All SAT II Math I Resources
Example Questions
Example Question #71 : Geometry
What is the maximum number of distinct regions that can be created with 4 intersecting circles on a plane?
Try sketching it out.
Start with one circle and then keep adding circles like a venn diagram and start counting. A region is any portion of the figure that can be defined and has a boundary with another portion. Don't forget that the exterior (labeled 14) is a region that does not have exterior boundaries.
Example Question #72 : Geometry
Note: Figure may not be drawn to scale
In rectangle has length and width and respectively. Point lies on line segment and point lies on line segment . Triangle has area , in terms of and what is the possible range of values for ?
cannot be determined
Notice that the figure may not be to scale, and points and could lie anywhere on line segments and respectively.
Next, recall the formula for the area of a triangle:
To find the minimum area we need the smallest possible values for and .
To make smaller we can shift points and all the way to point . This will make triangle have a height of :
is the minimum possible value for the area.
To find the maximum value we need the largest possible values for and . If we shift point all the way to point then the base of the triangle is and the height is , which we can plug into the formula for the area of a triangle:
which is the maximum possible area of triangle
Example Question #72 : Geometry
Which of the following describes a triangle with sides of length 10 inches, 1 foot, and 2 feet?
This is an obtuse triangle.
This is an acute triangle.
This triangle cannot exist.
This is a right triangle.
More information is needed to answer this question.
This triangle cannot exist.
One foot is equal to 12 inches, so the triangle would have sides 10, 12, and 24 inches. Since
,
the triangle violates the Triangle Inequality, which states that the sum of the lengths of the two smaller sides must exceed the length of the third. The triangle cannot exist.
Example Question #73 : Geometry
Which of the following describes a triangle with sides of length nine yards, thirty feet, and 360 inches?
The triangle is acute and scalene.
The triangle cannot exist.
The triangle is obtuse and scalene.
The triangle is obtuse and isosceles.
The triangle is acute and isosceles.
The triangle is acute and isosceles.
Nine yards is equal to inches.
30 feet is equal to inches.
In terms of inches, the triangle has sides of length 324, 360, 360; this exists since
and this is an isosceles triangle, since two sides have the same length.
Also,
,
making the triangle acute.
Example Question #3 : Other 2 Dimensional Geometry
Refer to the above diagram. Which of the following choices gives a set of collinear points?
Collinear points are points that are contained in the same line. Of the four choices, only fit the description, since all are on Line .
Example Question #4 : Other 2 Dimensional Geometry
You are given triangles and , with . Which of these statements, along with what you are given, is enough to prove that ?
and have the same perimeter.
None of the other responses is correct.
gives us the congruence of two corresponding angles and one corresponding side; this is not enough to establish similarity.
The perimeters of the triangles are irrelevant to their similarity, so and having the same perimeter does not help to establish similarity, with or without what is given.
establishes the proportionality of two nonincluded sides of the angles known to be congruent. However, there is no statement that establishes similarity as a result of this.
, along with , sets up the conditions of the Angle-Angle Similarity Postulate, which states that if two triangles have two pairs of congruent angles between them, the triangles are similar. is the correct choice.
Example Question #77 : 2 Dimensional Geometry
Regular Octagon has perimeter 80. has as its midpoint; segment is drawn. To the nearest tenth, give the length of .
Below is the regular Octagon , with the referenced midpoint and segment . Note that perpendiculars have also been constructed from and to meet at and , respectively.
is a right triangle with legs and and hypotenuse .
The perimeter of the regular octagon is 80, so the length of each side is one-eighth of 80, or 10. Consequently,
To find the length of , we can break it down as
Quadrilateral is a rectangle, so .
is a 45-45-90 triangle with leg and hypotenuse ; by the 45-45-90 Triangle Theorem,
For similar reasons, .
Therefore,
can now be evaluated using the Pythagorean Theorem:
Substituting and evaluating:
,
the correct choice.
Example Question #1 : Volume
A circular swimming pool has diameter meters and depth 2 meters throughout. Which of the following expressions give the amount of water it holds, in cubic meters?
The pool can be seen as a cylinder with diameter - and, subsequently, radius half this, or - and depth, or height, 2. The volume of a cylinder is defined by the formula
Example Question #1 : Volume
The above depicts a rectangular swimming pool for an apartment. 60% of the pool is six feet deep, and the remaining part of the pool is four feet deep. How many cubic feet of water does the pool hold?
None of the other choices gives the correct answer.
None of the other choices gives the correct answer.
The cross-section of the pool is the area of its surface, which is the product of its length and its width:
square feet.
Since 60% of the pool is six feet deep, this portion of the pool holds
cubic feet of water.
Since the remainder of the pool - 40% - is four feet deep, this portion of the pool holds
cubic feet of water.
Add them together: the pool holds
cubic feet of water.
This answer is not among the choices.
Example Question #1 : Volume
Find the volume of a cube in inches with a side of
Convert the side dimension to inches first before finding the volume.
Write the volume for a cube and substitute the new side to obtain the volume in inches.
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