When we add decimals, we can treat it like a normal addition problem, we just need to remember out decimal: 

\(\displaystyle \frac{\begin{array}[b]{r}.35\\ +\ .13\end{array}}{\ \ \ \ }\)

       \(\displaystyle .48\)

Adding decimals is just like adding regular numbers, you just must remember to bring down your decimal point: 

\(\displaystyle \frac{\begin{array}[b]{r}.51\\ +\ .11\end{array}}{\ \ \ \ }\)

       \(\displaystyle .62\)

Adding decimals is like adding regular numbers, you just need to remember your decimal:

\(\displaystyle \frac{\begin{array}[b]{r}.24\\ +\ .05\end{array}}{\ \ \ \ }\)

       \(\displaystyle .29\)

Adding decimals is just like adding whole numbers. But, you must remember your decimal in your answer.

You start adding on the far right which in this case is the hundredths place. \(\displaystyle 7+4=11\). We have to carry a \(\displaystyle 1\) from the sum \(\displaystyle 11\) above the tenths place and place the other \(\displaystyle 1\) below the hundredths place. 

Next, add the tenths place. 

The decimal will be carried down and remain between the tenths place and the ones place. 

The final addition portion is the ones place. 

The final answer is \(\displaystyle 9.41\)

Adding decimals is just like adding whole numbers. But, you must remember your decimal in your answer.

You start adding on the far right which in this case is the hundredths place. \(\displaystyle 4+6=10\). We have to carry a \(\displaystyle 1\) from the sum \(\displaystyle 10\) above the tenths place and place the \(\displaystyle 0\) below the hundredths place. 

Next, add the tenths place. 

The decimal will be carried down and remain between the tenths place and the ones place. 

The final addition portion is the ones place. 

The final answer is \(\displaystyle 5.90\)

Adding decimals is just like adding whole numbers. But, you must remember your decimal in your answer.

You start adding on the far right which in this case is the hundredths place. 

Next, add the tenths place. \(\displaystyle 8+6=14\). We have to carry a \(\displaystyle 1\) from the sum \(\displaystyle 14\) above the ones place and place the \(\displaystyle 4\) below the tenths place. 

The decimal will be carried down and remain between the tenths place and the ones place. 

The final addition portion is the ones place. 

The final answer is \(\displaystyle 1.48\)

Adding decimals is just like adding whole numbers. But, you must remember your decimal in your answer.

You start adding on the far right which in this case is the hundredths place. 

Next, add the tenths place. 

The decimal will be carried down and remain between the tenths place and the ones place. 

The final addition portion is the ones place. \(\displaystyle 8+3=11\). The first \(\displaystyle 1\) in \(\displaystyle 11\) will be carried into the tens place. 

The final answer is \(\displaystyle 11.47\)

\(\displaystyle \frac{1}{4}+\frac{1}{2}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{1}{2}\times\frac{2}{2}=\frac{2}{4}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{1}{4}+\frac{2}{4}=\frac{3}{4}\)

\(\displaystyle \frac{1}{5}+\frac{1}{2}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{1}{5}\times\frac{2}{2}=\frac{2}{10}\)

\(\displaystyle \frac{1}{2}\times \frac{5}{5}=\frac{5}{10}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{2}{10}+\frac{5}{10}=\frac{7}{10}\)

\(\displaystyle \frac{1}{3}+\frac{2}{5}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{1}{3}\times\frac{5}5{}=\frac{5}{15}\)

\(\displaystyle \frac{2}{5}\times\frac{3}{3}=\frac{6}{15}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{5}{15}+\frac{6}{15}=\frac{11}{15}\)