All High School Math Resources
Example Questions
Example Question #42 : Plane Geometry
The lengths of the three sides of a right triangle form a set of consecutive even integers when arranged from least to greatest. If the second largest side has a length of x, then which of the following equations could be used to solve for x?
(x – 1)2 + x2 = (x + 1)2
(x – 2) + x = (x + 2)
x 2 + (x + 2)2 = (x + 4)2
(x + 2)2 + (x – 2)2 = x2
(x – 2)2 + x2 = (x + 2)2
(x – 2)2 + x2 = (x + 2)2
We are told that the lengths form a series of consecutive even integers. Because even integers are two units apart, the side lengths must differ by two. In other words, the largest side length is two greater than the second largest, and the second largest length is two greater than the smallest length.
The second largest length is equal to x. The second largest length must thus be two less than the largest length. We could represent the largest length as x + 2.
Similarly, the second largest length is two larger than the smallest length, which we could thus represent as x – 2.
To summarize, the lengths of the triangle (in terms of x) are x – 2, x, and x + 2.
In order to solve for x, we can make use of the fact that the triangle is a right triangle. If we apply the Pythagorean Theorem, we can set up an equation that could be used to solve for x. The Pythagorean Theorem states that if a and b are the lengths of the legs of the triangle, and c is the length of the hypotenuse, then the following is true:
a2 + b2 = c2
In this particular case, the two legs of our triangle are x – 2 and x, since the legs are the two smallest sides; therefore, we can say that a = x – 2, and b = x. Lastly, we can say c = x + 2, since x + 2 is the length of the hypotenuse. Subsituting these values for a, b, and c into the Pythagorean Theorem yields the following:
(x – 2)2 + x2 = (x + 2)2
The answer is (x – 2)2 + x2 = (x + 2)2.
Example Question #3 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem
What is the hypotenuse of a right triangle with sides 5 and 8?
√89
12
8√13
15
5√4
√89
Because this is a right triangle, we can use the Pythagorean Theorem which says a2 + b2 = c2, or the squares of the two sides of a right triangle must equal the square of the hypotenuse. Here we have a = 5 and b = 8.
a2 + b2 = c2
52 + 82 = c2
25 + 64 = c2
89 = c2
c = √89
Example Question #1 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem
A right triangle has side lengths of 21 and 72. What is the length of the hypotenuse?
67
84
80
75
70
75
By the Pythagorean Theorem, 212 + 722 = hyp2. Then hyp2 = 5625, and the hypotenuse = 75. If you didn't know how to figure out that 752 = 5625, that's okay. Look at the answer choices. We could easily have squared them and chosen the answer choice that, when squared, equals 5625.
Example Question #4 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem
Sam and John both start at the same point. Sam walks 30 feet north while John walks 40 feet west. How far apart are they at their new locations?
Sam and John have walked at right angles to each other, so the distance between them is the hypotenuse of a triangle. The distance can be found using the Pythagorean Theorem.
Example Question #1 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem
Daria and Ashley start at the same spot and walk their two dogs to the park, taking different routes. Daria walks 1 mile north and then 1 mile east. Ashley walks her dog on a path going northeast that leads directly to the park. How much further does Daria walk than Ashley?
2 + √2 miles
Cannot be determined
1 mile
2 – √2 miles
√2 miles
2 – √2 miles
First let's calculate how far Daria walks. This is simply 1 mile north + 1 mile east = 2 miles. Now let's calculate how far Ashley walks. We can think of this problem using a right triangle. The two legs of the triangle are the 1 mile north and 1 mile east, and Ashley's distance is the diagonal. Using the Pythagorean Theorem we calculate the diagonal as √(12 + 12) = √2. So Daria walked 2 miles, and Ashley walked √2 miles. Therefore the difference is simply 2 – √2 miles.
Example Question #2 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem
Which of the following sets of sides cannnot belong to a right triangle?
2, 2, 2√2
5, 12, 13
3, 4 ,5
6, 7, 8
2, 2√3, 4
6, 7, 8
To answer this question without plugging all five answer choices in to the Pythagorean Theorem (which takes too long on the GRE), we can use special triangle formulas. Remember that 45-45-90 triangles have lengths of x, x, x√2. Similarly, 30-60-90 triangles have lengths x, x√3, 2x. We should also recall that 3,4,5 and 5,12,13 are special right triangles. Therefore the set of sides that doesn't fit any of these rules is 6, 7, 8.
Example Question #1 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem
Max starts at Point A and travels 6 miles north to Point B and then 4 miles east to Point C. What is the shortest distance from Point A to Point C?
5 miles
10 miles
2√13 miles
7 miles
4√2 miles
2√13 miles
This can be solved with the Pythagorean Theorem.
62 + 42 = c2
52 = c2
c = √52 = 2√13
Example Question #15 : Right Triangles
Which set of side lengths CANNOT correspond to a right triangle?
5, 12, 13
7, 24, 25
8, 15, 17
6, 8, 11
3, 4, 5
6, 8, 11
Because we are told this is a right triangle, we can use the Pythagorean Theorem, a2 + b2 = c2. You may also remember some of these as special right triangles that are good to memorize, such as 3, 4, 5.
Here, 6, 8, 11 will not be the sides to a right triangle because 62 + 82 = 102.
Example Question #91 : Geometry
Angela drives 30 miles north and then 40 miles east. How far is she from where she began?
50 miles
45 miles
35 miles
60 miles
50 miles
By drawing Angela’s route, we can connect her end point and her start point with a straight line and will then have a right triangle. The Pythagorean theorem can be used to solve for how far she is from the starting point: a2+b2=c2, 302+402=c2, c=50. It can also be noted that Angela’s route represents a multiple of the 3-4-5 Pythagorean triple.
Example Question #32 : Right Triangles
To get from his house to the hardware store, Bob must drive 3 miles to the east and then 4 miles to the north. If Bob was able to drive along a straight line directly connecting his house to the store, how far would he have to travel then?
Since east and north directions are perpendicular, the possible routes Bob can take can be represented by a right triangle with sides a and b of length 3 miles and 5 miles, respectively. The hypotenuse c represents the straight line connecting his house to the store, and its length can be found using the Pythagorean theorem: c2 = 32+ 42 = 25. Since the square root of 25 is 5, the length of the hypotenuse is 5 miles.