles

Note: Figure NOT drawn to scale.

Refer to the above diagram. Give the perimeter of the red polygon.

Possible Answers:

The perimeter cannot be determined from the information given.

340

140

240

120

Correct answer:

240

Explanation:

Since opposite sides of a rectangle have the same measure, the missing sidelengths can be calculated as in the diagram below:

Rectangles

The sidelengths of the red polygon can now be added to find the perimeter:

40 + 80 + 20 + 30 + 20 + 50 = 240

Report an Error

Example Question #2 : How To Find The Perimeter Of The Rectangle

The width of a rectangle is , the length is , and the perimeter is 72. What is the value of ?

Possible Answers:

Correct answer:

Explanation:

Start with the equation for the perimeter of a rectangle:

P=l+l+w+w=2l+2w

We know the perimeter is 72, the length is , and the width is . Plug these values into our equation.

72=2(6x)+2(3x)

Multiply and combine like terms.

72=12x+6x

72=18x

Divide by 18 to isolate the variable.

$\frac{72}{18}=x$

Simplify the fraction by removing the common factor.

$\frac{72}{18}=\frac{72\div18}{18\div18}=\frac{4}{1}=4$

Report an Error

Example Question #3 : How To Find The Perimeter Of The Rectangle

Rectangles

Note: Figure NOT drawn to scale.

Refer to the above diagram. Give the ratio of the perimeter of the large rectangle to that of the smaller rectangle.

Possible Answers:

12:5

16:7

2:1

The correct answer is not given among the other choices.

8:3

Correct answer:

12:5

Explanation:

Opposite sides of a rectangle are congruent.

The large rectangle has perimeter

40 + 80 + 40 + 80 = 240 .

The smaller rectangle has perimeter

20 + 30 + 20 + 30 = 100 .

The ratio is

$\frac{240}{100} = \frac{240 \div 20 }{100\div 20 } = \frac{12}{5}$ ; that is, 12 to 5.

Report an Error

Example Question #121 : Geometry

What is the perimeter of a rectangle with a width of 3 and a length of 10?

Possible Answers:

Correct answer:

Explanation:

The formula for the perimeter of a rectangle is $\dpi{100} Perimeter=2l+2w$ .

Plug in our given values to solve:

$\dpi{100} Perimeter = 2(20)+2(3)$

$\dpi{100} Perimeter = 20+6$

$\dpi{100} Perimeter = 26$

Report an Error

Example Question #11 : Rectangles

Rectangle ABCD has an area of . If the width of the rectangle is , what is the perimeter?

Possible Answers:

Correct answer:

Explanation:

The area of a rectangle is found by multiplying the length times the width. The question tells you the width is and the area is .

Thus the length is 8. $\left ( 40 \div5\right)$ .

To find the perimeter you add up all of the sides.

length+length+width+width=perimeter

8 + 8 + 5 + 5 = 26

Report an Error

Example Question #5 : How To Find The Perimeter Of The Rectangle

If the perimeter of a rectangle is inches and the width is inches, what is the length?

Possible Answers:

Correct answer:

Explanation:

The perimeter of a rectangle is represented by the following formula, in which W represents width and L represents length:

2W+2L= Perimeter

Given that the width is inches and that the perimeter is inches, the following applies:

$2\cdot 2+2L=14$

4+2L=14

Next, subtract from each side.

2L=10

Now, divide each side by .

This gives us

L=5

Report an Error

Example Question #42 : Quadrilaterals

A rectangle has an area of . The length of each side is a whole number. What is NOT a possible value for the rectangle's perimeter?

Possible Answers:

Correct answer:

Explanation:

Since each side is a whole number, first find the whole number factors of . They are and , and , and , and and . These sidelengths correspond to perimeters of , , , and , respectively. Thus, is answer.

Report an Error

Example Question #43 : Quadrilaterals

Rectangle

Give the perimeter of the above rectangle in centimeters, using the conversion factor 91.44 centimeters per yard.

Possible Answers:

$2,011.68 \textrm{ cm}$

$1,005.84 \textrm{ cm}$

$1,097.28 \textrm{ cm}$

$2,194.56 \textrm{ cm}$

$4,389.12 \textrm{ cm}$

Correct answer:

$2,011.68 \textrm{ cm}$

Explanation:

The perimeter of the rectangle is 8 + 3 + 8 + 3 = 22 yards. To convert this to centimeters, multiply by the given conversion factor:

$91.44 \times 22 = 2,011.68$ centimeters.

Report an Error

Example Question #44 : Quadrilaterals

Find the perimeter of the rectangle shown below

Screen shot 2015 11 10 at 9.55.29 pm

Possible Answers:

Correct answer:

Explanation:

The perimeter of a rectangle, or any shape, is the distance around the outside. You add up the length of each side to find this number. The coordinates of the points are (-3,8)(5,8)(5,-2)(-3,-2) . You need to find the distance between each point. The short side is units, and the longer side is units.

$(8\times2)+(10\times2)=16+20=36$

Report an Error

Example Question #1 : How To Find The Area Of A Rectangle

Steve's bedroom measures 20' by 18' by 8' high. He wants to paint the ceiling and all four walls using a paint that gets 360 square feet of coverage per gallon. A one-gallon can of the paint Steve wants costs $36.00; a one-quart can costs $13.00. What is the least amount of money that Steve can expect to spend on paint in order to paint his room?

Possible Answers:

$\$98$

$\$111$

$\$85$

$\$108$

$\$121$

Correct answer:

$\$108$

Explanation:

Two of the walls have area $20 \cdot 8 = 160\;\textrm{in}^{2}$ ; two have area $18 \cdot 8 = 144\;\textrm{in}^{2}$ ; the ceiling has area $20 \cdot 18 = 360\;\textrm{in}^{2}$ .

Therefore, the total area Steve wants to cover is

$A = 160 + 160 + 144 + 144 + 360 =968 \; \textrm{in}^{2}$

Divide 968 by 360 to get the number of gallons Steve needs to paint his bedroom:

$968 \div 360 \approx 2.7$

Since $2 \frac{1}{2} < 2.7 < 2\frac{3}{4}$ , Steve needs to purchase either two gallon cans and three quart cans, or three gallon cans.

The first option will cost him $36 \cdot2 + 13 \cdot3 = \$111$ ; the second option will cost him $36 \cdot3 = \$108$ . The latter is the more economical option.

Report an Error

← Previous 1 2 3 4 5 6 7 8 9 … 13 14 Next →

View SSAT- Middle Level Tutors

Chase
Certified Tutor

Western Governors University, Bachelor of Science, Mathematics.

View SSAT- Middle Level Tutors

Meredith
Certified Tutor

University of Arkansas at Little Rock, Bachelor in Arts, English. University of Arkansas at Little Rock, Masters in Education...

View SSAT- Middle Level Tutors

Denisha
Certified Tutor

Nova Southeastern University, Doctor of Medicine, Ayurvedic Medicine. Nova Southeastern University, Master in Public Health, ...

All SSAT Middle Level Math Resources

10 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Statistics Tutors in Phoenix, Statistics Tutors in Washington DC, GRE Tutors in Dallas Fort Worth, Spanish Tutors in New York City, Computer Science Tutors in Chicago, Statistics Tutors in San Francisco-Bay Area, MCAT Tutors in Houston, French Tutors in Chicago, LSAT Tutors in Chicago, ACT Tutors in New York City

Popular Courses & Classes

Spanish Courses & Classes in Phoenix, SAT Courses & Classes in New York City, SAT Courses & Classes in Atlanta, ACT Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Houston, LSAT Courses & Classes in Los Angeles, Spanish Courses & Classes in Los Angeles, LSAT Courses & Classes in Washington DC, SSAT Courses & Classes in Chicago, ISEE Courses & Classes in Phoenix

Popular Test Prep

GRE Test Prep in New York City, SAT Test Prep in Houston, GRE Test Prep in Boston, LSAT Test Prep in Denver, GMAT Test Prep in New York City, SSAT Test Prep in Washington DC, ACT Test Prep in Dallas Fort Worth, SAT Test Prep in Los Angeles, SAT Test Prep in Boston, MCAT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

SSAT Middle Level Math : Quadrilaterals

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #1 : How To Find The Perimeter Of The Rectangle

Example Question #2 : How To Find The Perimeter Of The Rectangle

Example Question #3 : How To Find The Perimeter Of The Rectangle

Example Question #121 : Geometry

Example Question #11 : Rectangles

Example Question #5 : How To Find The Perimeter Of The Rectangle

Example Question #42 : Quadrilaterals

Example Question #43 : Quadrilaterals

Example Question #44 : Quadrilaterals

Example Question #1 : How To Find The Area Of A Rectangle

All SSAT Middle Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: