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Example Questions
Example Question #151 : Pre Calculus
Simplify the following expression so that it is only 1 logarithm:
When combining logarithms there are a few rules to remember. First, addition outside a log is multiplication inside. Subtraction outside a log is division inside. Finally, multiplication/division outside are exponents inside. Also, ln(1)=0. So,
turns into
and then
Example Question #1 : Exponential Functions
Suppose the graph of an exponential equation contains the points and . What is the formula of this line?
Recall the standard form of an exponential equation:
Plug in the two ordered pairs:
Solve for a in the first equation:
Now plug this value into the second equation:
Simplify:
Multiply both sides by 3/2 and simplify:
Plug this into the first equation to solve for a:
Plug the values of a and b into the general form to get the answer:
Example Question #2 : Exponential Functions
A calculator is required to solve this problem.
Suppose a population is currently at 5000, and that it increases by 5% every year. How large will the population be in 5 years? Round your answer to the nearest whole number.
5000
6250
5469
5250
6381
6381
The standard formula for population growth is
,
where is the population after time t, is the initial population, and r is the rate of growth as a decimal, per unit time. (In other words, r and t must have the same units.)
The problem also gives us initial population as 5000 and growth rate as 5% or .05.
Plug in:
Simplify the parentheses:
Evaluate:
Round to get the final answer:
Example Question #3 : Exponential Functions
To solve this question you will need a calculator or other graphing tool capable of evaluating logarithms.
Suppose a colony of bacteria is decaying at a constant rate of 2% per minute. How many minutes will it take for the colony's population to decrease by half? Round your answer to the nearest whole minute.
25 minutes
20 minutes
34 minutes
35 minutes
-35 minutes
34 minutes
We recall that the formula for population decay is
,
where is the population at time t, is the initial population, and r is the rate of decrease per unit time (same unit as t).
is half of , so we can write
.
Simplify and eliminate common factors:
Take the log of both sides. Note that the log has base .98.
Use the change of base theorem to rewrite the log:
Round:
Example Question #1 : Exponential Functions
Expand and simplify:
Example Question #2 : Exponential Functions
Identify the curve representing in the graph below.
A
B
D
E
C
D
the -int will be when and the -int will not exist because all the values of this function are positive.
So the curve must be D since that is the only curve that intersects at the point
Example Question #1 : Sequences And Series
Evaluate:
None of the other answers are correct.
This sum can be determined using the formula for the sum of an infinite geometric series, with initial term and common ratio :
Example Question #1 : Sequences And Series
The fourth term in an arithmetic sequence is -20, and the eighth term is -10. What is the hundredth term in the sequence?
55
220
210
105
110
220
An arithmetic sequence is one in which there is a common difference between consecutive terms. For example, the sequence {2, 5, 8, 11} is an arithmetic sequence, because each term can be found by adding three to the term before it.
Let denote the nth term of the sequence. Then the following formula can be used for arithmetic sequences in general:
, where d is the common difference between two consecutive terms.
We are given the 4th and 8th terms in the sequence, so we can write the following equations:
.
We now have a system of two equations with two unknowns:
Let us solve this system by subtracting the equation from the equation . The result of this subtraction is
.
This means that d = 2.5.
Using the equation , we can find the first term of the sequence.
Ultimately, we are asked to find the hundredth term of the sequence.
The answer is 220.
Example Question #2 : Sequences And Series
What is the lowest value of where the sum of the arithmetic sequence where will exceed 200?
The sum of all odd numbers is another way to construct perfect squares. To see why this is, we can construct the series as follows.
We draw from the series by subtracting one from each term.
We discard the 0 term and factor 2 out of the remaining terms.
And finally we use the property that to evaluate the series.
The smallest value of where the square exceeds 200 is .
Example Question #1 : Sequences And Series
The first term in an arithmetic series is 3, and the 9th term is 35. What is the 17th term?
The terms of an arithmetic series are generated by the relation
,
where is the 1st term, is the nth term, and d is the common difference.
For
,
for
.
The first step is to find .
, so
.
Now to find , when .
Use the generating relation
.
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