All AP Physics 2 Resources
Example Questions
Example Question #51 : Magnetism And Electromagnetism
A resistor is connected to a coil with turns and a cross sectional area of . A magnet is lowered as shown in the figure. The magnetic field increases from to in . Find the magnitude of the current going through the resistor.
There is a change in flux produced by the changing magnetic field which is given by
where is the cross sectional area of the coil, is the change in magnetic field, and is the angle of the field lines relative to the normal of the cross section of the coil.
In this case the magnet is perpendicular to the cross section of the coil and so
The change in magnetic field is just the final given value minus the intial value. Faraday's Law says that an emf will be generated by a change in flux,
where is the number of turns in the coil. Plugging in the change in flux gives
The change in time is just since we can start our clock at zero. The current can be found using Ohm's Law where
Example Question #1 : Solenoids
Suppose a long solenoid has a current increase from zero to in . The induced EMF magnitude is . Find the inductance.
Write the formula for inductance and substitute the givens. The length of the solenoid has no effect in this problem.
Example Question #1 : Solenoids
A transformer is plugged into a household outlet that supplies of current. The transformer steps up the potential to having a secondary coil with turns. How many turns does the primary coil have?
turns
turns
turns
turns
turns
The relationship between the number of turns for the primary coil and secondary coil in a transformer ( and respectively) to the relative potentials is
Solving for ,
Example Question #51 : Electricity And Magnetism
Which of the following is not likely to cause a magnet to lose strength?
Heating the magnet
All of these will cause a magnet to lose strength
Striking the magnet with a hammer
Dropping the magnet on the floor
Cooling the magnet
Cooling the magnet
Magnetism is caused by electrons in a material aligning and causing an aggregate magnetic field that can exert influence over other things. The magnetic strength is limited by random fluctuations in the electrons, making them no longer aligned. If the magnet were to be cooled, the electrons would have less kinetic energy, and would be less likely to have random fluctuations. This would make the strength increase.
All of the other things would make the strength of a magnet decrease. Striking it would impart kinetic energy, and would momentarily vibrate the electrons. Likewise, heating it would make the electrons vibrate more.
Example Question #2 : Other Magnetism Concepts
Suppose there is a velocity filter than can detect a particle's speed at the instant where the electric force is equal to the magnetic force. In order to increase the particle's speed, which of the following factors should be changed?
Increased charge of the particle
Increased magnetic field
Increased magnetic field and electric field
Increased charge of the particle and magnetic field
Increased electric field
Increased electric field
In this question, we're told that the velocity filter is able to detect the speed of a particle when the magnetic force and electric force are equal to each other. In order to determine when the particle's velocity will be the greatest, we'll need to keep in mind the equations for both the electric force and magnetic force:
Next, we'll need to set them equal to each other:
Then, we can isolate the velocity term:
Based on this equation, we see that if we want to increase the particle's velocity, we'll need to increase the electric field. Increasing the particle's charge will have no effect on the particle's velocity, and increasing the magnetic field will actually decrease the particle's velocity.
Example Question #2 : Other Magnetism Concepts
Which of the following scenarios would not result in a lower overall magnetic field?
Heating a permanent magnet
Cooling a permanent magnet
Adding an external magnetic field to a diamagnet
Dropping a permanent magnet on the floor
All of these scenarios lower the effective magnetic field.
Cooling a permanent magnet
The magnetic field around permanent magnets is caused by the alignment of the material's electrons, which no longer average out to a net field of zero and instead combine to form a greater field. If the electrons come out of alignment, then the field wanes or stops altogether. Additionally, the random vibrations of the electrons inhibits the effectiveness of the field. Therefore, if you were to apply energy to a magnet, it would be less effective because the electrons would have greater random motion. Heating the magnet applies thermal energy to it, and dropping it applies kinetic energy to it, which means neither of them would be the right answer. When you cool a magnet, you are removing some of the energy it has, making the electrons have less random motion.
A diamagnet is a material that, when it is exposed to a magnetic field, produces a magnetic field in the opposite direction as the external field, which leaves an overall lesser field.
Example Question #1 : Electrostatics
You have two charges on an axis. One charge of is located at the origin, and the other charge of is located at 4m. At what point along the axis is the electric field zero?
There is no point on the axis at which the electric field is 0
The equation for an electric field from a point charge is
To find the point where the electric field is 0, we set the equations for both charges equal to each other, because that's where they'll cancel each other out. Let be the point's location. The radius for the first charge would be , and the radius for the second would be .
Therefore, the only point where the electric field is zero is at , or 1.34m.
Example Question #701 : Ap Physics 2
A charge of is at , and a charge of is at . At what point on the x-axis is the electric field 0?
To find where the electric field is 0, we take the electric field for each point charge and set them equal to each other, because that's when they'll cancel each other out.
The 's can cancel out.
Therefore, the electric field is 0 at .
Example Question #1 : Point Charges
Imagine two point charges 2m away from each other in a vacuum. One of the charges has a strength of . If the force between the particles is 0.0405N, what is the strength of the second charge?
There is not enough information to determine the strength of the other charge
The equation for force experienced by two point charges is
We're trying to find , so we rearrange the equation to solve for it.
Now, we can plug in our numbers.
Therefore, the strength of the second charge is .
Example Question #1 : Electrostatics
What is the electric force between these two point charges?
The force between two point charges is shown in the formula below:
, where and are the magnitudes of the point charges, is the distance between them, and is a constant in this case equal to
Plugging in the numbers into this equation gives us
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