SSAT Elementary Level Math : SSAT Elementary Level Quantitative (Math)

Study concepts, example questions & explanations for SSAT Elementary Level Math

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Example Questions

Example Question #962 : Common Core Math: Grade 3

\(\displaystyle \frac{\begin{array}[b]{r}20\\ \times\ 4\end{array}}{ \ \ \ \space}\)

Possible Answers:

\(\displaystyle 50\)

\(\displaystyle 90\)

\(\displaystyle 80\)

\(\displaystyle 60\)

\(\displaystyle 70\)

Correct answer:

\(\displaystyle 80\)

Explanation:

To solve this problem, we multiply \(\displaystyle 4\) by the ones position and the tens position. 

\(\displaystyle 4\times0=0\)

\(\displaystyle 4\times2=8\)

\(\displaystyle \frac{\begin{array}[b]{r}20\\ \times\ 4\end{array}}{ \ \ \space80}\)

Example Question #472 : How To Multiply

\(\displaystyle \frac{\begin{array}[b]{r}30\\ \times\ 5\end{array}}{ \ \ \ \space}\)

Possible Answers:

\(\displaystyle 140\)

\(\displaystyle 160\)

\(\displaystyle 150\)

\(\displaystyle 130\)

\(\displaystyle 170\)

Correct answer:

\(\displaystyle 150\)

Explanation:

To solve this problem, we multiply \(\displaystyle 5\) by the ones position and the tens position. 

\(\displaystyle 5\times0=0\)

\(\displaystyle 5\times3=15\)

\(\displaystyle \frac{\begin{array}[b]{r}30\\ \times\ 5\end{array}}{ \ \space150}\)

Example Question #473 : How To Multiply

\(\displaystyle \frac{\begin{array}[b]{r}40\\ \times\ 6\end{array}}{ \ \ \ \space}\)

Possible Answers:

\(\displaystyle 270\)

\(\displaystyle 240\)

\(\displaystyle 260\)

\(\displaystyle 280\)

\(\displaystyle 250\)

Correct answer:

\(\displaystyle 240\)

Explanation:

To solve this problem, we multiply \(\displaystyle 6\) by the ones position and the tens position. 

\(\displaystyle 6\times0=0\)

\(\displaystyle 6\times4=24\)

\(\displaystyle \frac{\begin{array}[b]{r}40\\ \times\ 6\end{array}}{ \ \space240}\)

Example Question #474 : How To Multiply

\(\displaystyle \frac{\begin{array}[b]{r}60\\ \times\ 7\end{array}}{ \ \ \ \space}\)

Possible Answers:

\(\displaystyle 410\)

\(\displaystyle 420\)

\(\displaystyle 440\)

\(\displaystyle 400\)

\(\displaystyle 430\)

Correct answer:

\(\displaystyle 420\)

Explanation:

To solve this problem, we multiply \(\displaystyle 7\) by the ones position and the tens position. 

\(\displaystyle 7\times0=0\)

\(\displaystyle 7\times6=42\)

\(\displaystyle \frac{\begin{array}[b]{r}60\\ \times\ 7\end{array}}{ \ \space420}\)

Example Question #71 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

\(\displaystyle \frac{\begin{array}[b]{r}90\\ \times\ 1\end{array}}{ \ \ \ \space}\)

Possible Answers:

\(\displaystyle 70\)

\(\displaystyle 80\)

\(\displaystyle 50\)

\(\displaystyle 90\)

\(\displaystyle 60\)

Correct answer:

\(\displaystyle 90\)

Explanation:

To solve this problem, we multiply \(\displaystyle 1\) by the ones position and the tens position. 

\(\displaystyle 1\times0=0\)

\(\displaystyle 1\times9=9\)

\(\displaystyle \frac{\begin{array}[b]{r}90\\ \times\ 1\end{array}}{ \ \ \space90}\)

Example Question #71 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

\(\displaystyle \frac{\begin{array}[b]{r}10\\ \times\ 2\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 30\)

\(\displaystyle 50\)

\(\displaystyle 20\)

\(\displaystyle 60\)

\(\displaystyle 40\)

Correct answer:

\(\displaystyle 20\)

Explanation:

To solve this problem, we multiply \(\displaystyle 2\) by the ones position and the tens position. 

\(\displaystyle 2\times0=0\)

\(\displaystyle 2\times1=2\)

\(\displaystyle \frac{\begin{array}[b]{r}10\\ \times\ 2\end{array}}{ \ \ \space20}\)

Example Question #967 : Common Core Math: Grade 3

\(\displaystyle \frac{\begin{array}[b]{r}20\\ \times\ 3\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 60\)

\(\displaystyle 70\)

\(\displaystyle 50\)

\(\displaystyle 90\)

\(\displaystyle 80\)

Correct answer:

\(\displaystyle 60\)

Explanation:

To solve this problem, we multiply \(\displaystyle 3\) by the ones position and the tens position. 

\(\displaystyle 3\times0=0\)

\(\displaystyle 3\times2=6\)

\(\displaystyle \frac{\begin{array}[b]{r}20\\ \times\ 3\end{array}}{ \ \ \space60}\)

Example Question #111 : Algebraic Concepts

\(\displaystyle \frac{\begin{array}[b]{r}30\\ \times\ 4\end{array}}{ \ \ \ \space}\)

Possible Answers:

\(\displaystyle 140\)

\(\displaystyle 120\)

\(\displaystyle 100\)

\(\displaystyle 110\)

\(\displaystyle 130\)

Correct answer:

\(\displaystyle 120\)

Explanation:

To solve this problem, we multiply \(\displaystyle 4\) by the ones position and the tens position. 

\(\displaystyle 4\times0=0\)

\(\displaystyle 4\times3=12\)

\(\displaystyle \frac{\begin{array}[b]{r}30\\ \times\ 4\end{array}}{ \ \space120}\)

Example Question #969 : Common Core Math: Grade 3

\(\displaystyle \frac{\begin{array}[b]{r}40\\ \times\ 5\end{array}}{ \ \ \ \space}\)

Possible Answers:

\(\displaystyle 200\)

\(\displaystyle 230\)

\(\displaystyle 220\)

\(\displaystyle 210\)

\(\displaystyle 240\)

Correct answer:

\(\displaystyle 200\)

Explanation:

To solve this problem, we multiply \(\displaystyle 5\) by the ones position and the tens position. 

\(\displaystyle 5\times0=0\)

\(\displaystyle 5\times4=20\)

\(\displaystyle \frac{\begin{array}[b]{r}40\\ \times\ 5\end{array}}{ \ \space200}\)

Example Question #971 : Common Core Math: Grade 3

\(\displaystyle \frac{\begin{array}[b]{r}50\\ \times\ 6\end{array}}{ \ \ \ \space}\)

Possible Answers:

\(\displaystyle 10\)

\(\displaystyle 50\)

\(\displaystyle 20\)

\(\displaystyle 40\)

\(\displaystyle 30\)

Correct answer:

\(\displaystyle 30\)

Explanation:

To solve this problem, we multiply \(\displaystyle 6\) by the ones position and the tens position. 

\(\displaystyle 6\times0=0\)

\(\displaystyle 6\times5=30\)

\(\displaystyle \frac{\begin{array}[b]{r}50\\ \times\ 6\end{array}}{ \ \space300}\)

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