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Common Core: High School - Geometry : High School: Geometry

Study concepts, example questions & explanations for Common Core: High School - Geometry

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All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #401 : High School: Geometry

Find the volume of a sphere with radius 409 . Round your answer to the nearest hundredth.

Possible Answers:

91223905.33

45611952.67

68417929

286588350.83

143294175.41

Correct answer:

286588350.83

Explanation:

In order to find the volume of a sphere, we need to recall the volume of a sphere equation.

$V = \frac{4 \pi}{3} r^{3}$
We simply plug in 409 for $\uptext{r}$ .

$V=\frac{4}{3}\cdot\pi\cdot ( 409 )^3$

V= 286588350.82697076

Now we round our answer to the nearest hundredth.

V= 286588350.83

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Example Question #401 : High School: Geometry

Find the volume of a hemisphere with radius 464 . Round your answer to the nearest hundredth.

Possible Answers:

209224508.02

133196458.67

99897344

418449016.03

66598229.33

Correct answer:

209224508.02

Explanation:

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$V = \frac{2 \pi}{3} r^{3}$

We simply plug in 464 for $\uptext{r}$ .

$V=\frac{2}{3}\cdot\pi\cdot ( 464 )^3$

V= 209224508.01568824

Now we round our answer to the nearest hundredth.

V= 209224508.02

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Example Question #402 : High School: Geometry

Find the volume of a hemisphere with radius 341 . Round your answer to the nearest hundredth.

Possible Answers:

39651821

166093159.41

52869094.67

26434547.33

83046579.7

Correct answer:

83046579.7

Explanation:

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$V = \frac{2 \pi}{3} r^{3}$

We simply plug in 341 for $\uptext{r}$ .

$V=\frac{2}{3}\cdot\pi\cdot ( 341 )^3$

V= 83046579.70337164

Now we round our answer to the nearest hundredth.

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Example Question #403 : High School: Geometry

Find the volume of a hemisphere with radius . Round your answer to the nearest hundredth.

Possible Answers:

457.33

1436.76

718.38

228.67

343

Correct answer:

718.38

Explanation:

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$V = \frac{2 \pi}{3} r^{3}$

We simply plug in for $\uptext{r}$ .

$V=\frac{2}{3}\cdot\pi\cdot ( 7 )^3$

V= 718.3775201208659

Now we round our answer to the nearest hundredth.

V= 718.38

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Example Question #1 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Find the volume of a sphere, where the radius is .

Possible Answers:

$V = \frac{2048}{3}$

$V = 512 \pi$

$V = \frac{2048 \pi}{3}$

V = 512

$V = \frac{256 \pi}{3}$

Correct answer:

$V = \frac{2048 \pi}{3}$

Explanation:

Before we find the volume of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the radius ( $\uptext{r}$ ), we can plug it into the equation.

$V = \frac{2048 \pi}{3}$

Thus the volume is, $\frac{2048 \pi}{3}$

Here is a picture representation of the sphere.

Plot1

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Example Question #2 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Find the volume of a sphere, where the radius is .

Possible Answers:

$V = 108 \pi$

V = 729

$V = 729 \pi$

V = 972

$V = 972 \pi$

Correct answer:

$V = 972 \pi$

Explanation:

Before we find the volume of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the radius ( $\uptext{r}$ ), we can plug it into the equation.

$V = 972 \pi$

Thus the volume is, $972 \pi$

Here is a picture representation of the sphere.

Plot2

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Example Question #1 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Find the volume of a sphere, where the radius is .

Possible Answers:

$V = 18432 \pi$

V = 13824

V = 18432

$V = 13824 \pi$

$V = 768 \pi$

Correct answer:

$V = 18432 \pi$

Explanation:

Before we find the volume of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the radius ( $\uptext{r}$ ), we can plug it into the equation.

$V = 18432 \pi$

Thus the volume is, $18432 \pi$

Here is a picture representation of the sphere.

Plot6

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Example Question #406 : High School: Geometry

Find the volume of a sphere, where the radius is .

Possible Answers:

$V = \frac{48668}{3}$

$V = 12167 \pi$

$V = \frac{2116 \pi}{3}$

V = 12167

$V = \frac{48668 \pi}{3}$

Correct answer:

$V = \frac{48668 \pi}{3}$

Explanation:

Before we find the volume of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the radius ( $\uptext{r}$ ), we can plug it into the equation.

$V = \frac{48668 \pi}{3}$

Thus the volume is, $\frac{48668 \pi}{3}$

Here is a picture representation of the sphere.

Plot12

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Example Question #41 : Geometric Measurement & Dimension

Find the radius of a sphere, where the volume is 1658 . Round your answer to digits.

Possible Answers:

r = 62.50

$r = \frac{2487 \pi}{2}$

$r = \frac{2487}{2}$

r = 15.75

r = 7.91

Correct answer:

r = 15.75

Explanation:

Before we find the radius of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the volume ( $\uptext{V}$ ), we can plug it into the equation.

$1658 = \frac{4 \pi}{3} r^{3}$

Now we can solve for $\uptext{r}$ .

Now we divide by $\frac{4 \pi}{3}$ on each side.

Now our equation is

$r^{3} = \frac{2487 \pi}{2}$

To solve for $\uptext{r}$ , we need to take the cube root on each side.

r = 15.75

Here is a picture representation of our sphere.

Plot3

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Example Question #42 : Geometric Measurement & Dimension

Find the radius of a hemisphere, where the volume is 2822 .
Round your answer to digits.

Possible Answers:

r = 4233

$r = \frac{4233}{\pi}$

r = 11.05

r = 115.32

r = 10.74

Correct answer:

r = 11.05

Explanation:

Before we find the radius of a hemisphere, we need to recall the equation.

$V = \frac{2 \pi}{3} r^{3}$

Since we are given the volume ( $\uptext{V}$ ), we can plug it into the equation.

$2822 = \frac{2 \pi}{3} r^{3}$

Now we can solve for $\uptext{r}$ .

Now we divide by $\frac{2 \pi}{3}$ on each side.

Now our equation is

$r^{3} = \frac{4233}{\pi}$

To solve for $\uptext{r}$ , we need to take the cube root on each side.

r = 11.05

Here is a picture of the hemisphere.

Plot4

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All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: High School - Geometry : High School: Geometry

Study concepts, example questions & explanations for Common Core: High School - Geometry

All Common Core: High School - Geometry Resources

Example Questions

Example Question #401 : High School: Geometry

Example Question #401 : High School: Geometry

Example Question #402 : High School: Geometry

Example Question #403 : High School: Geometry

Example Question #1 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Example Question #2 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Example Question #1 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Example Question #406 : High School: Geometry

Example Question #41 : Geometric Measurement & Dimension

Example Question #42 : Geometric Measurement & Dimension

All Common Core: High School - Geometry Resources

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