Call Now to Set Up Tutoring:

(888) 888-0446

GED Math : GED Math

Study concepts, example questions & explanations for GED Math

Create An Account

All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #671 : Ged Math

Solve for : 3y-7 = 4y

Possible Answers:

$-\frac{7}{12}$

Correct answer:

Explanation:

Subtract from both sides.

3y-7-3y = 4y-3y

Simplify both sides.

-7 =y

The answer is:

Report an Error

Example Question #672 : Ged Math

Solve for : $\frac{1}{2}x +\frac{7}{3} = \frac{8}{3}$

Possible Answers:

$\frac{2}{3}$

$\frac{1}{6}$

$\textup{The answer is not given.}$

Correct answer:

$\frac{2}{3}$

Explanation:

Multiply both sides by the least common denominator to cancel out the fractions.

$6(\frac{1}{2}x +\frac{7}{3}) = \frac{8}{3}\cdot6$

3x+14 = 16

Subtract 14 on both sides.

3x+14 -14= 16-14

3x=2

Divide by 3 on both sides.

$\frac{3x}{3}=\frac{2}{3}$

The answer is: $\frac{2}{3}$

Report an Error

Example Question #673 : Ged Math

Given the following equation, find the value of b when w=-3

$b-2=\frac{5w+12}{3}+4$

Possible Answers:

Correct answer:

Explanation:

Given the following equation, find the value of b when w=-3

$b-2=\frac{5w+12}{3}+4$

This may look a little messy up front, but don't worry, it's not overly complicated.

All we need to do is plug in -3 for w and solve for b.

Let's begin:

$b-2=\frac{5(-3)+12}{3}+4$

$b-2=\frac{-15+12}{3}+4$

Now add our numbers:

$b-2=\frac{-3}{3}+4$

Now we can simplify our fraction to get:

b-2=-1+4

From her on out it is just subtraction and addition:

b-2=3

b=3+2=5

So our answer is 5

Report an Error

Example Question #674 : Ged Math

Solve for .

$\sqrt{3x+4}-2=6$

Possible Answers:

Correct answer:

Explanation:

$\sqrt{3x+4}-2=6$

Start by adding to both sides.

$\sqrt{3x+4}=8$

Next, square both sides to get rid of the square root.

3x+4=64

Subtract from both sides.

3x=60

Finally, divide both sides by .

x=20

Report an Error

Example Question #70 : Solving For The Variable

Solve for :

$\sqrt{3x-1}+5=9$

Possible Answers:

$\frac{17}{3}$

$\frac{3}{17}$

Correct answer:

$\frac{17}{3}$

Explanation:

$\sqrt{3x-1}+5=9$

Start by subtracting from both sides.

$\sqrt{3x-1}=4$

Now, square both sides of the equation to get rid of the square root.

3x-1=16

Add to both sides.

3x=17

Divide both sides by .

$x=\frac{17}{3}$

Report an Error

Example Question #71 : Solving For The Variable

Solve for .

$\sqrt{x+15}-2=4$

Possible Answers:

x=21

x=26

x=41

x=16

Correct answer:

x=21

Explanation:

$\sqrt{x+15}-2=4$

Start by adding to both sides.

$\sqrt{x+15}=6$

Next, square both sides to get rid of the square root.

x+15=36

Finally, subtract from both sides.

x=21

Report an Error

Example Question #121 : Algebra

Solve for $\small x$ : $\small x=7+5-2$

Possible Answers:

$\small x=10$

$\small x=13$

None of these answers

$\small x=12$

$\small x=11$

Correct answer:

$\small x=10$

Explanation:

To solve for $\small x$ , all you have to do is simplify your equation until you get a number on one side and your $\small x$ on the other.

So for starters we already have all of our numbers on one side: $\small x=7+5-2$ . Now all we need to do is add and subtract when called for in order to get our answer.

Start by adding $\small 7$ to $\small 5$

$\small x=(7+5)-2$

$\small x=12-2$

Now subtract $\small 2$ from our newly formed $\small 12$

$\small x=10$

Your answer is $\small x=10$

Report an Error

Example Question #72 : Solving For The Variable

Solve for $\small x$ : $\small x-6=5\cdot3$

Possible Answers:

$\small x=21$

None of the other answers

$\small x=20$

$\small x=23$

$\small x=18$

Correct answer:

$\small x=21$

Explanation:

In order to solve for $\small x$ , all you have to do is simplify your equation so that your $\small x$ is on one side and your number is on the other.

For this equation, we have one number accompanying our $\small x$ . That is $\small -6$ : $\small x-6=5\cdot3$ .

Let's move that $\small -6$ over to the other side by adding it on both sides.

$\small x=5\cdot3-6$

Now that all of our numbers are on one side, it's time to simplify. Multiplication comes before addition, so we need to multiply the $\small 5$ and $\small 3$ together before we touch the $\small 6$ .

$\small x=(5\cdot 3)-6$

$\small x=15-6$

Now we can add the $\small 6$ to $\small 15$ .

$\small x=21$

Our answer is $\small x=21$

Report an Error

Example Question #122 : Algebra

Solve for $\small x$ : $\small \frac{x+6}{2}=6$

Possible Answers:

None of the other answers

$\small x=8$

$\small x=0$

$\small x=12$

$\small x=6$

Correct answer:

$\small x=6$

Explanation:

In order to solve for $\small x$ , we must simplify our equation so that we have $\small x$ on one side and our final number on the other side.

Before we can do any simplifying, we must get $\small x$ by itself. Currently our $\small x$ is being added by $\small 6$ , but it's also being divided by $\small 2$ . We can't touch the $\small +6$ yet, so let's move the $\small 2$ by multiplying both sides.

$\small \frac{x+6}{2}=6$

$\small x+6=6\cdot2$

Now let's move that $\small 6$ on the $\small x$ side by subtracting it on both sides.

$\small x+6=6\cdot2$

$\small x=6\cdot2-6$

Now that we have all our numbers to one side, it's time to start simplifying. Multiplication comes before subtraction, so we're going to multiply our $\small 6$ and $\small 2$ together.

$\small x=(6\cdot 2)-6$

$\small x=12-6$

Now we can subtract our $\small 6$ from $\small 12$ .

$\small x=12-6$

$\small x=6$

Our answer is $\small x=6$

Report an Error

Example Question #123 : Algebra

6x- 17 = 3x

Evaluate .

Possible Answers:

$x= 3 \frac{2}{3}$

$x= 5\frac{2}{3}$

$x = 1\frac{8}{9}$

$x = 2\frac{1}{3}$

Correct answer:

$x= 5\frac{2}{3}$

Explanation:

Solve this equation for by isolating the on the left side of the equation. This can be done by first, subtracting from both sides:

6x- 17 = 3x

6x- 17- 3x = 3x - 3x

6x- 3x - 17 =0

Collect like terms by subtracting coefficients of :

(6-3)x-17=0

3x - 17 =0

Add 17 to both sides:

3x - 17+ 17 =0+ 17

3x= 17

Divide both sides by 3:

$3x \div 3= 17 \div 3$

$x = \frac{17}{3}= 5 \frac{2}{3}$ ,

the correct choice.

Report an Error

View Tutors

Maryann
Certified Tutor

CUNY Queens College, Bachelor in Arts, Linguistics. Appalachian State University, Master of Arts, Special Education.

View Tutors

Laura
Certified Tutor

California State University-Fullerton, Bachelor in Business Administration, Business Administration and Management.

View Tutors

Jason
Certified Tutor

McMaster University, Bachelor in Arts, English.

All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Algebra Tutors in Chicago, Chemistry Tutors in Washington DC, LSAT Tutors in Boston, GMAT Tutors in Dallas Fort Worth, Biology Tutors in Phoenix, GRE Tutors in San Francisco-Bay Area, SAT Tutors in Miami, Physics Tutors in Phoenix, GRE Tutors in Washington DC, Algebra Tutors in Philadelphia

Popular Courses & Classes

SSAT Courses & Classes in Phoenix, Spanish Courses & Classes in Phoenix, SSAT Courses & Classes in New York City, ACT Courses & Classes in Houston, SAT Courses & Classes in Boston, ACT Courses & Classes in Los Angeles, GMAT Courses & Classes in San Diego, ISEE Courses & Classes in Denver, MCAT Courses & Classes in Miami, SSAT Courses & Classes in Miami

Popular Test Prep

MCAT Test Prep in San Francisco-Bay Area, SAT Test Prep in San Francisco-Bay Area, SAT Test Prep in New York City, GRE Test Prep in Chicago, ACT Test Prep in Los Angeles, ACT Test Prep in Houston, ISEE Test Prep in Denver, LSAT Test Prep in Phoenix, LSAT Test Prep in Los Angeles, MCAT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

GED Math : GED Math

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #671 : Ged Math

Example Question #672 : Ged Math

Example Question #673 : Ged Math

Example Question #674 : Ged Math

Example Question #70 : Solving For The Variable

Example Question #71 : Solving For The Variable

Example Question #121 : Algebra

Example Question #72 : Solving For The Variable

Example Question #122 : Algebra

Example Question #123 : Algebra

All GED Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: