All High School Math Resources
Example Questions
Example Question #71 : Right Triangles
A square garden has an area of 49 ft2. To the nearest foot, what is the diagonal distance across the garden?
7
10
11
8
9
10
Since the garden is square, the two sides are equal to the square root of the area, making each side 7 feet. Then, using the Pythagorean Theorem, set up the equation 72 + 72 = the length of the diagonal squared. The length of the diagonal is the square root of 98, which is closest to 10.
Example Question #61 : Right Triangles
A man at the top of a lighthouse is watching birds through a telescope. He spots a pelican 5 miles due north of the lighthouse. The pelican flies due west for 12 miles before resting on a buoy. What is the distance, in miles, from the pelican's current resting spot to the lighthouse?
We look at the 3 points of interest: the lighthouse, where the pelican started, and where the pelican ended. We can see that if we connect these 3 points with lines, they form a right triangle. (From due north, flying exactly west creates a 90 degree angle.) The three sides of the triangle are 5 miles, 13 miles and an unknown distance. Using the Pythagorean Theorem we get:
Example Question #52 : Triangles
An airplane is 8 miles west and 15 miles south of its destination. Approximately how far is the plane from its destination, in miles?
A right triangle can be drawn between the airplane and its destination.
Destination
15 miles Airplane
8 miles
We can solve for the hypotenuse, x, of the triangle:
82 + 152 = x2
64 + 225 = x2
289 = x2
x = 17 miles
Example Question #31 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem
An 8-foot-tall tree is perpendicular to the ground and casts a 6-foot shadow. What is the distance, to the nearest foot, from the top of the tree to the end of the shadow?
In order to find the distance from the top of the tree to the end of the shadow, draw a right triangle with the height(tree) labeled as 8 and base(shadow) labeled as 6:
From this diagram, you can see that the distance being asked for is the hypotenuse. From here, you can either use the Pythagorean Theorem:
or you can notice that this is simililar to a 3-4-5 triangle. Since the lengths are just increased by a factor of 2, the hypotenuse that is normally 5 would be 10.
Example Question #62 : Right Triangles
In the figure above, is a square and is three times the length of . What is the area of ?
Assigning the length of ED the value of x, the value of AE will be 3x. That makes the entire side AD equal to 4x. Since the figure is a square, all four sides will be equal to 4x. Also, since the figure is a square, then angle A of triangle ABE is a right angle. That gives triangle ABE sides of 3x, 4x and 10. Using the Pythagorean theorem:
(3x)2 + (4x)2 = 102
9x2 + 16x2 = 100
25x2 = 100
x2 = 4
x = 2
With x = 2, each side of the square is 4x, or 8. The area of a square is length times width. In this case, that's 8 * 8, which is 64.
Example Question #41 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem
The hypotenuse is the diameter of the circle. Find the area of the circle above.
Using the Pythagorean Theorem, we can find the length of the hypotenuse:
.
Therefore the hypotenuse has length 5.
The area of the circle is
Example Question #51 : Right Triangles
Find the length of the hypotenuse.
Note: This is a right triangle.
To find the length of this hypotenuse, we need to use the Pythagorean Theorem:
, where a and b are the legs and c is the hypotenuse.
Here, c is our missing hypotenuse length, a = 4 ,and b = 14.
Plug these values in and solve for c:
Example Question #71 : Right Triangles
Side in the triangle below (not to scale) is equal to . Side is equal to . What is the length of side ?
Use the Pythagorean Theorem: , where a and b are the legs and c is the hypotenuse.
We know and , so we can plug them in to solve for c:
Example Question #72 : Right Triangles
Dan drives 5 miles north and then 8 miles west to get to school. If he walks, he can take a direct path from his house to the school, cutting down the distance. How long is the path from Dan's house to his school?
89 miles
13 miles
19 miles
4.36 miles
9.43 miles
9.43 miles
We are really looking for the hypotenuse of a triangle that has legs of 5 miles and 8 miles.
Apply the Pythagorean Theorem:
a2 + b2 = c2
25 + 64 = c2
89 = c2
c = 9.43 miles
Example Question #63 : Right Triangles
What is the hypotenuse of a right triangle with side lengths and ?
The Pythagorean Theorem states that . This question gives us the values of and , and asks us to solve for .
Take and and plug them into the equation as and :
Now we can start solving for :
The length of the hypotenuse is .