In this word problem, it's first helpful to assign meaningful variables. Since the matinee equation is the "cleaner" of the two, you might start with:

Meaning that  the number of adult tickets to the matinee and  the number of children's tickets to the matinee.

Then look at the second equation. Since  is the same for each equation you're done there, but then unpack the relationship between matinee children's tickets and evening children's tickets. If, for the evening show, the number was "20 less than double," that means that you'd double the earlier number of children's tickets  and subtract 20 to get . That means that your second equation is:

So you have two equations now:

So use the Elimination Method and subtract the simpler, matinee equation from the more-complex, evening equation and you'll be left with:

So 

But remember: C is the number of children's matinee tickets, so you'll need to convert to the number of children's evening tickets. That number is , which equals 80.

This word problem starts you off with two equations. If you assign variables as  = bats and  = balls, you have:

, which reduces to 

and

You can then use the Elimination Method to eliminate the  terms and solve for :

, so . Plug that back in, and . So now you have the prices.

At this point, you know that you need the same number of  and , and that the total can only be as high as $240. If you call that same number , you have:

. So you'll be able to buy 4 bats and 4 balls.

Since you know that Jackie will purchase exactly one video game for $40, you can set up your equation (or inequality) here as:

Where  represents the number of books she buys. Since we're looking for the minimum number of books she needs to buy in order to be greater than or equal to $120, we use the greater-than-or-equal-to inequality.

Now you can subtract 40 from both sides:

And when you divide both sides by 30 you'll see that you have a number between 2 and 3. Note that you do not have to do the full decimal calculation, because you cannot buy part of a book! So since she can't buy 2.67 books, the minimum number she can purchase is 3.

To turn this problem into an equation, you can start by putting Katharine's goal of $50,000 on one side of the equation, and then arranging all of the inputs to that goal (ways she earns money) and impediments (ways she loses money) on the other. If you use m to represent the number of months, an initial equation would look like:

$50,000 = $10,000 + $6,500m - $4,000m

Which, qualitatively, is that her goal of $50,000 is equal to the $10,000 she has plus the $6,500 she earns each month, minus the $4,000 she loses each month.

Now you can combine like terms to simplify the equation:

$40,000 = $2,500m

And then divide 40000 by 2500 (which simplifies to 400 divided by 25) to solve:

m = 16 months

To translate this word problem into equation form, note that your unknown is the capacity of the pool. You know that the pool is currently half full and that with the proposed addition it would be 2/3 full, but you need to assign those fractions to an actual value. So your variable, , will represent the total capacity of the pool. Then you can set up your problem as:

From here it's an algebra problem. To get your  terms together, subtract  from both sides:

Then you'll need to find a common denominator of 6, and rewrite what you have to reflect that common denominator:

You can then combine like terms on the right-hand side of the equation:

And then multiply both sides by 6 to finish the problem:

To translate this word problem into equations, first assign variables to the new beams. Since you know there will be a longer and a shorter beam you might use  for longer and  for shorter. You would then have:

 (the total length is 48)

 (the longer is 20 more than the shorter)

You can then substitute the second equation into the first, replacing  with . This then gives you:

So  and 

But remember - the question asked you for the LONGER beam, so you'll need to plug that back in to one of the equations. Since  you can say that , so 34 is the correct answer.

While it is tempting to set up and solve an equation for this problem, the algebra for this problem may be difficult to translate quickly and accurately. Because you are dealing with relatively simple numbers that add up to a total, you should see that this should be an easy problem to backsolve.

Start with a total of , $80. If Shay paid $7 less than half of the total, that means she paid , or .

And if Ashley paid $8 more than  of the bill, that means that she paid , or $28. That means that Jenna must have paid the remainder, . However, since you know that Jenna paid $20, you should recognize that the total for answer choice $80 was too small and that the actual bill must have been slightly more.

You can go through the same process with answer choice $84. If Shay paid $7 less than half of the total, she paid .

And if Ashley paid $8 more than  of the bill, that means that she paid .

Since you know that Jenna paid $20, you should recognize that . Since the original total and the final sum match up, you can conclude that $84 is your answer, pick it, and move on.

Alternatively, you could set up the algebra:

While the problem setup here may seem a bit involved, if you are quick to combine like terms you should see that the algebra is very manageable here. You're given two fractions of the bill ( and  of the total) and three actual values (for Shay subtract 7, for Ashley add 8, and for Jenna add 20). So what you really have when you combine all of your like terms is:

 (where  represents the total bill). Since $21 represents the missing  of the bill, the bill is 4($21) = $84.

This problem can be solved algebraically but is likely solved more quickly by simply back solving. Your algebra would set up as:

 (eight times one-third of a number)  (is one greater than)  (five times one half of that number).

Those who are algebraically inclined could of course find common denominator, combine the  terms, and solve (more on that below). But others might be quicker looking at the answer choices. Since one of the first steps the problem tells you is that the number has to be divided by three ("eight times one-third of a number"), you'll want to plug in a number divisible by three for an easy start. And since you'll also have to divide that number by 2 ("five times one half that number"), you'll want an even one.

So start with 6. Eight times one-third of 6 is 8(2) = 16. Is that one greater than five times one half of 6? It is. Five times one half of 6 is 5(3) = 15. The relationship works, so 6 is correct.

To begin on this problem, first take  of 480 to determine that there are currently 120 hybrid cars. So if half were to be sold, then that would leave 60 hybrids.

Importantly, note that if 60 hybrids are sold, that means that 60 of the total of 480 cars are sold. That affects both the number of hybrids AND the number of total cars, which is now reduced to 420. So your new proportion of hybrids is the 60 hybrids out of the 420 total cars: