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AP Physics 2 : AP Physics 2

Study concepts, example questions & explanations for AP Physics 2

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All AP Physics 2 Resources

6 Diagnostic Tests 149 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : Snell's Law

Light in a vacuum hits the surface of an unknown material with an angle of incidence of $35^\circ$ . The angle of refraction is $22.5^\circ$ . What is the index of refraction of the unknown material?

Possible Answers:

1.23

None of these

1.75

1.50

1.13

Correct answer:

1.50

Explanation:

Snell's Law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity

Use Snell's Law

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

Solve for n_2 :

$n_1\frac{sin\theta_1}{sin\theta_2}=n_2$

Plug in values:

$1*\frac{sin35^\circ}{sin22.5^\circ}=n_2$

1.50=n_2

Report an Error

Example Question #12 : Snell's Law

Light in a vacuum hits the surface of an unknown material with an angle of incidence of $47^\circ$ . The angle of refraction is $18^\circ$ . What is the index of refraction of the unknown material?

Possible Answers:

1.90

1.51

None of these

2.36

2.13

Correct answer:

2.36

Explanation:

Snell's Law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity

Use Snell's Law

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

Solve for n_2 :

$n_1\frac{sin\theta_1}{sin\theta_2}=n_2$

Plug in values:

$1*\frac{sin47^\circ}{sin18^\circ}=n_2$

2.36=n_2

Report an Error

Example Question #11 : Snell's Law

Light travels from air n=1 to crown glass n=1.52 . If the wavelength of incident light is 620nm , determine the wavelength of refracted light.

Possible Answers:

435nm

None of these

591nm

467nm

408nm

Correct answer:

408nm

Explanation:

Snell's Law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity

Use Snell's Law

$\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Solve for $\lambda_2$ :

$\lambda_2=\frac{n_1}{n_2}\lambda_1$

Plug in values:

$\lambda_2=\frac{1}{1.52}620nm$

$\lambda_2=408nm$

Report an Error

Example Question #11 : Snell's Law

Light travels from air n=1 to crown glass n=1.52 . If the angle of incidence is $45^\circ$ , determine the angle of refraction.

Possible Answers:

$45^\circ$

$17.7^\circ$

$27.7^\circ$

$21.1^\circ$

$23.5^\circ$

Correct answer:

$27.7^\circ$

Explanation:

Snell's law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Use Snell's law

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

Solve for $\theta_2$ :

$sin^{-1}(\frac{n_1 sin\theta_1^\circ}{n_2})=\theta_2$

Plug in values:

$sin^{-1}(\frac{1*sin45^\circ}{1.52})=\theta_2$

$27.7^\circ=\theta_2$

Report an Error

Example Question #42 : Optics

Light travels from air n=1 to crown glass n=1.52 . If the angle of incidence is $22^\circ$ , determine the angle of refraction.

Possible Answers:

$10.8^\circ$

$9.3^\circ$

$14.3^\circ$

$17.3^\circ$

$21.5^\circ$

Correct answer:

$14.3^\circ$

Explanation:

Snell's law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Use Snell's law

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

Solve for $\theta_2$ :

$sin^{-1}(\frac{n_1 sin\theta_1^\circ}{n_2})=\theta_2$

Plug in values:

$sin^{-1}(\frac{1*sin22^\circ}{1.52})=\theta_2$

$14.3^\circ=\theta_2$

Report an Error

Example Question #11 : Snell's Law

Light travels from air n=1 to crown glass n=1.52 . If the angle of incidence is $78^\circ$ , determine the angle of refraction.

Possible Answers:

$34.2^\circ$

$11.6^\circ$

$37.7^\circ$

$40.1^\circ$

$45.2^\circ$

Correct answer:

$40.1^\circ$

Explanation:

Snell's law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Use

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

Solve for $\theta_2$ :

$sin^{-1}(\frac{n_1 sin\theta_1^\circ}{n_2})=\theta_2$

Plug in values:

$sin^{-1}(\frac{1*sin78^\circ}{1.52})=\theta_2$

$40.1^\circ=\theta_2$

Report an Error

Example Question #11 : Snell's Law

Light travels from air n=1 to water n=1.33 . If the wavelength of incident light is 530nm , determine the wavelength of refracted light.

Possible Answers:

320nm

251nm

457nm

None of these

398nm

Correct answer:

398nm

Explanation:

Snell's law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Use Snell's law:

$\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Solve for $\lambda_2$

$\lambda_2=\frac{n_1}{n_2}\lambda_1$

Plug in values:

$\lambda_2=\frac{1}{1.33}530nm$

$\lambda_2=398nm$

Report an Error

Example Question #21 : Snell's Law

Light travels from air n=1 to water n=1.33 . If the wavelength of incident light is 470nm , determine the wavelength of refracted light.

Possible Answers:

254nm

353nm

491nm

167nm

187nm

Correct answer:

353nm

Explanation:

Snell's law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Use

$\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Solve for $\lambda_2$

$\lambda_2=\frac{n_1}{n_2}\lambda_1$

Plug in values:

$\lambda_2=\frac{1}{1.33}470nm$

$\lambda_2=353nm$

Report an Error

Example Question #22 : Snell's Law

Light travels from air n=1 to water n=1.33 . If the wavelength of incident light is 610nm , determine the wavelength of refracted light.

Possible Answers:

389nm

459nm

686nm

295nm

419nm

Correct answer:

459nm

Explanation:

Snell's law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Use Snell's law:

$\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Solve for $\lambda_2$

$\lambda_2=\frac{n_1}{n_2}\lambda_1$

Plug in values:

$\lambda_2=\frac{1}{1.33}610nm$

$\lambda_2=459nm$

Report an Error

Example Question #461 : Ap Physics 2

Light travels from a vacuum, n=1 , to a material with n=1.24 . What will be the velocity in the new medium?

Possible Answers:

$2.41*10^8\frac{m}{s}$

$2.65*10^8\frac{m}{s}$

None of these

$2.11*10^8\frac{m}{s}$

$2.04*10^8\frac{m}{s}$

Correct answer:

$2.41*10^8\frac{m}{s}$

Explanation:

Snell's law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Use Snell's law

$\frac{v_1}{v_2}=\frac{n_2}{n_1}$

Solve for v_2 :

$\frac{n_1}{n_2}v_1=v_2$

The velocity of light in a vacuum:

$v_1=c=3.0*10^8\frac{m}{s}$

Plug in values:

$\frac{1}{1.24}3.0*10^8\frac{m}{s}=v_2$

$2.41*10^8\frac{m}{s}=v_2$

Report an Error

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All AP Physics 2 Resources

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AP Physics 2 : AP Physics 2

Study concepts, example questions & explanations for AP Physics 2

All AP Physics 2 Resources

Example Questions

Example Question #11 : Snell's Law

Example Question #12 : Snell's Law

Example Question #11 : Snell's Law

Example Question #11 : Snell's Law

Example Question #42 : Optics

Example Question #11 : Snell's Law

Example Question #11 : Snell's Law

Example Question #21 : Snell's Law

Example Question #22 : Snell's Law

Example Question #461 : Ap Physics 2

All AP Physics 2 Resources

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