Calculate the number of feet walked in an hour.  Then calculate what fraction of an hour 40 minutes is.

5280 * 4 = 21120 feet walked in an hour

60 minutes in an hour, so 40 minutes = 2/3 hour (40/60)

21120(2/3) = 14080 feet walked in 40 minutes

We can rewrite this as two equations

5/2 = x/y

x – y = 21

Solve y for x in the second equation: x = 21 + y → y = x – 21

Substitute back into the first equation and solve:

5/2 = x/(x – 21)

5(x – 21)/2 = x → (5x – 105)/2 = x → 5x – 105 = 2x → 5x – 2x = 105 → 3x = 105; x = 105/3 = 35

Since we know the numerator must be larger (given the prompt), the answer is x, or 35.

First, we need to figure out how many red, blue, and green marbles are in the bag before any are removed. Let 5x represent the number of red marbles. Because the marbles are in a ratio of 5 : 2 : 1, then if there are 5x red marbles, there are 2x blue, and 1x green marbles. If we add up all of the marbles, we will get the total number of marbles, which is 240.

5x + 2x + 1x = 240

8x = 240

x = 30

Because the number of red marbles is 5x, there are 5(30), or 150 red marbles. There are 2(30), or 60 blue marbles, and there are 1(30), or 30 green marbles.

So, the bag originally contains 150 red, 60 blue, and 30 green marbles. We are then told that one-third of the red marbles is removed. Because one-third of 150 is 50, there would be 100 red marbles remaining. Next, two-thirds of the green marbles are removed. Because (2/3)(30) = 20, there would be 10 green marbles left after 20 are removed.

To summarize, after the marbles are removed, there are 100 red, 60 blue, and 10 green marbles. The question asks us for the fraction of blue marbles in the bag after the marbles are removed. This means there would be 60 blue marbles out of the 170 left in the bag. The fraction of blue marbles would therefore be 60/170, which simplifies to 6/17.

The answer is 6/17.

If Charlie is 2 years old now; in 10 years he will be 12 years old. At that point, Alan will be twice as old as Charlie. Twice 12 is 24. This means that Alan is currently 10 years younger than 24, or 14. Since Alan is currently twice as old as Betty, she must be half of 14, or 7.

Another way to express ratios is through division.  10 divided by 14 is approximate 0.71.

3 filters can support a total of 120 creatures/plants.  The fish he wants need 2 plants for every 5 fish.  The plant needs 4 cleaning fish per 3 plants.  Thus for every 15 of the fish he wants, he needs 6 plants and 8 cleaning fish.

This gives us a total of 29 creatures.  We can complete this number 4 times, but then we are left with 4 spots open that the filters can support.

This is where the trick arises.  We can actually add one more fish in.  Since 1 plant supports up to 2.5 fish (2:5), and 2 cleaning fish support up to 1.5 plants, we can add 1 fish, 1 plant, and 2 cleaning fish to get a total of 120 creatures.  If we attempt to add 2 fish, then we must also add the 1 plant, but then we don't have enough space left to add the 2 cleaning fish necessary to support the remaining plant.

Thus Tom can buy at most 61 of the fish he originally wanted to get.

You will get this problem wrong if you do not pay attention to what is being asked. The problem states that the ratio of m to n is .

Because the problem asks for the ratio of 3n to m, we have to multiply 13 * 3 = 39 to get 3n and 5 * 1 = 5 to get m (or 1m).

Then the requested ratio of 3n to m is 39 to 5 or .

In order to maintain a proportion, each value in the ratio must be multiplied by the same value:

Before and after the snakes arrive, the number of lizards stays constant.

Before new snakes — Snakes : Lizards = 3x : 5x

After new snakes — Snakes : Lizards = 4x : 5x

Before the new snakes arrive, there are 3x snakes. After the 15 snakes are added, there are 4x snakes. Therefore, 3x + 15 = 4x. Solving for x gives x = 15.

There are 5x lizards, or 5(15) = 75 lizards.

Multiply the ratios. (q/r)(r/s)= q/s. (3/5) * (10/7)= 6:7.

Let  be the number of store employees,  the number of store managers, and  the number of corporate managers.

, so the number of store employees is .

, so the number of store managers is .

, so the number of corporate managers is .

Therefore, the number of employees who are either store managers or corporate managers is .