Call Now to Set Up Tutoring:

(888) 888-0446

Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

Create An Account

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #271 : Solving Equations

Solve the equation: 9(2-3x)=-(9-3x)

Possible Answers:

$\frac{3}{10}$

$-\frac{9}{8}$

$\frac{9}{10}$

$-\frac{3}{10}$

$\frac{3}{8}$

Correct answer:

$\frac{9}{10}$

Explanation:

Distribute the nine on the left side through both terms of the binomial.

9(2-3x) = 18-27x

Evaluate the right side of the equation.

-(9-3x) = -9+3x = 3x-9

Set the two simplified terms equal.

18-27x=3x-9

Add 27x on both sides.

18-27x+27x=3x-9+27x

18=30x-9

Add 9 on both sides.

18+9=30x-9+9

27=30x

Divide by thirty on both sides.

$\frac{27}{30}=\frac{30x}{30}$

Reduce both fractions.

The answer is: $\frac{9}{10}$

Report an Error

Example Question #272 : Solving Equations

Set up the equation: -8x+18=46

Possible Answers:

$-\frac{7}{9}$

$-\frac{1}{8}$

$-\frac{29}{4}$

$-\frac{7}{2}$

Correct answer:

$-\frac{7}{2}$

Explanation:

Subtract 18 from both sides.

-8x+18-18=46-18

Simplify the equation.

-8x = 28

Divide by negative eight on both sides.

$\frac{-8x }{-8}= \frac{28}{-8}$

Reduce both fractions.

The answer is: $-\frac{7}{2}$

Report an Error

Example Question #273 : Solving Equations

Solve the equation: 6-9x=-2(4-7x)

Possible Answers:

$-\frac{2}{23}$

$\frac{12}{41}$

$\frac{14}{23}$

$\frac{7}{46}$

$\frac{14}{9}$

Correct answer:

$\frac{14}{23}$

Explanation:

Distribute the negative two on the right side.

The equation becomes:

6-9x= -8+14x

Add on both sides.

6-9x+9x= -8+14x+9x

6=23x-8

Add 8 on both sides.

6+8=23x-8+8

14= 23x

Divide by 23 on both sides.

$\frac{14}{23}=\frac{ 23x}{23}$

The answer is: $\frac{14}{23}$

Report an Error

Example Question #274 : Solving Equations

Solve the equation: -8(3x+5)=-14+2x

Possible Answers:

$-\frac{27}{13}$

$\frac{27}{13}$

$\frac{1}{7}$

$\frac{13}{11}$

Correct answer:

Explanation:

Distribute the negative eight through the binomial.

-8(3x)+(-8)(5)=-14+2x

Simplify the left side.

-24x-40 = -14+2x

Add 24x on both sides.

-24x-40+24x = -14+2x+24x

Simplify both sides.

-40 =-14+26x

Add 14 on both sides.

-40 +14=-14+26x+14

Simplify both sides.

-26=26x

Divide by 26 on both sides

$\frac{-26}{26}=\frac{26x}{26}$

The answer is:

Report an Error

Example Question #751 : Basic Single Variable Algebra

Solve the equation: $-8(2x-3) = \frac{1}{5}$

Possible Answers:

$\frac{29}{16}$

$\frac{119}{80}$

$-\frac{121}{80}$

$\frac{121}{80}$

$-\frac{29}{16}$

Correct answer:

$\frac{119}{80}$

Explanation:

Multiply the negative eight through both terms of the binomial.

$-8(2x)-(-8)(3) = \frac{1}{5}$

Simplify the equation.

$-16x+24 = \frac{1}{5}$

Multiply by five on both sides to eliminate the fraction on the right side.

$5(-16x+24 )= \frac{1}{5} \cdot 5$

-80x+120 = 1

Subtract 120 on both sides.

-80x=-119

Divide by negative 80 on both sides. The double negatives will negate.

The answer is: $\frac{119}{80}$

Report an Error

Example Question #276 : Solving Equations

Solve the equation: 8x-34 = -13

Possible Answers:

$-\frac{47}{8}$

$-\frac{21}{8}$

$\textup{The answer is not given.}$

$\frac{47}{8}$

$\frac{21}{8}$

Correct answer:

$\frac{21}{8}$

Explanation:

Add 34 on both sides of the equation.

8x-34 +34= -13+34

The equation becomes:

8x=21

Divide by eight on both sides.

$\frac{8x}{8}=\frac{21}{8}$

The answer is: $\frac{21}{8}$

Report an Error

Example Question #752 : Basic Single Variable Algebra

Solve the equation: 5x-7 = 35-4x

Possible Answers:

$\frac{14}{3}$

$\frac{28}{3}$

$\frac{52}{9}$

Correct answer:

$\frac{14}{3}$

Explanation:

Add on both sides.

5x-7+4x = 35-4x+4x

Combine like terms. The equation will become:

9x-7 = 35

Add seven on both sides.

9x-7+7 = 35+7

9x=42

Divide by nine on both sides.

$\frac{9x}{9}=\frac{42}{9}$

Reduce the fraction.

The answer is: $\frac{14}{3}$

Report an Error

Example Question #751 : Basic Single Variable Algebra

Solve the equation: $\frac{1}{20}x+\frac{2}{15}= \frac{1}{30}$

Possible Answers:

$\frac{5}{2}$

Correct answer:

Explanation:

In order to eliminate the complications of converting fractions, we can multiply both sides by the least common denominator.

Write out the multiples of the denominators.

15-[15,30,45,60]

20-[20,40,60]

30-[30,60]

Multiply both sides of the equation by 60.

$60(\frac{1}{20}x+\frac{2}{15})= 60(\frac{1}{30})$

Simplify both sides.

3x+8 = 2

Subtract eight from both sides.

3x+8 -8= 2-8

3x=-6

Divide by three on both sides.

$\frac{3x}{3}=\frac{-6}{3}$

Simplify both sides.

The answer is:

Report an Error

Example Question #279 : Solving Equations

Solve the equation: -8x = -8(-x+3)

Possible Answers:

$\textup{No solution.}$

$-\frac{3}{2}$

$-\frac{3}{16}$

$\frac{3}{2}$

Correct answer:

$\frac{3}{2}$

Explanation:

Use distribution to simplify the right side.

-8x = -8(-x)+(-8)(3)

Simplify the parentheses.

-8x =8x-24

Subtract on both sides.

-8x -8x=8x-24-8x

-16x = -24

Divide by negative 16 on both sides.

$\frac{-16x }{-16}= \frac{-24}{-16}$

Reduce both fractions.

The answer is: $\frac{3}{2}$

Report an Error

Example Question #280 : Solving Equations

Solve the equation: $\frac{x}{5}+\frac{5}{3} = 5$

Possible Answers:

$\frac{25}{3}$

$\frac{75}{4}$

$\frac{50}{3}$

$\frac{1}{5}$

$\frac{35}{3}$

Correct answer:

$\frac{50}{3}$

Explanation:

In order to eliminate the fractions, we can multiply both sides by the least common denominator.

The least common denominator can be determined by multiplying the two denominators together.

$5\times 3 = 15$

$(15)(\frac{x}{5}+\frac{5}{3}) = 5(15)$

The equation becomes:

3x+25 = 75

Subtract both sides by 25.

3x+25 -25= 75-25

3x=50

Divide by three on both sides.

$\frac{3x}{3}=\frac{50}{3}$

The answer is: $\frac{50}{3}$

Report an Error

View Algebra 2 Tutors

Laura
Certified Tutor

New York University, Bachelor in Arts, French.

View Algebra 2 Tutors

Justin
Certified Tutor

Vanderbilt University, Bachelor, Computer Science, Mathematics, & Philosophy.

View Algebra 2 Tutors

Saarim
Certified Tutor

St Edwards University, Bachelor of Science, Mathematics.

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

ACT Tutors in Houston, GRE Tutors in Philadelphia, SSAT Tutors in Houston, ACT Tutors in Phoenix, Statistics Tutors in Denver, Statistics Tutors in Houston, GMAT Tutors in New York City, GMAT Tutors in Denver, French Tutors in Houston, English Tutors in San Francisco-Bay Area

Popular Courses & Classes

GRE Courses & Classes in Boston, SAT Courses & Classes in Seattle, SSAT Courses & Classes in Houston, LSAT Courses & Classes in Atlanta, SAT Courses & Classes in Atlanta, SSAT Courses & Classes in Dallas Fort Worth, GRE Courses & Classes in Philadelphia, MCAT Courses & Classes in Miami, MCAT Courses & Classes in San Francisco-Bay Area, SAT Courses & Classes in Phoenix

Popular Test Prep

SAT Test Prep in Los Angeles, GMAT Test Prep in New York City, LSAT Test Prep in San Francisco-Bay Area, ACT Test Prep in Philadelphia, SAT Test Prep in New York City, MCAT Test Prep in New York City, GRE Test Prep in Boston, SSAT Test Prep in San Francisco-Bay Area, GRE Test Prep in New York City, SSAT Test Prep in Boston

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #271 : Solving Equations

Example Question #272 : Solving Equations

Example Question #273 : Solving Equations

Example Question #274 : Solving Equations

Example Question #751 : Basic Single Variable Algebra

Example Question #276 : Solving Equations

Example Question #752 : Basic Single Variable Algebra

Example Question #751 : Basic Single Variable Algebra

Example Question #279 : Solving Equations

Example Question #280 : Solving Equations

All Algebra II Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: