Call Now to Set Up Tutoring:

(888) 888-0446

Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

Create An Account

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #412 : Equations

Solve the equation: 9-4x= 11-9x

Possible Answers:

$\frac{20}{13}$

$\frac{2}{13}$

$-\frac{2}{13}$

$\frac{2}{5}$

Correct answer:

$\frac{2}{5}$

Explanation:

Add on both sides.

9-4x+9x= 11-9x+9x

Combine like-terms on both sides.

9+5x =11

Subtract nine from both sides.

9+5x -9=11-9

5x=2

Divide by five on both sides.

$\frac{5x}{5}=\frac{2}{5}$

The answer is: $\frac{2}{5}$

Report an Error

Example Question #413 : Equations

Solve the equation: 8x-7 = 2x+7

Possible Answers:

$\frac{7}{3}$

$\frac{3}{8}$

$-\frac{7}{3}$

$\frac{14}3$

Correct answer:

$\frac{7}{3}$

Explanation:

Subtract from both sides.

8x-7-2x = 2x+7-2x

The equation becomes:

6x-7=7

Add seven on both sides.

6x-7+7=7+7

6x=14

Divide by six on both sides and reduce the fraction.

$\frac{6x}{6}=\frac{14}{6}$

The answer is: $\frac{7}{3}$

Report an Error

Example Question #414 : Equations

Solve the equation: 9x-12 = -4x+8

Possible Answers:

$\frac{4}{13}$

$-\frac{4}{13}$

$\frac{5}{13}$

$\frac{18}{13}$

$\frac{20}{13}$

Correct answer:

$\frac{20}{13}$

Explanation:

Add 12 on both sides.

9x-12 +12= -4x+8+12

9x= -4x+20

Add on both sides of the equation.

9x+4x= -4x+20+4x

Simplify both sides.

13x = 20

Divide by 13 on both sides.

$\frac{13x }{13}= \frac{20}{13}$

The answer is: $\frac{20}{13}$

Report an Error

Example Question #2601 : Algebra Ii

Solve the equation: 8x-9 = 31-8x

Possible Answers:

$-\frac{5}{2}$

$\textup{No solution.}$

$\frac{5}{2}$

$\frac{11}{8}$

$-\frac{11}{8}$

Correct answer:

$\frac{5}{2}$

Explanation:

Add on both sides.

8x-9 +8x= 31-8x+8x

The equation becomes:

16x-9 = 31

Add nine on both sides.

16x-9+9 = 31+9

The equation becomes:

16x = 40

Divide by 16 on both sides.

$\frac{16x }{16}= \frac{40}{16}$

Reduce the fractions.

$\frac{40}{16} = \frac{8\times 5}{8\times 2}$

The answer is: $\frac{5}{2}$

Report an Error

Example Question #761 : Basic Single Variable Algebra

Solve the equation: $\frac{1}{3}x-\frac{1}{4}=\frac{3}{7}$

Possible Answers:

$\frac{47}{28}$

$-\frac{47}{28}$

$\frac{31}{28}$

$\frac{57}{28}$

$-\frac{15}{28}$

Correct answer:

$\frac{57}{28}$

Explanation:

Determine the least common denominator of the fractions by multiplying all the denominators together.

3(4)(7)= 84

We can multiply both sides by 84 in order to eliminate the fractions.

$84(\frac{1}{3}x-\frac{1}{4})=\frac{3}{7}\cdot 84$

Simplify both sides.

$28x -21 = 3\cdot 12$

28x -21 = 36

Add 21 on both sides.

28x = 57

Divide by 28 on both sides.

$\frac{28x }{28}= \frac{57}{28}$

The answer is: $\frac{57}{28}$

Report an Error

Example Question #281 : Solving Equations

$f(x)=\frac{1}{3}x+4$

and

g(x)=3x+4 ,

what is the value of g(f(6)) ?

Possible Answers:

Correct answer:

Explanation:

In order to answer this question, you must first find f(6) .

Plugging in 6 for x in the f(x) equation,

$\\f(x)=\frac{1}{3}x+4 \\ \\f(6)=\frac{1}{3}(6)+4 \\ \\f(6)=\frac{2\cdot 3}{3}+4 \\ \\f(6)=2+4 \\ \\f(6)=6$

you get 6 as your answer, so then you plug 6 in as the x in the g(x) equation.

$\\g(x)=3x+4 \\g(6)=3(6)+4 \\g(6)=18+4 \\g(6)=22$ .

Thus g(f(6))=22 .

Report an Error

Example Question #412 : Equations

Solve 4x-2x=4 for .

Possible Answers:

x=2

x=0

x= -2

x=3

x=1

Correct answer:

x=2

Explanation:

4x-2x=2x , then setting 2x=4 and dividing the entire equation by , you get x=2 .

Report an Error

Example Question #413 : Equations

4x+2x=?

Possible Answers:

$6x^{2}$

Correct answer:

Explanation:

When adding 4x+2x , you only add the coefficients and keep the variable, so 4+2=6 and then keep the , so it equals .

Report an Error

Example Question #281 : Solving Equations

Solve the equation: -8x = 9x+4

Possible Answers:

$\frac{4}{17}$

$\frac{13}{17}$

$-\frac{4}{17}$

Correct answer:

$-\frac{4}{17}$

Explanation:

Isolate the x-variable by subtracting on both sides.

-8x-9x = 9x+4-9x

Simplify both sides.

-17x = 4

Divide by negative 17 on both sides.

$\frac{-17x}{-17} =\frac{4 }{-17}$

The answer is: $-\frac{4}{17}$

Report an Error

Example Question #282 : Solving Equations

Solve the equation: 2x-6 = 9x-7

Possible Answers:

$-\frac{13}{7}$

$\frac{1}{7}$

$\frac{13}{7}$

$\frac{13}{11}$

$\frac{11}{3}$

Correct answer:

$\frac{1}{7}$

Explanation:

Subtract from both sides of the equation.

2x-6 -2x= 9x-7-2x

-6 =7x-7

Add seven on both sides.

-6 +7=7x-7+7

1=7x

Divide by 7 on both sides.

$\frac{1}{7}=\frac{7x}{7}$

The answer is: $\frac{1}{7}$

Report an Error

View Algebra 2 Tutors

Bagher
Certified Tutor

San Jose State University, Master's/Graduate, Physics.

View Algebra 2 Tutors

Delilah
Certified Tutor

Emory University, Bachelor in Arts, Political Science and Government.

View Algebra 2 Tutors

Laura
Certified Tutor

New York University, Bachelor in Arts, French.

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Biology Tutors in Houston, Algebra Tutors in Denver, Reading Tutors in San Diego, SSAT Tutors in Chicago, English Tutors in Atlanta, MCAT Tutors in Denver, Calculus Tutors in Atlanta, ISEE Tutors in Seattle, Math Tutors in New York City, SSAT Tutors in Boston

Popular Courses & Classes

Spanish Courses & Classes in Dallas Fort Worth, LSAT Courses & Classes in Boston, SSAT Courses & Classes in Denver, ISEE Courses & Classes in Miami, ACT Courses & Classes in Chicago, GRE Courses & Classes in Los Angeles, Spanish Courses & Classes in Philadelphia, ACT Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in Boston, GRE Courses & Classes in Philadelphia

Popular Test Prep

ACT Test Prep in Los Angeles, MCAT Test Prep in Phoenix, SSAT Test Prep in San Francisco-Bay Area, ACT Test Prep in Dallas Fort Worth, MCAT Test Prep in Denver, MCAT Test Prep in San Francisco-Bay Area, MCAT Test Prep in Washington DC, LSAT Test Prep in Philadelphia, ISEE Test Prep in Denver, SSAT Test Prep in Denver

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #412 : Equations

Example Question #413 : Equations

Example Question #414 : Equations

Example Question #2601 : Algebra Ii

Example Question #761 : Basic Single Variable Algebra

Example Question #281 : Solving Equations

Example Question #412 : Equations

Example Question #413 : Equations

Example Question #281 : Solving Equations

Example Question #282 : Solving Equations

All Algebra II Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: