To solve this problem, first perform algebra on the given equation to isolate the  terms on one side of the equation and the numeric terms on the other. That means subtracting  from both sides and adding  to both sides to get:

You can then divide both sides by  to realize that .

Now, notice that the question did not ask you for the value of , but rather for the value of . So you now need to plug in  for  to finish the job: 

To answer this problem, you need to first solve for  in the given equation. You can first multiply each side by  to eliminate the denominator, yielding:

Then divide each side by  to isolate :

Now you can plug in  for  in the given expression. That yields: 

It can be easier to line real and imaginary parts vertically to keep things organized, but in essence, combine like terms (where 'like' here means real or imaginary):

When adding and subtracting complex numbers, the “” functions just like a regular variable, the same as if it were “” or any other letter variable. It is only when multiplying and dividing complex numbers that there is a special step where  is transformed into . This question simply asks you to subtract one complex number from another one, so “” functions just like any other letter variable.

First subtract the real number parts: . Then subtract the imaginary number parts: . Putting the parts together gives you the correct answer choice .

The tricky step is . Subtracting a negative is the same thing as adding a positive since the negative signs cancel each other out. Failure to do this step correctly can lead to the wrong answer choice .

Students who are expecting the question to be more challenging than it actually is may see the complex numbers in parentheses and jump to the conclusion that they need to multiply the complex numbers rather than just subtract them. Incorrectly multiplying the complex numbers  rather than subtracting them will lead to the wrong answer choice .

Multiplying the complex numbers and also making a mistake when multiplying  may lead to the wrong answer choice .

When adding and subtracting complex numbers, the “” functions just like a regular variable, the same as if it were “” or any other letter variable. It is only when multiplying and dividing complex numbers that there is the special step where  is transformed into . This question simply asks you to subtract one complex number from another one, so “” functions just like any other letter variable.

First subtract the real number parts: . Then subtract the imaginary number parts: . Putting the parts together gives you the correct answer choice .

To do both these subtraction steps correctly, the student needs to keep track of all the signs accurately and understand that subtracting a negative is the same thing as adding a positive, since the negative signs cancel each other out. Failure to do this step correctly with the imaginary number parts can lead to the wrong answer choice . Failure to do this step correctly with the real number parts and the imaginary number parts can lead to the wrong answer choice .

Students who are expecting the question to be more challenging than it actually is may see the complex numbers in parentheses and jump to the conclusion that they need to multiply the complex numbers rather than just subtract them. Incorrectly multiplying the complex numbers  rather than subtracting them will lead to the wrong answer choice .

When adding and subtracting complex numbers, the “” functions just like a regular variable, the same as if it were “” or any other letter variable. It is only when multiplying and dividing complex numbers that there is the special step where  is transformed into . This question simply asks you to add two complex numbers, so “” functions just like any other letter variable.

First add the real number parts . Then add the imaginary number parts . Putting the parts together gives you the correct answer choice .

It is easy to get confused when adding two negative numbers, which is the other main challenge in this question. Many students see it as a subtraction operation, so they want to say that . But when both numbers are negative, it works more like addition, but with every number having a negative sign. Failure to understand this concept and perform this operation correctly with the real number parts may lead to the wrong answer choice . Failure to understand this concept and perform this operation correctly with the imaginary number parts may lead to the wrong answer choice  Failure to understand this concept and perform this operation correctly with both parts may lead to the wrong answer choice .

There are a few tricks to this question. First of all, you must carefully observe the minus sign in the middle of the expression, which means that you are subtracting the complex numbers, not multiplying them! 

Second, you must note the term  in the second complex number. Now you have to know that because , therefore . So . Now our whole expression is . 

Finally, now you have to be very careful about all the minus signs! For both of the terms in the second complex number, you are now subtracting a negative, which means that you are actually just doing the same thing as adding a positive! Therefore, the whole expression is simply equivalent to . Now it looks much easier, doesn’t it? Simply adding together the real number parts and the imaginary number parts separately, you get the final answer, the correct answer choice . 

If you do not simplify  correctly, or if you accidentally subtract  instead of add  in the final step, you may get one of the wrong answer choices  or . If you accidentally subtract  instead of add  in the final step, you may get one of the wrong answer choices  or .

There are a few tricks to this question. First of all, you must carefully observe the minus sign in the middle of the expression, which means that you are subtracting the complex numbers, not multiplying them! 

Second, you must note the term  in the second complex number. Now you have to know that because , therefore . So . Now our whole expression is . 

Finally, now you have to be very careful about all the minus signs! For both of the terms in the second complex number, you are now subtracting a negative, which means that you are actually just doing the same thing as adding a positive! Therefore, the whole expression is simply equivalent to . Now it looks much easier, doesn’t it? Simply adding together the real number parts and the imaginary number parts separately, you get the final answer, the correct answer choice . 

If you do not simplify  correctly, or if you accidentally subtract  instead of add  in the final step, you may mistakenly think the “” and “” terms cancel out, and get one of the wrong answer choices  or . If you accidentally subtract  instead of add  in the final step, you may get one of the wrong answer choices 8i or .

This is the classic more difficult type of complex number/imaginary number question on the SAT math section: Division of one complex number by another complex number. The most difficult and critical key step of the solution process is the very first step: You must multiply both the numerator and denominator by what we call the complex conjugate of the denominator, which is a fancy term that just means you change the sign in the middle of the complex number (before the imaginary part). The reason we do this is that this will make the imaginary part in the denominator disappear! Recall the difference of squares formula in algebra: . This formula works because when you FOIL , the two middle terms  will cancel each other out. Well, the same thing happens here when you multiply the complex number in the denominator by its complex conjugate: the imaginary number middle terms will cancel each other out! So . The middle terms  cancel each other out, leaving us with . Now you have to know that because , therefore  So , and now the negative signs in the second term cancel out, making it positive: . The point of this whole process is that the end result is to simplify the denominator to a single real number, which in this case is . 

To finish solving the question, now you must also multiply the original numerator by the complex conjugate of the denominator: . The two middle terms, the imaginary parts, combine: .

Pro Tip: If you are alert here, you can already see that the imaginary part of the final answer will have  in the numerator and  in the denominator! This alone eliminates all of the wrong answer choices, so you can already see now that the correct answer choice must be !

If you do need to finish the solution and know the numerator of the real part as well, you continue , since you must know that  as we stated above. Finishing the simplification of the numerator, we get . Now we see how the entire correct answer choice  is right.

You may wonder how experienced math students can finish solving questions so fast and complete both SAT math sections within the strict time limits and still get perfect 800 SAT Math scores. The answer is, they use the four answer choices to guide them and speed up the process dramatically. Look at the answer choices  and . Do you see how they have exactly the same numbers and coefficients as the numerator and denominator of the expression in the original question? Well, experienced math students know that simplification of a fraction like this one with two or more terms in the denominator that are added or subtracted is never this simple! It always involved a more complicated process that inevitably changes the numbers and coefficients in the final answer. So experienced math students can eliminate these two answer choices instantly as soon as they look at them.

Then, looking at the other two answer choices  and , experienced math students see that the only difference between them is the sign in the middle, before the imaginary part. So the only step they have to do is to multiply the numerator by the complex conjugate of the denominator, . As soon as they see that the imaginary part of the numerator will have to be negative, , they already instantly know that  must be wrong, and  must be right. (See the Pro Tip above.) This is how the top SAT math students are able to answer difficult questions like this one so quickly and correctly.

This is the classic more difficult type of complex number/imaginary number question on the SAT math section: Division of one complex number by another complex number. The most difficult and critical key step of the solution process is the very first step: You must multiply both the numerator and denominator by what we call the complex conjugate of the denominator, which is a fancy term that just means you change the sign in the middle of the complex number (before the imaginary part). The reason we do this is that this will make the imaginary part in the denominator disappear! Recall the difference of squares formula in algebra: . This formula works because when you FOIL , the two middle terms  will cancel each other out. Well, the same thing happens here when you multiply the complex number in the denominator by its complex conjugate: the imaginary number middle terms will cancel each other out! So . The middle terms  cancel each other out, leaving us with . Now you have to know that because , therefore  So , and now the negative signs in the second term cancel out, making it positive: . The point of this whole process is that the end result is to simplify the denominator to a single real number, which in this case is . 

To finish solving the question, now you must also multiply the original numerator by the complex conjugate of the denominator: . The two middle terms, the imaginary parts, combine: .

Pro Tip: If you are alert here, you can already see that the imaginary part of the final answer will have in the numerator and  in the denominator! This alone eliminates all of the wrong answer choices, so you can already see now that the correct answer choice must be !

If you do need to finish the solution and know the numerator of the real part as well, you continue , since you must know that  as we stated above. Finishing the simplification of the numerator, we get . Now we see how the entire correct answer choice  is right.

You may wonder how experienced math students can finish solving questions so fast and complete both SAT math sections within the strict time limits and still get perfect 800 SAT Math scores. The answer is, they use the four answer choices to guide them and speed up the process dramatically. Look at the answer choices  and . Do you see how they have exactly the same numbers and coefficients as the numerator and denominator of the expression in the original question? Well, experienced math students know that simplification of a fraction like this one with two or more terms in the denominator that are added or subtracted is never this simple! It always involved a more complicated process that inevitably changes the numbers and coefficients in the final answer. So experienced math students can eliminate these two answer choices instantly as soon as they look at them.

Then, looking at the other two answer choices  and , experienced math students see that the only difference between them is the sign in the middle, before the imaginary part. So the only step they have to do is to multiply the numerator by the complex conjugate of the denominator, . As soon as they see that the imaginary part of the numerator will have to be negative, , they already instantly know that  must be wrong, and  must be right. (See the Pro Tip above.) This is how the top SAT math students are able to answer difficult questions like this one so quickly and correctly.