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AP Physics 2 : Electricity and Magnetism

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Example Questions

Example Question #733 : Ap Physics 2

Assume that the uniform electric field has a magnitude of $3.5* 10^4 \frac{N}{C}$ , which points in the positive x-direction. What is the force magnitude this field exerts on a $2 \mu C$ charge?

Possible Answers:

0.7 N

0.265N

7 * 10^4N

2.65N

0.07N

Correct answer:

0.07N

Explanation:

Use the formula to find the force that the test charge experiences.

F=E q_0

Substitute the values and determine the force.

$F=E q_0= (3.5 * 10^4 \frac{N}{C})(2* 10^{-6} C)= 0.07N$

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Example Question #1 : Electric Force In An Electric Field

A test charge of $7\mu C$ is placed in an electric field of $<.004,.004,.006>\frac{N}{C}$ .

Determine the force on the charge.

Possible Answers:

$\overrightarrow{F}=<2.8*10^{-8},4.2*10^{-8}, 4.2*10^{-8}>N$

None of these

$\overrightarrow{F}=<1.8*10^{-8},1.8*10^{-8}, 6.6*10^{-8}>N$

$\overrightarrow{F}=<2.8*10^{-8},2.8*10^{-8}, 2.8*10^{-8}>N$

$\overrightarrow{F}=<2.8*10^{-8},2.8*10^{-8}, 4.2*10^{-8}>N$

Correct answer:

$\overrightarrow{F}=<2.8*10^{-8},2.8*10^{-8}, 4.2*10^{-8}>N$

Explanation:

The definition of electric force on a charge in an electric field:

$\overrightarrow{F}=\overrightarrow{E}q$

Plug in values.

$\overrightarrow{F}=<.004,.004,.006>\frac{N}{C}7*10^{-6}C$

$\overrightarrow{F}=<2.8*10^{-8},2.8*10^{-8}, 4.2*10^{-8}>N$

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Example Question #1 : Electric Force In An Electric Field

A test charge of -8nC is placed in an electric field of $<.003,.003,.005>\frac{N}{C}$ .

Determine the force on the charge.

Possible Answers:

None of these

$\overrightarrow{F}=<-2.2*10^{-11},-1.9*10^{-11}, 2.0*10^{-11}>N$

$\overrightarrow{F}=<-1.4*10^{-11},-6.4*10^{-11}, 4.4*10^{-11}>N$

$\overrightarrow{F}=<-7.4*10^{-11},7.7*10^{-11}, 1.9*10^{-11}>N$

$\overrightarrow{F}=<-2.4*10^{-11},-2.4*10^{-11}, 4.2*10^{-11}>N$

Correct answer:

$\overrightarrow{F}=<-2.4*10^{-11},-2.4*10^{-11}, 4.2*10^{-11}>N$

Explanation:

The definition of electric force on a charge in an electric field:

$\overrightarrow{F}=\overrightarrow{E}q$

Plug in values.

$\overrightarrow{F}=<.003,.003,.005>\frac{N}{C}*-8*10^{-9}C$

$\overrightarrow{F}=<-2.4*10^{-11},-2.4*10^{11}, 4.2*10^{-11}>N$

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Example Question #2 : Electric Force In An Electric Field

A test charge of 9nC is placed in an electric field of $<.008,.008,.009>\frac{N}{C}$ .

Determine the force on the charge.

Possible Answers:

$\overrightarrow{F}=<8.2*10^{-11},8.2*10^{-11}, 3.7*10^{-11}>N$

None of these

$\overrightarrow{F}=<7.2*10^{-11},7.2*10^{-11}, 8.1*10^{-11}>N$

$\overrightarrow{F}=<6.2*10^{-11},6.2*10^{-11}, 1.7*10^{-11}>N$

$\overrightarrow{F}=<5.5*10^{-11},5.510^{-11}, 4.5*10^{-11}>N$

Correct answer:

$\overrightarrow{F}=<7.2*10^{-11},7.2*10^{-11}, 8.1*10^{-11}>N$

Explanation:

The definition of electric force on a charge in an electric field:

$\overrightarrow{F}=\overrightarrow{E}q$

Plug in values.

$\overrightarrow{F}=<.008,.008,.009>\frac{N}{C}*9*10^{-9}C$

$\overrightarrow{F}=<7.2*10^{-11},7.2*10^{-11}, 8.1*10^{-11}>N$

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Example Question #11 : Electric Force In An Electric Field

Calculate the force experienced by a particle with charge of q=3e^+ in the presence of an electric field $\vec{E}=500\hat{y}\left( \frac{N}{C} \right)$

$e=1.602*10^{-19}C$

Possible Answers:

$-2.40\times 10^{-16}\hat{z}(N)$

$2.40\times 10^{-16}\hat{y}(N)$

$2.40\times 10^{-16}\hat{x}(N)$

$-2.40\times 10^{-16}\hat{y}(N)$

$2.40\times 10^{-16}(N)$

Correct answer:

$2.40\times 10^{-16}\hat{y}(N)$

Explanation:

The force $\vec{F}$ on a given charge in the presence of an electric field $\vec{E}$ is given below as:

$\vec{F}=q\vec{E}$

It is important to note that the force will be directed along the same direction as the electric field. Therefore, for our problem, we are able to write

$\vec{F}=\left(3e^+ \right )\left(500\hat{y} \right )\left(\frac{N}{C} \right )$

$\vec F=3\left(1.602 * 10^{-19}C \right )500 \hat{y} \frac{N}{C}=2.40 \times 10^{-16}\hat{y}(N)$

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Example Question #12 : Electric Force In An Electric Field

A test charge of $6\mu C$ is placed in an electric field of $<.005,.005,.003>\frac{N}{C}$ . Determine the force on the charge.

Possible Answers:

$\overrightarrow{F}=<6*10^{-8},4*10^{-8}, 7.8*10^{-8}>N$

$\overrightarrow{F}=<9*10^{-8},9*10^{-8}, 1.8*10^{-8}>N$

None of these

$\overrightarrow{F}=<3*10^{-8},3*10^{-8}, 1.8*10^{-8}>N$

$\overrightarrow{F}=<3*10^{-8},3*10^{-8}, 4*10^{-8}>N$

Correct answer:

$\overrightarrow{F}=<3*10^{-8},3*10^{-8}, 1.8*10^{-8}>N$

Explanation:

The definition of electric force on a charge in an electric field is:

$\overrightarrow{F}=\overrightarrow{E}q$

$\overrightarrow{F}=<.005,.005,.003>\frac{N}{C}*(6*10^{-6}C)$

$\overrightarrow{F}=<3*10^{-8},3*10^{-8}, 1.8*10^{-8}>N$

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Example Question #91 : Electricity And Magnetism

A test charge of -9nC is placed in an electric field of $<-.008,-.008,.003>\frac{N}{C}$ . Determine the force on the charge.

Possible Answers:

$\overrightarrow{F}=<7.2*10^{-11},7.2*10^{-11}, -2.7*10^{-11}>N$

$\overrightarrow{F}=<7.2*10^{-11},4.5*10^{-11}, 4.5*10^{-11}>N$

None of these

$\overrightarrow{F}=<-7.2*10^{-11},-7.2*10^{-11}, 2.7*10^{-11}>N$

$\overrightarrow{F}=<6.9*10^{-11},7.2*10^{-11}, 3.8*10^{-11}>N$

Correct answer:

$\overrightarrow{F}=<-7.2*10^{-11},-7.2*10^{-11}, 2.7*10^{-11}>N$

Explanation:

The definition of electric force on a charge in an electric field is:

$\overrightarrow{F}=\overrightarrow{E}q$

$\overrightarrow{F}=<-.008,-.008,.003>\frac{N}{C}*(9*10^{-9}C)$

$\overrightarrow{F}=<-7.2*10^{-11},-7.2*10^{-11}, 2.7*10^{-11}>N$

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Example Question #41 : Electrostatics

A test charge of 35nC is placed in an electric field of $<.007,.006,.019>\frac{N}{C}$ . Determine the force on the charge.

Possible Answers:

$\overrightarrow{F}=<6.77*10^{-10},2.3*10^{-10}, 8.7*10^{-10}>N$

$\overrightarrow{F}=<3.11*10^{-10},5.25*10^{-10}, 3.11*10^{-10}>N$

$\overrightarrow{F}=<2.10*10^{-10},1.38*10^{-10}, 9.87*10^{-10}>N$

None of these

$\overrightarrow{F}=<2.45*10^{-10},2.1*10^{-10}, 6.65*10^{-10}>N$

Correct answer:

$\overrightarrow{F}=<2.45*10^{-10},2.1*10^{-10}, 6.65*10^{-10}>N$

Explanation:

The definition of electric force on a charge in an electric field is:

$\overrightarrow{F}=\overrightarrow{E}q$

$\overrightarrow{F}=<.007,.006,.019>\frac{N}{C}*(35*10^{-9}C)$

$\overrightarrow{F}=<2.45*10^{-10},2.1*10^{-10}, 6.65*10^{-10}>N$

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Example Question #14 : Electric Force In An Electric Field

Determine the force on a point charge of q=-33nC in an electric field of $<2.5,3.1>\frac{N}{C}$

Possible Answers:

$<7.77*10^{-9},1.02*10^{-7}>N$

$<8.25*10^{-9},1.02*10^{-7}>N$

$<-8.25*10^{-9},-1.02*10^{-7}>N$

None of these

$<-1.25*10^{-9},-8.02*10^{-7}>N$

Correct answer:

$<-8.25*10^{-9},-1.02*10^{-7}>N$

Explanation:

Use the following form of the electric force equation:

F_E=Eq

Plug in values:

$F_E=-33*10^{-9}*<2.5,3.1>\frac{N}{C}$

$F_E=<-8.25*10^{-9},-1.02*10^{-7}>N$

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Example Question #41 : Electrostatics

An object deep in space of mass 50mg and charge 60nC accelerates at $1.1\frac{m}{s^2}$ . Determine the electric field at this location.

Possible Answers:

$4.49*10^3\frac{N}{C}$

$1.11*10^3\frac{N}{C}$

$8.44*10^3\frac{N}{C}$

$3.86*10^2\frac{N}{C}$

$9.17*10^2\frac{N}{C}$

Correct answer:

$9.17*10^2\frac{N}{C}$

Explanation:

Use the following equation for electric force:

F_E=Eq

Plug in values:

$50*10^{-6}*1.1=60*10^{-9}*E$

$E=9.16*10^3\frac{N}{C}$

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All AP Physics 2 Resources

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AP Physics 2 : Electricity and Magnetism

Study concepts, example questions & explanations for AP Physics 2

All AP Physics 2 Resources

Example Questions

Example Question #733 : Ap Physics 2

Example Question #1 : Electric Force In An Electric Field

Example Question #1 : Electric Force In An Electric Field

Example Question #2 : Electric Force In An Electric Field

Example Question #11 : Electric Force In An Electric Field

Example Question #12 : Electric Force In An Electric Field

Example Question #91 : Electricity And Magnetism

Example Question #41 : Electrostatics

Example Question #14 : Electric Force In An Electric Field

Example Question #41 : Electrostatics

All AP Physics 2 Resources

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