All HiSET: Math Resources
Example Questions
Example Question #1 : Understand And Apply Concepts Of Equations
Give the nature of the solution set of the equation
.
One rational solution
One imaginary solution
Two rational solutions
Two irrational solutions
Two imaginary solutions
Two imaginary solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
This can be done by simply switching the first and second terms:
The key to determining the nature of the solution set is to examine the discriminant . Setting , the value of the discriminant is
The discriminant has a negative value. It follows that the solution set comprises two imaginary values.
Example Question #7 : Quadratic Equations
Give the nature of the solution set of the equation
One rational solution
Two rational solutions
Two imaginary solutions
Two irrational solutions
One imaginary solution
Two imaginary solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
This can be done by adding 17 to both sides:
The key to determining the nature of the solution set is to examine the discriminant
. Setting , the value of the discriminant is
This value is negative. Consequently, the solution set comprises two imaginary numbers.
Example Question #11 : Understand And Apply Concepts Of Equations
Give the nature of the solution set of the equation
Two rational solutions
One rational solution
Two imaginary solutions
Two irrational solutions
One imaginary solution
Two irrational solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
To accomplish this, first, multiply the binomials on the left using the FOIL technique:
Collect like terms:
Now, subtract 18 from both sides:
The key to determining the nature of the solution set is to examine the discriminant . Setting , the value of the discriminant is
The discriminant is a positive number, so there are two real solutions. Since 73 is not a perfect square, the solutions are irrational.
Example Question #1 : Quadratic Equations
Give the nature of the solution set of the equation
One rational solution
Two irrational solutions
One imaginary solution
Two imaginary solutions
Two rational solutions
Two imaginary solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
To accomplish this, first, multiply the binomials on the left using the FOIL technique:
Collect like terms:
Now, add 18 to both sides:
The key to determining the nature of the solution set is to examine the discriminant . Setting , the value of the discriminant is
This discriminant is negative. Consequently, the solution set comprises two imaginary numbers.
Example Question #11 : Understand And Apply Concepts Of Equations
Give the nature of the solution set of the equation
Two imaginary solutions
Two rational solutions
Two irrational solutions
One rational solution
One imaginary solution
Two irrational solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
This can be done by switching the first and third terms on the left:
The key to determining the nature of the solution set is to examine the discriminant
. Setting , the value of the discriminant is
.
The discriminant is a positive number but not a perfect square. Therefore, there are two irrational solutions.
Example Question #21 : Algebraic Concepts
Give the nature of the solution set of the equation
One imaginary solution
One rational solution
Two irrational solutions
Two imaginary solutions
Two rational solutions
Two irrational solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
This can be done by subtracting 34 from to both sides:
The key to determining the nature of the solution set is to examine the discriminant
. Setting , the value of the discriminant is
.
The discriminant is a positive number but not a perfect square. Therefore, there are two irrational solutions.
Example Question #12 : Understand And Apply Concepts Of Equations
Solve the following equation:
The first step to solving an equation where is in a radical is to isolate the radical. To do this, we need to subtract the 5 from both sides.
Now that the radical is isolated, clear the radical by raising both sides to the power of 3. Note:
Now we want to isolate the term. First, subtract the 5 from both sides.
Finally, divide both sides by to solve for .
Example Question #1 : Rearrange Formulas/Equations To Highlight A Quantity Of Interest
Solve for :
To solve for in a literal equation, use the properties of algebra to isolate on one side, just as if you were solving a regular equation.
Multiply both sides by :
Subtract from both sides:
Multiply both sides by , distributing on the right:
,
the correct response.
Example Question #2 : Rearrange Formulas/Equations To Highlight A Quantity Of Interest
Solve for :
Assume is positive.
To solve for in a literal equation, use the properties of algebra to isolate on one side, just as if you were solving a regular equation.
Subtract from both sides:
Divide both sides by 9:
Take the square root of both sides:
Simplify the expression on the right by splitting it, and taking the square root of numerator and denominator:
,
the correct response.
Example Question #1 : Rearrange Formulas/Equations To Highlight A Quantity Of Interest
Solve for :
To solve for in a literal equation, use the properties of algebra to isolate on one side, just as if you were solving a regular equation.
First, take the reciprocal of both sides:
Multiply both sides by :
Distribute on the right:
Subtract 1 from both sides, rewriting 1 as to facilitate subtraction:
,
the correct response.