GED Math : GED Math

Study concepts, example questions & explanations for GED Math

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Example Questions

Example Question #32 : Probability

Billy flips a fair coin three times.  His results were three tails.  Billy then flipped the coin three times again and was shocked to see the results were also three tails!  What is the probability that Billy flipped the coin 6 times, and all trials are tails?

Possible Answers:

Correct answer:

Explanation:

Every result for a fair coin is independent of the previous trials.

The probability of landing heads or tails is .

For the coin to land on tails six consecutive times,

The answer is:  

Example Question #33 : Probability

 A classroom contains the following:

  • 12 boys
  • 14 girls

Find the probability the teacher calls on a girl.

Possible Answers:

Correct answer:

Explanation:

To find the probability of an event, we will use the following formula:

Given the event of the teacher calling on a girl, we can calculate the following:

because there are 14 girl in the class.

We can also calculate the following:

because there are 26 total students in the class the teacher could potentially call on:

  • 12 boys
  • 14 girls

So, we substitute. We get

Therefore, the probability that the teacher calls on a girl is 

Example Question #34 : Probability

A board game uses a six sided die, and a spinner that is split into quarters with the colors red, blue, yellow, and green. What is the probability of rolling a  or  and spinning green?

Possible Answers:

Correct answer:

Explanation:

Start by figuring out the probability of rolling a  or . Since a six sided die has an equal chance of landing on each number, the probability would be , or .

 

Next, figure out the probability of spinning green. Since the spinner is divided equally into quarters, the probability of spinning green is .

 

Because the question asks about the probability of both events happening, you will need to multiply the two probabilities together.

 

Example Question #31 : Statistics

For a certain game, players will need to spin a spinner divided into equal sixths and numbered from  to  then roll a normal fair  sided die. What is the probability of spinning an even number and rolling a ?

Possible Answers:

Correct answer:

Explanation:

Start by finding the probability of spinning an even number. We have  total possibilities for the spinner. Out of those six,  will give us even numbers: . Thus, we can write the following probability:

Next, determine the probability of rolling a  on the die. Since we are using a fair,  sided die, the probability of rolling a  will be .

Since the question asks about the probability of both events happening, we will need to multiply the two probabilities.

Example Question #31 : Probability

At a certain carnival game, players must toss beanbags into a small colored circle within a square playing field, as shown by the figure below.

4

The length of one side of the playing field is  inches, and the diameter of the circle is one-fourth that of a side of the playing field. What is the probability of the bean bag landing in the colored circle? Use 

Possible Answers:

Correct answer:

Explanation:

Recall the definition of a probability:

Now, the desired outcome for this scenario is the beanbag landing in the circle. Thus, we can use the area of the circle as the desired outcome. In addition, the total possible outcomes can then be represented by the area of the entire square playing field.

Start by finding the area of the playing field. Recall how to find the area of a square:

Plug in the given side length of the square.

Next, find the area of the circle.

Since the question informs us that the diameter of the circle is one-fourth that of the side of the square playing field, the diameter of the circle must be . It also follows that the radius of the circle must be .

Recall how to find the area of the circle.

Plug in the given radius to find the area of the circle.

Now that we have both areas, we can write probability:

 

Example Question #34 : Probability

A class of  students was surveyed to see how many pets each student's family owned. The results were then graphed as shown below.

1

If two students are selected at random from this class one after another without replacement, what is the probability that the first student selected will have  pets and that the second student selected will have  pets?

Possible Answers:

Correct answer:

Explanation:

Recall how to find the probability of an event:

Since there are  students out of the total  who have two pets, the probability for that occurring is .

Now, since we are selecting students without replacement, this means that the total number of students to choose from when it's time to select the second student is . There are also  students who have no pets, so we can write  as the probability that the second student selected will have no pets.

Since the question wants to know the probability of both events happening, we will multiply the probabilities together:

Example Question #36 : Probability

If you have a standard, six-sided die, what is the probability of rolling two numbers greater than 3 on two separate rolls?

Possible Answers:

Correct answer:

Explanation:

If you have a standard, six-sided die, what is the probability of rolling two numbers greater than 3 on two separate rolls?

We need to find the probability of two independent events. To do so, we need to find the probability of each event and multiply them.

There are three numbers on a six-sided die that are greater than 3 (4,5,and 6).

Thus, our probability of each event is

But, we want the probability of doing this twice, so we need to multiply our probabilities.

So, our answer is 

Example Question #37 : Probability

Spinner

If the arrow in the above spinner is spun, what is the probability that it will land in a green region?

Possible Answers:

Correct answer:

Explanation:

Each of the larger regions is one-eighth of the ring; each of the smaller regions is one-sixteenth of the ring. There are three small green regions and no large green regions, so the green portion of the ring is

of the ring. This is the probability that the arrow will land in a green region.

Example Question #31 : Calculations

In order to win a carnival game, a player must roll an even number on a fair six-sided die, then spin have a spinner land on the blue portion. The spinner is evenly divided into five sections with the following colors: red, blue, yellow, green, and purple. What is the probability of winning this game?

Possible Answers:

Correct answer:

Explanation:

Recall what a probability is:

For the die, we can find the probability of rolling an even number:

Next, for the spinner, we can find the probability of landing on blue:

Since we want the probability of both evens happening, we will need to multiply the individual probabilities together:

Example Question #41 : Statistics

A spinner is divided into five equal quadrants, each of which with a different color: red, blue yellow, green, and orange. If you roll a fair six-sided dice and then spin the spinner, what is the probability of rolling  then landing on either red or blue?

Possible Answers:

Correct answer:

Explanation:

Start by finding the individual probabilities of either event.

The probability of rolling a  is .

The probability of landing on either red or blue on the spinner is .

To find the probability of both events happening, you must multiply the two probabilities together.

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