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GED Math : GED Math

Study concepts, example questions & explanations for GED Math

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All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #24 : Solving For The Variable

Solve for k.

$\frac{k}{9} = 12$

Possible Answers:

k=72

k=108

k=98

k=89

k=96

Correct answer:

k=108

Explanation:

To solve for k, we want k to stand alone. So, we get

$\frac{k}{9} = 12$

$\frac{k}{9} \cdot 9 = 12 \cdot 9$

k= 108

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Example Question #25 : Solving For The Variable

Solve for : $2x+\frac{y}{4} = \frac{x}{2}$

Possible Answers:

y=-8x

y=8x

y=-6x

y=6x

y=-4x

Correct answer:

y=-6x

Explanation:

Multiply both sides by the least common denominator, four.

This will eliminate the fractions.

$4(2x+\frac{y}{4}) = (\frac{x}{2})(4)$

8x+y = 2x

Subtract on both sides.

8x+y-8x = 2x-8x

The answer is: y=-6x

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Example Question #71 : Algebra

Which of the following makes this equation true:

6y+5=47

Possible Answers:

y=6

y=8

y=4

y=9

y=7

Correct answer:

y=7

Explanation:

To answer the question, we will solve for y. We get

6y+5-5=47-5

6y+0=42

6y=42

$\frac{6y}{6} = \frac{42}{6}$

y=7

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Example Question #26 : Solving For The Variable

Which of the following makes this equation true:

$\frac{a}{8} +1 =10$

Possible Answers:

a=9

a=7

a=64

a=56

a=72

Correct answer:

a=72

Explanation:

To answer the question, we will solve for a. We get

$\frac{a}{8}+1-1=10-1$

$\frac{a}{8}+0=9$

$\frac{a}{8}=9$

$\frac{a}{8} \cdot 8 = 9 \cdot 8$

a = 72

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Example Question #72 : Algebra

Which of the following makes this equation true:

14x-8=160

Possible Answers:

x=7

x=12

x=8

x=11

x=9

Correct answer:

x=12

Explanation:

To answer this question, we will solve for y. We get

14x-8+8=160+8

14x-0=168

14x=168

$\frac{14x}{14} = \frac{168}{14}$

x=12

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Example Question #81 : Algebra

Solve for :

$\frac{2}{7}y - \frac{3}{7} = \frac{1}{5}$

Possible Answers:

$y = \frac{44}{245}$

$y = \frac{5}{11}$

$y = 2 \frac{1}{5}$

$y = 5\frac{25 }{44}$

Correct answer:

$y = 2 \frac{1}{5}$

Explanation:

One way to solve a linear equation with fractional coefficients is to first multiply both sides by their least common denominator; this is the least common multiple of 5 and 7, which is 35, so multiply by this:

$\frac{2}{7}y - \frac{3}{7} = \frac{1}{5}$

$35 \cdot \left (\frac{2}{7}y - \frac{3}{7} \right ) = 35 \cdot \frac{1}{5}$

Since fractions are involved, change 35 to $\frac{35}{1}$ , and distribute on the left side:

$\frac{35}{1} \cdot \left (\frac{2}{7}y - \frac{3}{7} \right ) =\frac{35}{1} \cdot \frac{1}{5}$

$\frac{35}{1} \cdot \frac{2}{7}y - \frac{35}{1} \cdot \frac{3}{7} =\frac{35}{1} \cdot \frac{1}{5}$

Cross-cancel and multiply fractions across:

$\frac{5}{1} \cdot \frac{2}{1}y - \frac{5}{1} \cdot \frac{3}{1} =\frac{7}{1} \cdot \frac{1}{1}$

$\frac{10}{1}y - \frac{15}{1} =\frac{7}{1}$

10y -15 =7

Isolate on the left side by first adding 15 to both sides:

10y -15 + 15 =7 + 15

10y = 22

Divide both sides by 10:

$\frac{10y}{10} = \frac{22}{10}$

$y = 2\frac{2}{10} = 2 \frac{1}{5}$

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Example Question #31 : Solving For The Variable

Which of the following makes this equation true:

$\frac{y}{9} = 13$

Possible Answers:

y=99

y=6

y=4

y=117

y=118

Correct answer:

y=117

Explanation:

To answer the question, we will solve for y. We get

$\frac{y}{9} = 13$

$\frac{y}{9} \cdot 9 = 13 \cdot 9$

y = 117

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Example Question #81 : Algebra

Solve the equation: x+4 = 8-x

Possible Answers:

$\textup{No solution.}$

Correct answer:

Explanation:

Add on both sides.

x+4+x = 8-x+x

2x+4=8

Subtract 4 on both sides.

2x+4-4=8-4

2x=4

Divide by 2 on both sides.

$\frac{2x}{2}=\frac{4}{2}$

The answer is:

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Example Question #631 : Ged Math

Solve for : y-3 = 2(y-2)

Possible Answers:

Correct answer:

Explanation:

Distribute the right side.

y-3 = 2y-4

Subtract on both sides.

y-3 -y= 2y-4-y

-3 = y-4

Add 4 on both sides.

-3 +4= y-4+4

The answer is: y=1

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Example Question #31 : Solving For The Variable

Solve for the variable: 9x-4 = 17

Possible Answers:

$\frac{13}{9}$

$\frac{7}{2}$

$\frac{7}{3}$

$\frac{9}{7}$

Correct answer:

$\frac{7}{3}$

Explanation:

Add 4 on both sides.

9x-4 +4= 17+4

9x=21

Divide by 9 on both sides.

$\frac{9x}{9}=\frac{21}{9}$

Reduce both sides.

The answer is: $\frac{7}{3}$

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All GED Math Resources

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GED Math : GED Math

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #24 : Solving For The Variable

Example Question #25 : Solving For The Variable

Example Question #71 : Algebra

Example Question #26 : Solving For The Variable

Example Question #72 : Algebra

Example Question #81 : Algebra

Example Question #31 : Solving For The Variable

Example Question #81 : Algebra

Example Question #631 : Ged Math

Example Question #31 : Solving For The Variable

All GED Math Resources

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