All Algebra II Resources
Example Questions
Example Question #1 : Circle Functions
Find the negative coterminal of 160.
Coterminal angles are angles that are the same but written differently. Circles have 360 degrees, so an angle that goes above this threshold has completed one revolution. For example, a 450 degree angle would be in the same position as a 90 degree angle.
To find a positive coterminal angle, add 360 degrees to the initial value.
To find the negative coterminal angle, simply subtract 360. The only exception to this rule would be if the initial value were greater than 360. In this case, subtract 360 until the value is negative, making it a negative coterminal. Therefore,
160-360 = -200
Do this a second time and we get -560. These are examples of negative coterminal angles.
Example Question #7 : Circle Functions
Which of the following equations represent a circle?
The circle is represented by the formula:
Although some of the equations might not in this form, we can see by the variables that the equation is most similar to the form.
Multiply two on both sides of the equation and we will have:
This is an equation of a circle. The other equations represent other conic shapes.
The answer is:
Example Question #8 : Circle Functions
Determine the equation of a circle that has radius and is centered at
None of these
Definition of the formula of a circle:
Where:
is the coordinate of the center of the circle
is the coordinate of the center of the circle
is the radius of the circle
Plugging in values:
Example Question #61 : Quadratic Functions
Determine the center and radius, respectively, given the equation:
In order to solve for the radius, we will need to complete the square twice.
Group the x and y-variables in parentheses. Starting from the original equation:
Add two on both sides.
Divide by the second term coefficient of each binomial by 2, and add the squared quantity on both sides of the equation.
The equation becomes:
Factorize both polynomials in parentheses and simplify the right side.
The center is:
The radius is:
The answer is:
Example Question #1 : Graphing Circle Functions
Determine the graph of the equation
Hyperbola, centered at
Circle, centered at with radius
Circle, centered at with radius
Ellipse, centered at
Circle, centered at with radius
The equation of a circle in standard for is:
Where the center and the radius of the cirlce is .
Dividing by 4 on both sides of the equation yields
or
an equation whose graph is a circle, centered at (2,3) with radius = .5
Example Question #2 : Graphing Circle Functions
Give the radius and the center of the circle for the equation below.
Look at the formula for the equation of a circle below.
Here is the center and is the radius. Notice that the subtraction in the center is part of the formula. Thus, looking at our equation it is clear that the center is and the radius squared is . When we square root this value we get that the radius must be .
Example Question #1 : Graphing Circle Functions
Determine the equation of a circle whose center lies at the point and has a radius of .
The equation for a circle with center and radius is :
Our circle is centered at with radius , so the equation for this circle is :
Example Question #1 : Graphing Circle Functions
What is the radius of the circle?
The parent equation of a circle is represented by . The radius of the circle is equal to . The radius of the cirle is .
Example Question #5 : Graphing Circle Functions
What is the center of the circle expressed by the funciton ?
The equation can be rewritten so that it looks like the parent equation for a circle . After completeing the square, the equation changes from to . From there it can be expressed as . Therefore the center of the circle is at .
Example Question #1 : Graphing Circle Functions
The graph of the equation
is a circle with what as the length of its radius?
Rewrite the equation of the circle in standard form
as follows:
Since and , we complete the squares by adding:
The standard form of the equation sets
,
so the radius of the circle is