All AP Physics 2 Resources
Example Questions
Example Question #1 : Electric Fields
In the diagram above, where is the electric field due to the two charges zero?
to the right of
to the right of
to the left of
There is no point where the electric field is zero
to the left of
to the right of
Electric field is a vector. In between the charges is where 's field points right and 's field points left, so somewhere in between, the two vectors will add to zero. It will be closer to the weaker charge, , but since field depends on the inverse-square of the distance, it will not be linear, and we'll have to do some math.
First set the magnitudes of the two fields equal to each other. The vectors point in opposite directions, so when their magnitudes are equal, the vector sum is zero.
Many of the terms cancel, making it a bit easier. Now cross multiply and solve the quadratic:
Example Question #3 : Electric Fields
If charge has a value of , charge has a value of, and is equal to , what will be the magnitude of the force experienced by charge ?
None of these
Using coulombs law to solve
Where:
it the first charge, in coulombs.
is the second charge, in coulombs.
is the distance between them, in meters
is the constant of
Converting into
Plugging values into coulombs law
Magnitude will be the absolute value
Example Question #2 : Electric Fields
Charge has a charge of
Charge has a charge of
The distance between their centers, is .
What is the magnitude of the electric field at the center of due to
None of these
Using the electric field equation:
Where is
is the charge, in
is the distance, in .
Convert to and plug in values:
Magnitude is equivalent to absolute value:
Example Question #18 : Electrostatics
Charge has a charge of
Charge has a charge of
The distance between their centers, is .
What is the magnitude of the electric field at the center of due to ?
None of these
Using the electric field equation:
Where is
is the charge, in
is the distance, in .
Convert to and plug in values:
Magnitude is equivalent to absolute value:
Example Question #1 : Electric Fields
Charge has a charge of
Charge has a charge of
The distance between their centers, is .
What is the magnitude of the electric field at the center of due to
None of these
Use the electric field equation:
Where is
is the charge, in
is the distance, in .
Convert to and plug in values:
Magnitude is equivalent to absolute value:
Example Question #2 : Electric Fields
What is the electric field strength of a stationary 30C charge at a distance of 80cm away?
pointing towards the source charge
pointing towards the source charge
pointing away from the source charge
pointing away from the source charge
pointing away from the source charge
To solve this question, we need to recall the equation for electric field strength.
Notice that the equation above represents an inverse square relationship between the electric field and the distance between the source charge and the point of space that we are interested in.
Plug in the values given in the question stem to calculate the magnitude of the electric field.
Now that we have determined the magnitude of the electric field, we need to identify which direction it is pointing with respect to the source charge. To do this, we'll need to remember that electric fields point away from positive charges and towards negative charges. Therefore, since our source charge is positive, the electric field will be pointing away from the source charge.
Example Question #21 : Electrostatics
Charge has a charge of
Charge has a charge of
The distance between their centers, is .
What is the magnitude of the electric field at the center of due to
None of these
Use the electric field equation:
Where is
is the charge, in Coulombs
is the distance, in meters.
Convert to and plug in values:
Magnitude is equivalent to absolute value:
Example Question #22 : Electrostatics
Charge has a charge of
Charge has a charge of
The distance between their centers, is .
What is the magnitude of the electric field at the center of due to ?
None of these
Use the electric field equation:
Where is
is the charge, in Coulombs
is the distance, in meters.
Convert to and plug in values:
Magnitude is equivalent to absolute value:
Example Question #11 : Electric Fields
Charge has a charge of
Charge has a charge of
The distance between their centers, is .
What is the magnitude of the electric field at the center of due to
None of these
Use the electric field equation:
Where is
is the charge, in Coulombs
is the distance, in meters.
Convert to and plug in values:
Magnitude is equivalent to absolute value:
Example Question #24 : Electrostatics
Charge A and B are apart. If charge A has a charge of and a mass of , charge B has a charge of and a mass of , determine the electric field at A due to B.
None of these
Using electric field formula:
Converting to , to and plugging in values:
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