The problem that you are challenged to solve is .

 is the dividend, this is what is being broken up into groups.  is our divisor which is the number of groups you are making. We need to split  in thirds to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine what  can be multiplied by to make  or get close to it without going over.  is the fact that works best ( is too large). We will place the numeral  directly above the  in the ones place to indicate that  groups of  fit into the . We will put the product of  which was  underneath the  and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the  in the tenths place down and put it next to the . We will work with the numbers as if they were  when thinking of multiplication facts, but it should be noted this is actually  when you consider the decimal placement.  so we place the  above the "house" in the tenths place of our quotient and subtract the . We are left with  remaining.

Finally, we carry down the  from the hundredths place and place it next to the  giving us  (or  for the purpose of our multiplication facts.)  so we place the  above the  in the hundredths place on top of our "house" and subtract the  leaving us with a remainder of .

Our final answer is 

The problem that you are challenged to solve is . 

 is the dividend, this is what is being broken up into groups.  is our divisor which is the number of groups you are making. We need to split  in quarters to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine what  can be multiplied by to make  or get close to it without going over.  is the fact that works best. We will place the numeral  directly above the  in the ones place to indicate that  groups of  fit into the . We will put the product of  which was  underneath the  and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the  in the tenths place down and put it next to the .  so we place the  above the "house" in the tenths place of our quotient and subtract the . We are left with  remaining.

Finally, we carry down the  from the hundredths place and place it next to the .  so we place the  above the  in the hundredths place on top of our "house" and subtract the  leaving us with a remainder of .

Our final answer is 

The problem that you are challenged to solve is .

 is the dividend, this is what is being broken up into groups.  is our divisor which is the number of groups you are making. We need to split  in half to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house". 

Next, we need to use or multiplication facts to determine what  can be multiplied by to make  or get close to it without going over.  is the fact that works best. We will place the numeral  directly above the  in the ones place to indicate that  groups of  fit into the . We will put the product of  which was  underneath the  and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the  in the tenths place down and put it next to the .  so we place the  above the "house" in the tenths place of our quotient and subtract the . We are left with  remaining so there is no remainder. 

Our final answer is , which means that half of  is 

When multiplying decimals, we can use our base ten blocks to create an area model. To do this, we want to use our hundreds, or one whole, block:

 is equal to five tenths. Remember, our one whole block is made up of ten tenths. We can shade in , or five tenths blocks, of the whole. Let's shade  of the vertical tenths blocks. Let's use blue to shade:

Next, we want to shade four of the tenths blocks to represent the . Since we shaded vertical for the first step, we need to shade horizontal for this step. Let's use yellow to shade:

Notice the green shading. This is where the yellow and the blue shading overlapped. (Remember, yellow and blue make green). The overlapping section is our answer. There are twenty green hundredths blocks; therefore, our answer is  which is equal to two tenths, :

When multiplying decimals, we can use our base ten blocks to create an area model. To do this, we want to use our hundreds, or one whole, block:

 is equal to three tenths. Remember, our one whole block is made up of ten tenths. We can shade in , or three tenths blocks, of the whole. Let's shade  of the vertical tenths blocks. Let's use blue to shade:

Next, we want to shade four of the tenths blocks to represent the . Since we shaded vertical for the first step, we need to shade horizontal for this step. Let's use yellow to shade:

Notice the green shading. This is where the yellow and the blue shading overlapped. (Remember, yellow and blue make green). The overlapping section is our answer. There are twelve green hundredths blocks, or one tenths block and two hundredths block; therefore, our answer is 

When multiplying decimals, we can use our base ten blocks to create an area model. To do this, we want to use our hundreds, or one whole, block:

 is equal to three tenths. Remember, our one whole block is made up of ten tenths. We can shade in , or three tenths blocks, of the whole. Let's shade  of the vertical tenths blocks. Let's use blue to shade:

Next, we want to shade two of the tenths blocks to represent the . Since we shaded vertical for the first step, we need to shade horizontal for this step. Let's use yellow to shade:

Notice the green shading. This is where the yellow and the blue shading overlapped. (Remember, yellow and blue make green). The overlapping section is our answer. There are six green hundredths blocks and no tenths; therefore, our answer is 

We can first think of this as , which you should know is . But, we need to remember our decimal point. In the problem we have two number after the decimals, so our answer must have two numbers after the decimal point: 

We can first think of this as , which you should know is . But, we need to remember our decimal point. In the problem we have two number after the decimals, so our answer must have two numbers after the decimal point: 

The first step when multiplying decimals is lining up the digits on the right-side regardless of place value. It is okay for a tenths place to be in line with a ones place, we want the numbers lined up on the right. 

Then, multiply the digits furthest to the right. In this case, it would be . The  is placed under the problem in the product's area and the  is carried to the top of the problem above the next set of digits. 

Now we will continue multiplying using the  until we have exhausted all digits in the first row. Next is  we must add the  we carried to the top to our product. . Place the  in the product's area and carry the . 

Multiply  and add the  on top . There are no other digits in the top number so we will place the entire  underneath in the product's area. 

You will notice that we have not placed the decimal, that will come at the end of the solution. Now we can cross out the digits we have exhausted and put a placeholder zero in the product's area to hold the place of the furthest right digit that we have finished with. 

It is time to multiply by our final digit,  in , we start back with the furthest right-hand digit, . . Place the  in the products area and carry the  above the next digit we will multiply. 

Continue multiplying,  and add the  on top, . Place the  in the prodict's area and carry your . 

Finally, we are at the last multiplication step before we combine our product.  and we add the  that we carried giving us a total of . The entire  is placed in the product's area because we are out of digits to multiply. 

Now we add our partial products together. 

The last step in a decimal multiplication problem is to place the decimal. Count how many digits are behind the decimal in your problem and we will do the same in the product. This problem has  digits behind the decimal as you can see in pink. 

We will place the decimal in the product so that there are  digits behind it. Giving us a final answer of 

The first step when multiplying decimals is lining up the digits on the right-side regardless of place value. It is okay for a tenths place to be in line with a ones place, we want the numbers lined up on the right. 

Then, multiply the digits furthest to the right. In this case, it would be . The  is placed under the problem in the product's area and the  is carried to the top of the problem above the next set of digits. 

Now we will continue multiplying using the  until we have exhausted all digits in the first row. Next is  we must add the  we carried to the top to our product. . Place the  in the product's area and carry the . 

Multiply  and add the  on top . We will place the  underneath in the product's area. 

You will notice that we have not placed the decimal, that will come at the end of the solution. Now we can cross out the digits we have exhausted and put a placeholder zero in the product's area to hold the place of the furthest right digit that we have finished with. 

It is time to multiply by our final digit,  in , we start back with the furthest right-hand digit, . . Place the  in the products area. 

Continue multiplying, . Place the  in the product's area. 

Finally, we are at the last multiplication step before we combine our product.  . The  is placed in the product's area and we are out of digits to multiply. 

Now we add our partial products together. 

The last step in a decimal multiplication problem is to place the decimal. Count how many digits are behind the decimal in your problem and we will do the same in the product. This problem has  digits behind the decimal as you can see in pink. 

We will place the decimal in the product so that there are  digits behind it. Giving us a final answer of