Whenever you have a chance to solve a system of equations using the Elimination Method, it is generally your fastest option. Here if you multiply the first equation by 2, you can then subtract the two equations:

 gives you a new first equation of .  When you then stack and subtract:

You're left with:

So .

Then just plug  back in to one of the two equations and you can solve for . If you use the first, you'll have:

So .  This means that the ordered pair is .

This problem provides you with a quick opportunity to use the Elimination Method. Because there is an  in the first equation and  in the second, if you add the two equations you can eliminate the  terms and solve straight for :

This means that .  

Then you can plug  into either of the equations and you'll solve for . Using the first equation, that would be:

So 

This means that the correct ordered pair is .

The first step on this problem is to take the equation you're given, , and solve for . To do that, divide both sides by  to arrive at . Importantly, recognize that the question is not asking for the value of , but rather for the value of the expression . To find that answer, plug in  and the expression will look like . This then equals , making the correct answer .

Whenever you're solving for a variable in an equation that has fractions, it's a good first step to multiply both sides by the denominator to get all the variables and values outside of the fractions. Here that means. multiplying both sides by  to get .

Next, you have a linear equation in which the variable has a coefficient, so divide by the coefficient to isolate the variable. If you divide both sides by , you then have: . You can then reduce the fraction  to , and since the answer choices only use integers and decimals, you can convert the fraction to the proper decimal, 

The first step on this problem is to use the equation that you're provided so that you can solve for . To do so, take  and divide both sides by . That leaves you with . Of course, the question doesn't ask you for the value of , but rather the value of . So plug in  and the expression looks like:  which is . That simplifies to , giving you your final answer.

Note that this problem does not ask you to solve for a particular variable, but instead a particular fraction or ratio, . For that reason, your goal as you perform algebra should be to isolate the ratio of  and . You can do that by multiplying both sides by . That gives you:

, which simplifies to .  

You can then just flip each fraction (in doing so, you're doing the same thing to both sides, namely taking the reciprocal), to get:

, which simplifies to .

The first key to this problem is to combine like terms; each side of the equation has multiple  terms for you to sum to simplify the equation.  Your streamlined equation should look like:

Now you can get all the  terms on one side and all the numeric terms on the other so that you're ready to solve. That means subtracting  and  from each side, yielding:

Then you can divide both sides by  to arrive at your final answer:

To solve this problem algebraically, take the given equation and subtract  from both sides to isolate the  term. That gives you:

Then you can divide both sides by  to yield:

When you plug in  to , that gives you , which is .

To solve this problem algebraically, distribute the multiplication across each set of parentheses, remembering to multiply each term within the parentheses by its coefficient. That gives you:

Then you can combine like terms on the left side, since you have two  terms and two numeric terms. That simplifies to:

From there, subtract  from both sides and you have your answer, .