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GRE Subject Test: Math : Algebra

Study concepts, example questions & explanations for GRE Subject Test: Math

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All GRE Subject Test: Math Resources

2 Diagnostic Tests 148 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

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Example Question #21 : Imaginary Numbers & Complex Functions

$\sqrt{-7}\cdot \sqrt{-4}$

Possible Answers:

$-i\sqrt{7}$

$i\sqrt{28}$

$-2\sqrt{7}$

$\sqrt{28}$

$2\sqrt{7}$

Correct answer:

$-2\sqrt{7}$

Explanation:

$\sqrt{-7}\cdot \sqrt{-4}$

First, take out i (the square root of -1) from both radicals and then multiply. You are not allowed to first multiply the radicals and then simplify because the roots are negative.

$i\sqrt{7}\cdot 2i$

$2i^{2}\sqrt{7}$

Change i squared to -1

$2(-1)\sqrt{7}$

$-2\sqrt{7}$

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Example Question #21 : Imaginary Numbers & Complex Functions

$\frac{\sqrt{-51}}{\sqrt{3}}$

Possible Answers:

$\sqrt{-17}$

$-\sqrt{17}$

$i\sqrt{17}$

17i

$\sqrt{17}$

Correct answer:

$i\sqrt{17}$

Explanation:

$\frac{\sqrt{-51}}{\sqrt{3}}$

Take i (the square root of -1) out of the radical.

$\frac{i\sqrt{51}}{\sqrt{3}}$

$i\sqrt{17}$

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Example Question #12 : Operations On Complex Numbers

$\sqrt{5}\cdot \sqrt{-42}$

Possible Answers:

$i\sqrt{210}$

$5i\sqrt{14}$

$-2\sqrt{3}$

$i\sqrt{47}$

Correct answer:

$i\sqrt{210}$

Explanation:

$\sqrt{5}\cdot \sqrt{-42}$

Take out i (the square root of -1) from the radical and then multiply.

$\sqrt{5}\cdot i\sqrt{42}$

$i\sqrt{210}$

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Example Question #271 : Gre Subject Test: Math

$\sqrt{-45}\cdot \sqrt{72}$

Possible Answers:

$-\sqrt{10}$

$18i\sqrt{10}$

$i\sqrt{10}$

$6i\sqrt{10}$

$4i\sqrt{10}$

Correct answer:

$18i\sqrt{10}$

Explanation:

$\sqrt{-45}\cdot \sqrt{72}$

Take out i (the square root of -1) and then simplify before multiplying.

$i\sqrt{45}\cdot \sqrt{72}$

$i\sqrt{9\cdot 5}\cdot \sqrt{36\cdot 2}$

$3i\sqrt{5}\cdot 6\sqrt{2}$

$18i\sqrt{10}$

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Example Question #273 : Gre Subject Test: Math

$-\sqrt{-16}\cdot \sqrt{-40}$

Possible Answers:

$i\sqrt{10}$

$8\sqrt{5}$

$-4i\sqrt{10}$

$8\sqrt{10}$

$4\sqrt{5}$

Correct answer:

$8\sqrt{10}$

Explanation:

$-\sqrt{-16}\cdot \sqrt{-40}$

Take out i (the square root of -1) from both radicals and then multiply. You are not allowed to first multiply the radicals and then simplify because the roots are negative.

$-i\sqrt{16}\cdot i\sqrt{40}$

$-4i\cdot i\sqrt{4\cdot 10}$

$-4i\cdot 2i\sqrt{10}$

$-8i^{2}\sqrt{10}$

$-8(-1)\sqrt{10}$

$8\sqrt{10}$

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Example Question #91 : Algebra

$-\sqrt{-20}\cdot -\sqrt{32}$

Possible Answers:

$8i\sqrt{10}$

$-4\sqrt{10}$

$-8i\sqrt{10}$

$-8\sqrt{10}$

$8\sqrt{10}$

Correct answer:

$8i\sqrt{10}$

Explanation:

$-\sqrt{-20}\cdot -\sqrt{32}$

Take out i (the square root of -1) from the radical, simplify, and then multiply.

$-i\sqrt{20}\cdot -\sqrt{32}$

$-i\sqrt{5\cdot 4}\cdot -\sqrt{16\cdot 2}$

$-2i\sqrt{5}\cdot -4\sqrt{2}$

$8i\sqrt{10}$

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Example Question #92 : Algebra

$\sqrt{-70}\cdot -\sqrt{-50}$

Possible Answers:

$5\sqrt{20}$

$10\sqrt{30}$

$5\sqrt{10}$

$10\sqrt{35}$

$-5\sqrt{5}$

Correct answer:

$10\sqrt{35}$

Explanation:

$\sqrt{-70}\cdot -\sqrt{-50}$

Take out i (the square root of -1) from both radicals, simplify, and then multiply. You are not allowed to first multiply the radicals and then simplify because the roots are negative.

$i\sqrt{70}\cdot -i\sqrt{50}$

$i\sqrt{70}\cdot -i\sqrt{25\cdot 2}$

$i\sqrt{70}\cdot -5i\sqrt{2}$

$-5i^{2}\sqrt{140}$

$-5(-1)\sqrt{140}$

$5\sqrt{140}$

$5\sqrt{4\cdot 35}$

$10\sqrt{35}$

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Example Question #21 : Operations On Complex Numbers

$\sqrt{-225}\cdot \sqrt{-289}$

Possible Answers:

$-15\sqrt{17}$

255i

$15i\sqrt{17}$

25i

Correct answer:

Explanation:

$\sqrt{-225}\cdot \sqrt{-289}$

Take out i (the square root of -1) from both radicals, simplify, and then multiply. You are not allowed to first multiply the radicals and then simplify because the roots are negative.

$i\sqrt{225}\cdot i\sqrt{289}$

$15i\cdot 17i$

$255i^{2}$

255(-1)

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Example Question #21 : Operations On Complex Numbers

$\sqrt{-15}\cdot \sqrt{-33}$

Possible Answers:

$\sqrt{495}$

$-i\sqrt{495}$

$i\sqrt{495}$

$-3\sqrt{55}$

$-\sqrt{495}$

Correct answer:

$-3\sqrt{55}$

Explanation:

$\sqrt{-15}\cdot \sqrt{-33}$

Take out i (the square root of -1) from both radicals and then multiply. You are not allowed to first multiply the radicals and then simplify because the roots are negative.

$i\sqrt{15}\cdot i\sqrt{33}$

$i^{2}\sqrt{495}$

$(-1)\sqrt{495}$

It might be difficult to tell that this simplifies but you should always check if the perfect squares (4, 9, 16, etc) divide into this number. 9 does divide into 495 so this simplifies further.

$-\sqrt{9\cdot 55}$

$-3\sqrt{55}$

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Example Question #31 : Imaginary Numbers & Complex Functions

$-\sqrt{121}\cdot \sqrt{-12}$

Possible Answers:

$44i\sqrt{3}$

$-44\sqrt{3}$

$-22i\sqrt{3}$

$11i\sqrt{12}$

$-44i\sqrt{3}$

Correct answer:

$-22i\sqrt{3}$

Explanation:

$-\sqrt{121}\cdot \sqrt{-12}$

Take out i (the square root of -1) from the radical, simplify each radical, then multiply.

$-\sqrt{121}\cdot i\sqrt{12}$

$-11\cdot i\sqrt{4\cdot 3}$

$-11\cdot 2i\sqrt{3}$

$-22i\sqrt{3}$

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GRE Subject Test: Math : Algebra

Study concepts, example questions & explanations for GRE Subject Test: Math

All GRE Subject Test: Math Resources

Example Questions

Example Question #21 : Imaginary Numbers & Complex Functions

Example Question #21 : Imaginary Numbers & Complex Functions

Example Question #12 : Operations On Complex Numbers

Example Question #271 : Gre Subject Test: Math

Example Question #273 : Gre Subject Test: Math

Example Question #91 : Algebra

Example Question #92 : Algebra

Example Question #21 : Operations On Complex Numbers

Example Question #21 : Operations On Complex Numbers

Example Question #31 : Imaginary Numbers & Complex Functions

All GRE Subject Test: Math Resources

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