All SAT II Math I Resources
Example Questions
Example Question #61 : Geometry
Regular Pentagon has a perimeter of eighty.
Give the length of diagonal to the nearest tenth.
The perimeter of the regular pentagon is 80, so each side measures one fifth of this, or 16. Also, each interior angle of a regular pentagon measures .
The pentagon, along with diagonal , is shown below:
A triangle is formed with , and included angle measure . The length of the remaining side can be calculated using the law of cosines:
,
where and are the lengths of two sides, the measure of their included angle, and the length of the side opposite that angle.
Setting , and , substitute and evaluate :
Taking the square root of both sides:
,
the correct choice.
Example Question #141 : Quadrilaterals
is rhombus with side lengths in meters. and . What is the length, in meters, of ?
30
24
15
5
12
24
A rhombus is a quadrilateral with four sides of equal length. Rhombuses have diagonals that bisect each other at right angles.
Thus, we can consider the right triangle to find the length of diagonal . From the given information, each of the sides of the rhombus measures meters and .
Because the diagonals bisect each other, we know:
Using the Pythagorean theorem,
Example Question #1 : Finding Angles
What angle do the minute and hour hands of a clock form at 4:45?
There are twelve numbers on a clock; from one to the next, a hand rotates . At 4:45, the minute hand is exactly on the "9" - that is, at the . The hour hand is three-fourths of the way from the "4" to the "5" - that is, on the position. Therefore, the difference is the angle they make:
Example Question #2 : Finding Angles
What angle do the minute and hour hands of a clock form at 8:50?
There are twelve numbers on a clock; from one to the next, a hand rotates . At 8:50, the minute hand is exactly on the "10" - that is, on the position. The hour hand is five-sixth of the way from the "8" to the "9" - that is, on the position. Therefore, the difference is the angle they make:
.
Example Question #3 : Finding Angles
Note: Figure NOT drawn to scale.
The above hexagon is regular. What is ?
Two of the angles of the quadrilateral formed are angles of a regular hexagon, so each measures
.
The four angles of the quadrilateral are . Their sum is , so we can set up, and solve for in, the equation:
Example Question #1 : Finding Angles
Can a triangle have a set of angles that are and degrees?
No
Yes
No
A triangle's angles must add up to degrees.
The angles given add up to 181,
.
That means that this cannot be an actual triangle.
Example Question #5 : Finding Angles
If two angles of a triangle are and , find the measurement of the third angle.
Step 1: Recall the sum of the angles of a triangle...
The sum of the internal angles of a triangle is .
Step 2: To find the missing angle, subtract the given angles from ...
Example Question #61 : Geometry
The sides of a triangle have lengths 6 yards, 18 feet, and 216 inches. Which of the following is true about this triangle?
This triangle is acute and scalene.
The triangle is acute and equilateral.
This triangle is acute and isosceles, but not equilateral.
This triangle is right and isosceles, but not equilateral.
This triangle is right and scalene.
The triangle is acute and equilateral.
One yard is equal to 3 feet; it is also equal to 36 inches. Therefore:
18 feet is equal to yards,
and
216 feet is equal to yards.
The three sides are congruent, making the triangle equilateral - and all equilateral triangles are acute.
Example Question #2 : Analyzing Figures
Figures not drawn to scale
The triangles above are similar. Given the measurements above, what is the length of side c?
inches
inches
inches
inches
inches
inches
You can find the length of c by first finding the length of the hypotenuse of the larger similar triangle and then setting up a ratio to find the hypotenuse of the smaller similar triangle.
You also could have found 10 by recognizing this triangle is a form of a 3-4-5 triangle.
The hypotenuse of the bigger triangle is 10 inches.
Now that we know the length of the hypotenuse for the larger triangle, we can set up a ratio equation to find the hypotenuse of the smaller triangle.
cross multiply
Example Question #62 : Geometry
If line 2 and line 3 eventually intersect when extended to the left which of the following could be true?
I, II, and III
I and III
Cannot be determined
I and II
I only
I only
Read the question carefully and notice that the image is deceptive: these lines are not parallel. So we cannot apply any of our rules about parallel lines. So we cannot infer II or III, those are only true if the lines are parallel. If we sketch line 2 and line 3 meeting we will form a triangle and it is possible to make a = e. One such solution is to make a and e 60 degrees.
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