All PSAT Math Resources
Example Questions
Example Question #567 : Geometry
All of the following could be the possible side lengths of a triangle EXCEPT:
The length of the third side of a triangle must always be between (but not equal to) the sum and the difference of the other two sides.
For instance, take the example of 2, 6, and 7.
and . Therefore, the third side length must be greater than 4 and less than 8. Because 7 is greater than 4 and less than 8, it is possible for these to be the side lengths of a triangle.
The 5, 7, 12 answer choice is the only option for which this is not the case.
and . Therefore, the third side length must be between 2 and 12. Because it is equal to the sum, not less than the sum, it is not possible that these could be the side lengths of a triangle.
Example Question #251 : Plane Geometry
and are similar triangles. The perimeter of Triangle A is 45” and the length of two of its sides are 15” and 10”. If the perimeter of Triangle B is 135” and what are lengths of two of its sides?
The perimeter is equal to the sum of the three sides. In similar triangles, each side is in proportion to its correlating side. The perimeters are also in equal proportion.
Perimeter A = 45” and perimeter B = 135”
The proportion of Perimeter A to Perimeter B is .
This applies to the sides of the triangle. Therefore to get the any side of Triangle B, just multiply the correlating side by 3.
15” x 3 = 45”
10” x 3 = 30“
Example Question #352 : Geometry
Find the height of a triangle if the area of the triangle = 18 and the base = 4.
4
6
1
9
9
The area of a triangle = (1/2)bh where b is base and h is height. 18 = (1/2)4h which gives us 36 = 4h so h =9.
Example Question #334 : Plane Geometry
If triangle ABC has vertices (0, 0), (6, 0), and (2, 3) in the xy-plane, what is the area of ABC?
9
18
20
12
10
Example Question #1 : How To Find The Area Of An Acute / Obtuse Triangle
The height, , of triangle in the figure is one-fourth the length of . In terms of h, what is the area of triangle ?
If *, then the length of must be .
Using the formula for the area of a triangle (), with , the area of the triangle must be .
Example Question #1 : How To Find The Length Of The Diagonal Of A Hexagon
How many diagonals are there in a regular hexagon?
A diagonal is a line segment joining two non-adjacent vertices of a polygon. A regular hexagon has six sides and six vertices. One vertex has three diagonals, so a hexagon would have three diagonals times six vertices, or 18 diagonals. Divide this number by 2 to account for duplicate diagonals between two vertices. The formula for the number of vertices in a polygon is:
where .
Example Question #2 : How To Find The Length Of The Diagonal Of A Hexagon
How many diagonals are there in a regular hexagon?
18
3
6
9
10
9
A diagonal connects two non-consecutive vertices of a polygon. A hexagon has six sides. There are 3 diagonals from a single vertex, and there are 6 vertices on a hexagon, which suggests there would be 18 diagonals in a hexagon. However, we must divide by two as half of the diagonals are common to the same vertices. Thus there are 9 unique diagonals in a hexagon. The formula for the number of diagonals of a polygon is:
where n = the number of sides in the polygon.
Thus a pentagon thas 5 diagonals. An octagon has 20 diagonals.
Example Question #1 : How To Find The Length Of The Diagonal Of A Hexagon
Regular Hexagon has a diagonal with length 1.
Give the length of diagonal .
The key is to examine in thie figure below:
Each interior angle of a regular hexagon, including , measures , so it can be easily deduced by way of the Isosceles Triangle Theorem that . , so by angle addition,
.
Also, by symmetry,
,
so ,
and is a triangle whose long leg has length .
By the Theorem, , which is the hypotenuse of , has length times that of the long leg, so .
Example Question #1 : How To Find The Length Of The Diagonal Of A Hexagon
Regular Hexagon has a diagonal with length 1.
Give the length of diagonal .
The key is to examine in thie figure below:
Each interior angle of a regular hexagon, including , measures , so it can be easily deduced by way of the Isosceles Triangle Theorem that . , so by angle addition,
.
Also, by symmetry,
,
so ,
and is a triangle whose hypotenuse has length .
By the Theorem, the long leg of has length times that of hypotenuse , so .
Example Question #574 : Geometry
Regular hexagon has side length of 1.
Give the length of diagonal .
The key is to examine in thie figure below:
Each interior angle of a regular hexagon, including , measures , so it can be easily deduced by way of the Isosceles Triangle Theorem that . To find we can subtract from . Thus resulting in:
Also, by symmetry,
,
so .
Therefore, is a triangle whose short leg has length .
The hypotenuse of this triangle measures twice the length of short leg , so .