We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

Create An Account

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #231 : Solving Equations

Solve for .

4(x-15)=2(2x-6)

Possible Answers:

No Solutions

Correct answer:

No Solutions

Explanation:

To solve for , we need to isolate the variable by having the variable on one side and numbers on the other side.

4(x-15)=2(2x-6) Distribute the 4,2 to each term in the parentheses.

4x-60=4x-24 Because there is on each side of the equation, they would essentially cancel out leaving us with 0=36 which is not valid.

Answer is no solutions.

Report an Error

Example Question #232 : Solving Equations

Solve: 9x-17=81-2x

Possible Answers:

$-\frac{98}{11}$

$\frac{108}{11}$

$\frac{108}{7}$

$\frac{98}{11}$

Correct answer:

$\frac{98}{11}$

Explanation:

Isolate the x-variables on one side of the equation and the integers on the other.

Add on both sides of the equation.

9x-17+2x=81-2x+2x

11x-17=81

Add 17 on both sides of the equation.

11x-17+17=81+17

Simplify both sides.

11x=98

Divide by 11 on both sides.

$x=\frac{98}{11}$

The answer is: $\frac{98}{11}$

Report an Error

Example Question #233 : Solving Equations

Solve the equation: 4(x-9) = 30x

Possible Answers:

$\frac{18}{17}$

$\frac{3}{2}$

$\frac{33}{2}$

$-\frac{18}{13}$

$\frac{18}{13}$

Correct answer:

$-\frac{18}{13}$

Explanation:

Use distribution to simplify the left side.

4(x)-4(9) = 30x

4x-36=30x

Subtract on both sides.

4x-36-(4x)=30x-(4x)

Simplify.

-36 = 26x

Divide by 26 on both sides.

$\frac{-36}{26} = \frac{26x}{26}$

Reduce both fractions.

The answer is: $-\frac{18}{13}$

Report an Error

Example Question #234 : Solving Equations

Solve the equation: $\frac{10}{11}x - \frac{1}{33} = \frac{7}{66}$

Possible Answers:

$\frac{13}{66}$

$\frac{10}{3}$

$\frac{3}{40}$

$\frac{3}{20}$

Correct answer:

$\frac{3}{20}$

Explanation:

In order to determine the value of x, we will need to convert the fractions to a least common denominator.

The LCD is 66 because this value is the smallest number that every individual denominator can be divided into.

Convert the fractions.

$\frac{10(6)}{11(6)}x - \frac{1(2)}{33(2)} = \frac{7}{66}$

$\frac{60}{66}x-\frac{2}{66}= \frac{7}{66}$

Since all the denominators are similar, we can simply set the numerators equal. Multiplying both sides by 66 will eliminate the denominators.

60x-2=7

Add two on both sides.

60x=9

Divide by 60 on both sides and reduce the fraction.

$\frac{60x}{60}=\frac{9}{60}= \frac{3}{20}$

The answer is: $\frac{3}{20}$

Report an Error

Example Question #235 : Solving Equations

Solve the equation: 9-18x =43+2x

Possible Answers:

$-\frac{17}{10}$

$-\frac{16}{17}$

$-\frac{27}{10}$

$-\frac{17}{8}$

Correct answer:

$-\frac{17}{10}$

Explanation:

Group the x-variables and integers on a separate side of the equation.

Add 18x on both sides.

9-18x +(18x)=43+2x+(18x)

Simplify the equation.

9=20x+43

Subtract on both sides.

9-43=20x+43-43

Simplify both sides.

-34=20x

Divide by twenty on both sides.

$\frac{-34}{20}=\frac{20x}{20}$

Reduce both fractions.

The answer is: $-\frac{17}{10}$

Report an Error

Example Question #236 : Solving Equations

Solve the following equation: $\frac{1}{x}+2 =-8$

Possible Answers:

$-\frac{1}{60}$

$-\frac{1}{6}$

$-\frac{1}{10}$

$-\frac{1}{16}$

$\frac{3}{5}$

Correct answer:

$-\frac{1}{10}$

Explanation:

Subtract two from both sides.

$\frac{1}{x}+2-2 =-8-2$

$\frac{1}{x}=-10$

Multiply by on both sides.

$\frac{1}{x} \cdot x=-10 \cdot x$

1=-10x

Divide by negative ten on both sides.

$\frac{1}{-10}=\frac{-10x}{-10}$

Simplify both fractions.

The answer is: $-\frac{1}{10}$

Report an Error

Example Question #237 : Solving Equations

Solve the equation: -7x+38 = -5x-50

Possible Answers:

$-\frac{22}{3}$

$\frac{22}{3}$

Correct answer:

Explanation:

Isolate the x-variables on one side and the integers on another.

Add on both sides of the equation.

-7x+38 +(7x)= -5x-50+(7x)

Simplify both sides.

38= 2x-50

Add 50 on both sides.

38+50= 2x-50+50

88=2x

Divide by two on both sides.

$\frac{88}{2}=\frac{2x}{2}$

The answer is:

Report an Error

Example Question #238 : Solving Equations

Solve the equation: 9x-6=3x+4

Possible Answers:

$-\frac{3}{5}$

$\frac{1}{3}$

$\frac{5}{2}$

$\frac{5}{3}$

$\textup{The answer is not given.}$

Correct answer:

$\frac{5}{3}$

Explanation:

Subtract from both sides.

9x-6-(3x)=3x+4-(3x)

6x-6=4

Add six on both sides.

6x-6+6=4+6

6x=10

Divide by six on both sides.

$\frac{6x}{6}=\frac{10}{6}$

Reduce the fractions.

The answer is: $\frac{5}{3}$

Report an Error

Example Question #239 : Solving Equations

Solve the equation: -4x-18 = 46-8x

Possible Answers:

$-\frac{16}{7}$

$-\frac{16}{3}$

Correct answer:

Explanation:

Add on each side.

-4x-18 +8x= 46-8x+8x

Simplify both sides.

4x-18= 46

Add 18 on both sides.

4x-18+18= 46+18

4x=64

Divide four on both sides.

$\frac{4x}{4}=\frac{64}{4}$

The answer is:

Report an Error

Example Question #240 : Solving Equations

Solve the equation: 6x-18 = 3x-2

Possible Answers:

$\frac{16}{3}$

$\textup{The answer is not given.}$

$\frac{20}{3}$

$-\frac{16}{3}$

Correct answer:

$\frac{16}{3}$

Explanation:

Subtract on both sides.

6x-18 -3x= 3x-2-3x

3x-18 = -2

Add 18 on both sides.

3x-18 +18= -2+18

3x=16

Divide by three on both sides.

$\frac{3x}{3}=\frac{16}{3}$

The answer is: $\frac{16}{3}$

Report an Error

View Algebra 2 Tutors

Mariam
Certified Tutor

Yarmouk University, Bachelor of Science, Mathematics. Touro College, Master of Science, Teacher Education, Multiple Levels.

View Algebra 2 Tutors

Jyotiparna
Certified Tutor

Vellore Institute of Technology, Bachelor of Technology, Chemical Engineering. University of Toronto, Master of Engineering, ...

View Algebra 2 Tutors

Andrew
Certified Tutor

University of Wisconsin-Stevens Point, Bachelor of Science, Mathematics. University of Wisconsin-Oshkosh, Master of Science, ...

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

SSAT Tutors in Miami, Chemistry Tutors in Washington DC, Computer Science Tutors in New York City, SAT Tutors in Philadelphia, Algebra Tutors in Phoenix, Calculus Tutors in San Francisco-Bay Area, Statistics Tutors in Washington DC, Computer Science Tutors in Houston, LSAT Tutors in Boston, English Tutors in Chicago

Popular Courses & Classes

SAT Courses & Classes in Los Angeles, GRE Courses & Classes in Denver, ACT Courses & Classes in Atlanta, MCAT Courses & Classes in Phoenix, Spanish Courses & Classes in Seattle, MCAT Courses & Classes in San Diego, ACT Courses & Classes in San Francisco-Bay Area, ISEE Courses & Classes in Philadelphia, GMAT Courses & Classes in Los Angeles, ISEE Courses & Classes in Phoenix

Popular Test Prep

SAT Test Prep in Houston, ACT Test Prep in Atlanta, ACT Test Prep in San Diego, MCAT Test Prep in New York City, SAT Test Prep in Miami, SSAT Test Prep in New York City, SSAT Test Prep in Seattle, LSAT Test Prep in Washington DC, SAT Test Prep in Philadelphia, MCAT Test Prep in Houston

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #231 : Solving Equations

Example Question #232 : Solving Equations

Example Question #233 : Solving Equations

Example Question #234 : Solving Equations

Example Question #235 : Solving Equations

Example Question #236 : Solving Equations

Example Question #237 : Solving Equations

Example Question #238 : Solving Equations

Example Question #239 : Solving Equations

Example Question #240 : Solving Equations

All Algebra II Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: