All SAT Math Resources
Example Questions
Example Question #33 : Proportion / Ratio / Rate
If an airplane is flying 225mph about how long will it take the plane to go 600 miles?
3.5 hours
2.4 hours
2.5 hours
2.7 hours
3.2 hours
2.7 hours
Speed = distance /time; So by solving for time we get time = distance /speed. So the equation for the answer is (600 miles)/ (225 miles/hr)= 2.67 hours; Remember to round up when the last digit of concern is 5 or more.
Example Question #31 : Fractions
Vikki is able to complete 4 SAT reading questions in 6 minutes. At this rate, how many questions can she answer in 3 1/2 hours?
35
140
150
170
210
140
First, find how many minutes are in 3 1/2 hours: 3 * 60 + 30 = 210 minutes. Then divide 210 by 6 to find how many six-minute intervals are in 210 minutes: 210/6 = 35. Since Vikki can complete 4 questions every 6 minutes, and there are 35 six-minute intervals we can multiply 4 by 35 to determine the total number of questions that she can complete.
4 * 35 = 140 problems.
Example Question #32 : Proportion / Ratio / Rate
The price of k kilograms of quartz is 50 dollars, and each kilogram makes s clocks. In terms of s and k, what is the price, in dollars, of the quartz required to make 1 clock?
We want our result to have units of "dollars" in the numerator and units of "clocks" in the denominator. To do so, put the given information into conversion ratios that cause the units of "kilogram" to cancel out, as follows: (50 dollar/k kilogram)* (1 kilogram / s clock) = 50/(ks) dollar/clock.
Since the ratio has dollars in the numerator and clocks in the denominator, it represents the dollar price per clock.
Example Question #11 : How To Find Rate
Minnie can run 5000 feet in 15 minutes. At this rate of speed, how long will it take her to fun 8500 feet?
25.5 min
75.5 min
36.5 min
20 min
18.5 min
25.5 min
Find the rate of speed. 5000ft/15 min = 333.33 ft per min
Divide distance by speed to find the time needed
8500ft/333.33ft per min = 25.5
Example Question #1401 : Sat Mathematics
Ruby drives to her grandmother's house and back. On the way there, she travels at an average speed of 40 miles per hour. On the way back, she travels at an average speed of 60 miles per hour. What is Ruby's average speed for the entire round trip?
40
48
52
60
50
48
Remember d=rt where d = distance, r = rate, and t = time. In this case, the distance to and the distance from are the same, so we know that
d = r1 t1 and d = r2 t2
Since r1 = 40 and r2 = 60, we can solve for the times and get
t1 = d/40 and t2 = d/60
Average speed is found by total distance over total time, so we get
Multiplying the numerator and denominator by 120/d we get 240/(3 + 2) = 48.
Example Question #41 : Proportion / Ratio / Rate
If an object takes 10 minutes to go 3 miles, how fast is the object going?
36 mph
18 mph
10/3 mph
3/10 mph
1/2 mph
18 mph
First convert minutes to hours, so 10 minutes is 1/6 hours; then remember distance = rate * time, so distance/time = rate then 3/(1/6) = 18 mph
Example Question #41 : Proportion / Ratio / Rate
Mary travels at a constant speed to her friend Clara's house by walking directly east for 8 miles, and then walking directly north for 6 miles. The amount of time that it takes her to reach Clara's house is equal to t. If Mary had been able to travel directly to Clara's house in a straight line at the same speed, how much time would she have saved, in terms of t?
5t/7
3t/7
6t/7
2t/7
4t/7
2t/7
Example Question #21 : How To Find Rate
Sam earns d dollars per day. At this rate, how many days will it take Sam to earn q dollars?
10q
100d/q
d/q
q/d
dq
q/d
q is the number of dollars to be earned, d is the amount earned each day, so you divide q by d to get the number of days.
Example Question #44 : Proportion / Ratio / Rate
Bob can build a house in 3 days. Gary can build a house in 5 days. How long does it take them to build a house together?
3/2 days
4 days
2 days
5/4 days
15/8 days
15/8 days
DO NOT pick 4 days, which would be the middle number between Bob and Gary's rates of 3 and 5 days respectively. The middle rate is the answer that students always want to pick, so the SAT will provide it as an answer to trick you!
Let's think about this intuitively before we actually solve it, so hopefully you won't be tempted to pick a trick answer ever again! Bob can build the house in 3 days if he works by himself, so with someone else helping him, it has to take less than 3 days to build the house! This will always be true. Never pick the middle rate on a combined rates problem like this!
Now let's look at the problem computationally. Bob can build a house in 3 days, so he builds 1/3 of a house in 1 day. Similarly, Gary can build a house in 5 days, so he builds 1/5 of a house in 1 day. Then together they build 1/3 + 1/5 = 5/15 + 3/15 = 8/15 of the house in 1 day.
Now, just as we did to see how much house Gary and Bob can build separately in one day, we can take the reciprocal of 8/15 to see how many days it takes them to build a house together. (When we took the reciprocal for Bob, 3 days/1 house = 1/3 house per day.) The reciprocal of 8/15 is 15/8, so they took 15/8 days to build the house together. 15/8 days is almost 2 days, which seems like a reasonable answer. Make sure your answer choices make sense when you are solving word problems!
Example Question #41 : Proportion / Ratio / Rate
Two brothers, Jake and Fred, have a pool in which 9 laps is 1 mile. Jake swims 2 laps in 1 minute, and Fred swims 4 laps in 1 minute. How far has Jake swum when Fred has finished swimming 2 miles?
2 miles
3/2 miles
3/4 miles
1 mile
9/2 miles
1 mile
We can solve this with lots of calculations and conversions of laps to miles, etc., or we can look at what the question is really asking. We want to know how far Jake swims in the time it takes Fred to swim two miles. Instead of converting Fred's miles to laps and comparing to Jake's laps, let's just look at how fast the two brothers swim in relation to one another. Fred swims twice as fast as Jake, so in the same amount of time, he will swim twice as far as Jake. Therefore if Fred swims 2 miles, Jake swims 1 mile in the same amount of time.
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