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SSAT Middle Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Middle Level Math

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All SSAT Middle Level Math Resources

10 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #27 : Find Greatest Common Factor

Use the distributive property to express the sum 33+27 $\displaystyle 33+27$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

3(11+9) $\displaystyle 3(11+9)$

3(11+8) $\displaystyle 3(11+8)$

3(10+9) $\displaystyle 3(10+9)$

2(12+9) $\displaystyle 2(12+9)$

3(11+6) $\displaystyle 3(11+6)$

Correct answer:

3(11+9) $\displaystyle 3(11+9)$

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

33+27 $\displaystyle 33+27$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=3$ $\displaystyle \text{GCF}=3$

After we reduce each addend by the greatest common factor we can rewrite the expression:

3(11+9) $\displaystyle 3(11+9)$

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Example Question #28 : Find Greatest Common Factor

Use the distributive property to express the sum 12+27 $\displaystyle 12+27$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

3(4+7) $\displaystyle 3(4+7)$

3(4+9) $\displaystyle 3(4+9)$

4(3+9) $\displaystyle 4(3+9)$

None of these

3(2+9) $\displaystyle 3(2+9)$

Correct answer:

3(4+9) $\displaystyle 3(4+9)$

Explanation:

12+27 $\displaystyle 12+27$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=3$ $\displaystyle \text{GCF}=3$

After we reduce each addend by the greatest common factor we can rewrite the expression:

3(4+9) $\displaystyle 3(4+9)$

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Example Question #29 : Find Greatest Common Factor

Use the distributive property to express the sum 10+50 $\displaystyle 10+50$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

10(1+7) $\displaystyle 10(1+7)$

$\displaystyle 10(1+15)$

5(1+5) $\displaystyle 5(1+5)$

10(1+5) $\displaystyle 10(1+5)$

10(3+5) $\displaystyle 10(3+5)$

Correct answer:

10(1+5) $\displaystyle 10(1+5)$

Explanation:

10+50 $\displaystyle 10+50$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=10$ $\displaystyle \text{GCF}=10$

After we reduce each addend by the greatest common factor we can rewrite the expression:

10(1+5) $\displaystyle 10(1+5)$

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Example Question #34 : How To Find The Distributive Property

Use the distributive property to express the sum 20+70 $\displaystyle 20+70$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

10(2+7) $\displaystyle 10(2+7)$

10(2+8) $\displaystyle 10(2+8)$

None of these

10(2+9) $\displaystyle 10(2+9)$

10(4+7) $\displaystyle 10(4+7)$

Correct answer:

10(2+7) $\displaystyle 10(2+7)$

Explanation:

20+70 $\displaystyle 20+70$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=10$ $\displaystyle \text{GCF}=10$

After we reduce each addend by the greatest common factor we can rewrite the expression:

10(2+7) $\displaystyle 10(2+7)$

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Example Question #41 : How To Find The Distributive Property

Use the distributive property to express the sum 80+110 $\displaystyle 80+110$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

$\displaystyle 5(16+11)$

$\displaystyle 10(6+11)$

$\displaystyle 10(8+12)$

$\displaystyle 10(13+11)$

$\displaystyle 10(8+11)$

Correct answer:

$\displaystyle 10(8+11)$

Explanation:

80+110 $\displaystyle 80+110$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=10$ $\displaystyle \text{GCF}=10$

After we reduce each addend by the greatest common factor we can rewrite the expression:

$\displaystyle 10(8+11)$

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Example Question #42 : How To Find The Distributive Property

Use the distributive property to express the sum 50+130 $\displaystyle 50+130$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

$\displaystyle 10(6+14)$

$\displaystyle 10(6+13)$

None of these

$\displaystyle 10(5+12)$

$\displaystyle 10(5+13)$

Correct answer:

$\displaystyle 10(5+13)$

Explanation:

50+130 $\displaystyle 50+130$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=10$ $\displaystyle \text{GCF}=10$

After we reduce each addend by the greatest common factor we can rewrite the expression:

$\displaystyle 10(5+13)$

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Example Question #33 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Use the distributive property to express the sum 121+11 $\displaystyle 121+11$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

$\displaystyle 11(13+1)$

$\displaystyle 11(11+1)$

$\displaystyle 11(12+1)$

$\displaystyle 13(11+1)$

$\displaystyle 11(11+3)$

Correct answer:

$\displaystyle 11(11+1)$

Explanation:

121+11 $\displaystyle 121+11$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=11$ $\displaystyle \text{GCF}=11$

After we reduce each addend by the greatest common factor we can rewrite the expression:

$\displaystyle 11(11+1)$

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Example Question #43 : How To Find The Distributive Property

Use the distributive property to express the sum 132+77 $\displaystyle 132+77$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

$\displaystyle 11(13+7)$

9(13+7) $\displaystyle 9(13+7)$

$\displaystyle 12(9+13)$

$\displaystyle 11(12+7)$

None of these

Correct answer:

$\displaystyle 11(12+7)$

Explanation:

132+77 $\displaystyle 132+77$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=11$ $\displaystyle \text{GCF}=11$

After we reduce each addend by the greatest common factor we can rewrite the expression:

$\displaystyle 11(12+7)$

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Example Question #35 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Use the distributive property to express the sum 88+33 $\displaystyle 88+33$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

11(8+3) $\displaystyle 11(8+3)$

10(8+3) $\displaystyle 10(8+3)$

11(4+3) $\displaystyle 11(4+3)$

9(8+3) $\displaystyle 9(8+3)$

11(8+6) $\displaystyle 11(8+6)$

Correct answer:

11(8+3) $\displaystyle 11(8+3)$

Explanation:

88+33 $\displaystyle 88+33$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=11$ $\displaystyle \text{GCF}=11$

After we reduce each addend by the greatest common factor we can rewrite the expression:

11(8+3) $\displaystyle 11(8+3)$

Report an Error

Example Question #36 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Use the distributive property to express the sum 110+22 $\displaystyle 110+22$ as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

None of these

$\displaystyle 11(20+2)$

$\displaystyle 11(12+2)$

$\displaystyle 11(10+2)$

$\displaystyle 11(10+4)$

Correct answer:

$\displaystyle 11(10+2)$

Explanation:

110+22 $\displaystyle 110+22$

In this case, the greatest common factor shared by each number is:

$\text{GCF}=11$ $\displaystyle \text{GCF}=11$

After we reduce each addend by the greatest common factor we can rewrite the expression:

$\displaystyle 11(10+2)$

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SSAT Middle Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #27 : Find Greatest Common Factor

Example Question #28 : Find Greatest Common Factor

Example Question #29 : Find Greatest Common Factor

Example Question #34 : How To Find The Distributive Property

Example Question #41 : How To Find The Distributive Property

Example Question #42 : How To Find The Distributive Property

Example Question #33 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Example Question #43 : How To Find The Distributive Property

Example Question #35 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Example Question #36 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

All SSAT Middle Level Math Resources

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