LSAT Logic Games : Solving grouping games
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Example Questions
Example Question #650 : Lsat Logic Games
A suburban housing development has six models of homes—A, B, C, D, E, and F. Each model has at least one of the following three features: swimming pool, central air conditioning, and patio. The following conditions apply to the distribution of these features:
B has a swimming pool and a patio.
C has a swimming pool and central air conditioning.
C and E have no features in common.
D has more features than C.
B and F have exactly one feature in common.
A has fewer features than F.
If no two home models have exactly the same features as one another, then each of the following could be true EXCEPT:
Exactly four of the six homes have a swimming pool
Exactly three of the six homes have a patio
Exactly four of the six homes have central air conditioning
Exactly four of the six homes have a patio
Exactly three of the six homes have a swimming pool
Exactly three of the six homes have a patio
B, C, D, and E are already locked in. A has only one feature and it must either be a pool or central air, because a patio would make it identical to E. F must have central air, according to the diagram. Between the options of pool or patio, it must have a patio, because having a pool would make it identical to C. Therefore, B, D, E, and F must have patios, thus showing it is false to say that “exactly three of the six homes have a patio.”
Example Question #141 : Solving Grouping Games
Eight people will participate in a basketball game. There will be two teams, Team 1 and Team 2, each with three starters and one alternate. The eight people are Brady, Carol, Dave, Elsie, Fran, George, Herb, and Irene. The following rules apply:
George and Brady must be on different teams
If Carol starts for Team 2, then Irene starts for Team 1
Either Dave or Irene is an alternate, but not both
If Fran starts, then George is an alternate on the same team
Elsie must start
Which of the following could be a list of the starters and alternates for each team?
Team 1 starters: Herb, Fran, Elsie; alternate: George
Team 2 starters: Brady, Carol, Irene; alternate: Dave
Team 1 starters: Fran, Irene, Elsie; alternate: George
Team 2 starters: Brady, Carol, Dave; alternate: Herb
Team 1 starters: Elsie, Brady, Carol; alternate: Irene
Team 2 starters: Herb, George, Dave; alternate: Fran
Team 1 starters: Carol, Dave, Elsie; alternate: George
Team 2 starters: Brady, Fran, Herb; alternate: Irene
Team 1 starters: Elsie, Herb, Carol; alternate: Irene
Team 2 starters: Brady, George, Dave; alternate: Fran
Team 1 starters: Elsie, Brady, Carol; alternate: Irene
Team 2 starters: Herb, George, Dave; alternate: Fran
Each incorrect answer contradicts one or more of the rules. Apply the rules to eliminate each incorrect answer.
Example Question #142 : Solving Grouping Games
Eight people will participate in a basketball game. There will be two teams, Team 1 and Team 2, each with three starters and one alternate. The eight people are Brady, Carol, Dave, Elsie, Fran, George, Herb, and Irene. The following rules apply:
George and Brady must be on different teams
If Carol starts for Team 2, then Irene starts for Team 1
Either Dave or Irene is an alternate, but not both
If Fran starts, then George is an alternate on the same team
Elsie must start
If Carol is on Team 2, what must be true?
Dave is an alternate
Brady is on Team 2
Dave and Carol are on the same team
Elsie is on Team 2
Brady is an alternate
Dave is an alternate
When Carol starts on Team 2, Irene starts on Team 1. Since Dave and Irene cannot both be starters, Dave must be an alternate.
Example Question #143 : Solving Grouping Games
Eight people will participate in a basketball game. There will be two teams, Team 1 and Team 2, each with three starters and one alternate. The eight people are Brady, Carol, Dave, Elsie, Fran, George, Herb, and Irene. The following rules apply:
George and Brady must be on different teams
If Carol starts for Team 2, then Irene starts for Team 1
Either Dave or Irene is an alternate, but not both
If Fran starts, then George is an alternate on the same team
Elsie must start
If George and Herb start for Team 1, what must be true?
Elsie starts for Team 2
Irene is an alternate
Irene is on Team 1
Carol is on Team 1
Dave is the alternate for Team 1
Elsie starts for Team 2
When George and Herb start for Team 1, the third starter for that team must either be Irene or Carol. One alternate must be either Irene or Dave, and the other must be Fran. as a result, Elsie must start for Team 2.
Example Question #144 : Solving Grouping Games
Eight people will participate in a basketball game. There will be two teams, Team 1 and Team 2, each with three starters and one alternate. The eight people are Brady, Carol, Dave, Elsie, Fran, George, Herb, and Irene. The following rules apply:
George and Brady must be on different teams
If Carol starts for Team 2, then Irene starts for Team 1
Either Dave or Irene is an alternate, but not both
If Fran starts, then George is an alternate on the same team
Elsie must start
Which of the following cannot be true?
Herb is an alternate
Irene and Carol are on the same team
Irene is an alternate
Fran is an alternate
Brady is on the same team as Fran
Herb is an alternate
To answer this question, you must note the significant restrictions on which players can be alternates. One of the alternates must be either Irene or Dave. The other alternate must be either George or Fran. As a result, Herb can never be an alternate.
Example Question #145 : Solving Grouping Games
Eight people will participate in a basketball game. There will be two teams, Team 1 and Team 2, each with three starters and one alternate. The eight people are Brady, Carol, Dave, Elsie, Fran, George, Herb, and Irene. The following rules apply:
George and Brady must be on different teams
If Carol starts for Team 2, then Irene starts for Team 1
Either Dave or Irene is an alternate, but not both
If Fran starts, then George is an alternate on the same team
Elsie must start
If Irene is an alternate, which of the following could be true?
Carol is on Team 2
Brady is on Team 1
Brady and George are on the same team
Dave is an alternate
Irene and Fran are on the same team
Brady is on Team 1
When Irene is an alternate, a few things are restricted. First, Carol must be a starter on Team 1. Second, Fran cannot be on the same team as Irene. Finally, Dave must be a starter if Irene is an alternate.
Example Question #146 : Solving Grouping Games
Eight people will participate in a basketball game. There will be two teams, Team 1 and Team 2, each with three starters and one alternate. The eight people are Brady, Carol, Dave, Elsie, Fran, George, Herb, and Irene. The following rules apply:
George and Brady must be on different teams
If Carol starts for Team 2, then Irene starts for Team 1
Either Dave or Irene is an alternate, but not both
If Fran starts, then George is an alternate on the same team
Elsie must start
If the rules are changed so that both Irene and Dave must be starters, and if all other rules remain, which of the following could be true?
Both Fran and George are alternates
Both Carol and Brady are alternates
Both Elsie and Fran are alternates
Both Brady and Herb are alternates
Both Carol and Herb are alternates
Both Fran and George are alternates
If neither Irene nor Dave was an alternate, no rule would prevent Fran and George from being alternates on different teams. While it is possible for both to be alternates, it is not possible for neither of them to be.
Example Question #147 : Solving Grouping Games
Three stores -- Store T, Store U, and Store V -- are selling five types of fruit: apples, bananas, grapes, oranges, and strawberries. Each store sells exactly three types of fruit, and each type of fruit is sold by at least one store. The following conditions are applicable:
Exactly two of the stores sell bananas.
If Store T sells grapes, Store U does not sell grapes.
If Store V does not sell oranges, it sells bananas.
Store U sells exactly two of the same types of fruit Store V sells.
Any store that sells oranges does not also sell strawberries.
Which one of the following could be a complete and accurate list of the types of fruit each store sells?
Store T: apples, bananas, oranges; Store U: apples, grapes, strawberries; Store V: bananas, grapes, strawberries
Store T: bananas, grapes, oranges; Store U: apples, bananas, oranges; Store V: apples, bananas, strawberries
Store T: apples, bananas, oranges; Store U: bananas, grapes, strawberries; Store V: apples, grapes, strawberries
Store T: apples, bananas, grapes; Store U: apples, grapes, oranges; Store V: bananas, grapes, strawberries
Store T: bananas, oranges, strawberries; Store U: apples, grapes, oranges; Store V: apples, bananas, strawberries
Store T: apples, bananas, oranges; Store U: apples, grapes, strawberries; Store V: bananas, grapes, strawberries
The correct answer choice is the only one that satisfies all the conditions. Each of the other answer choices breaks one or more conditions by having more than two stores sell bananas, having both Stores T and U sell grapes, having Store V sell neither oranges nor bananas, having Stores U and V not have two types of fruit in common, or having a store sell both oranges and strawberries.
Example Question #148 : Solving Grouping Games
Three stores -- Store T, Store U, and Store V -- are selling five types of fruit: apples, bananas, grapes, oranges, and strawberries. Each store sells exactly three types of fruit, and each type of fruit is sold by at least one store. The following conditions are applicable:
Exactly two of the stores sell bananas.
If Store T sells grapes, Store U does not sell grapes.
If Store V does not sell oranges, it sells bananas.
Store U sells exactly two of the same types of fruit Store V sells.
Any store that sells oranges does not also sell strawberries.
If Stores T and U both sell oranges, which one of the following could be true?
Store V sells oranges.
Store T sells bananas.
All three stores sell apples.
Store U sells grapes.
Two of the stores sell strawberries.
All three stores sell apples.
All three stores can (and, in fact, must) sell apples under this scenario. Because the other two stores sell oranges, Store V (and only Store V) must sell strawberries. Consequently, Stores U and V must sell bananas because their remaining two fruits must be in common. Thus, Store T cannot sell bananas. Finally, Store U and Store V cannot sell grapes because if they did, Store T would be unable to sell three types of fruit. The only remaining fruit for Stores U and V to sell in common is apples.
Example Question #149 : Solving Grouping Games
Three stores -- Store T, Store U, and Store V -- are selling five types of fruit: apples, bananas, grapes, oranges, and strawberries. Each store sells exactly three types of fruit, and each type of fruit is sold by at least one store. The following conditions are applicable:
Exactly two of the stores sell bananas.
If Store T sells grapes, Store U does not sell grapes.
If Store V does not sell oranges, it sells bananas.
Store U sells exactly two of the same types of fruit Store V sells.
Any store that sells oranges does not also sell strawberries.
Which one of the following CANNOT be true?
Exactly two of the stores sell strawberries.
Exactly one of the stores sells apples.
Exactly one of the stores sells grapes.
Exactly one of the stores sells oranges.
Exactly two of the stores sell oranges.
Exactly one of the stores sells apples.
At least two of the stores must sell apples. The conditions make it clear that other than apples, none of the other fruits can be sold by all three stores: Oranges and strawberries are mutually exclusive, bananas are sold at exactly two stores, and grapes cannot be sold at both Store T and Store U. Furthermore, either oranges or strawberries (or both) must be sold at only one store, since they cannot both be sold at the same store. This leaves at least four open slots which must be filled by either grapes or apples. Since grapes cannot be sold at all three stores, at least two of these slots must be filled by apples.
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