All Common Core: High School - Geometry Resources
Example Questions
Example Question #4 : Identify Shapes In 2 D Cross Sections And Rotations In 3 D: Ccss.Math.Content.Hsg Gmd.B.4
Given a sphere with a volume of
find the area of the perpendicular cross section right through its center. Round your answer to the nearest tenth.
The first step is to recall the volume equation of a sphere.
Since we are given the volume, we can plug it in for V
Since we want to find the area of the perpendicular cross section, we need to find what the radius is.
Now we solve for r
Now we can use the radius we found to find the area of the cross section.
The cross section in this case is a circle, so now we will use the area of a circle formula, which is
Now we simply substitute the radius we just found for
.
Now we round our answer to the nearest tenth, which is
Example Question #6 : Identify Shapes In 2 D Cross Sections And Rotations In 3 D: Ccss.Math.Content.Hsg Gmd.B.4
Given a sphere with a volume of
find the area of the perpendicular cross section right through its center. Round your answer to the nearest tenth.
The first step is to recall the volume equation of a sphere.
Since we are given the volume, we can plug it in for V
Since we want to find the area of the perpendicular cross section, we need to find what the radius is.
Now we solve for r
Now we can use the radius we found to find the area of the cross section.
The cross section in this case is a circle, so now we will use the area of a circle formula, which is
Now we simply substitute the radius we just found for
.
Now we round our answer to the nearest tenth, which is
Example Question #7 : Identify Shapes In 2 D Cross Sections And Rotations In 3 D: Ccss.Math.Content.Hsg Gmd.B.4
Given a sphere with a volume of
find the area of the perpendicular cross section right through its center. Round your answer to the nearest tenth.
The first step is to recall the volume equation of a sphere.
Since we are given the volume, we can plug it in for V
Since we want to find the area of the perpendicular cross section, we need to find what the radius is.
Now we solve for r
Now we can use the radius we found to find the area of the cross section.
The cross section in this case is a circle, so now we will use the area of a circle formula, which is
Now we simply substitute the radius we just found for
.
Now we round our answer to the nearest tenth, which is
Example Question #8 : Identify Shapes In 2 D Cross Sections And Rotations In 3 D: Ccss.Math.Content.Hsg Gmd.B.4
Given a sphere with a volume of
find the area of the perpendicular cross section right through its center. Round your answer to the nearest tenth.
The first step is to recall the volume equation of a sphere.
Since we are given the volume, we can plug it in for V
Since we want to find the area of the perpendicular cross section, we need to find what the radius is.
Now we solve for r
Now we can use the radius we found to find the area of the cross section.
The cross section in this case is a circle, so now we will use the area of a circle formula, which is
Now we simply substitute the radius we just found for
.
Now we round our answer to the nearest tenth, which is
Example Question #8 : Identify Shapes In 2 D Cross Sections And Rotations In 3 D: Ccss.Math.Content.Hsg Gmd.B.4
Given a cylinder with radius
and height find the area of a cross section that's parallel to its base. Round your answer to the nearest tenth.
The first step is see what the cross section parallel to the base looks like.
Since we are dealing with a cylinder, the cross section that we are dealing with parallel to the base is a circle.
So all we need to do is recall the area of a circle equation, and substitute the radius given for
.
Now we round our answer to the nearest tenth
Example Question #9 : Identify Shapes In 2 D Cross Sections And Rotations In 3 D: Ccss.Math.Content.Hsg Gmd.B.4
Given a cylinder with radius
and height find the area of a cross section that's parallel to its base. Round your answer to the nearest tenth.
The first step is see what the cross section parallel to the base looks like.
Since we are dealing with a cylinder, the cross section that we are dealing with parallel to the base is a circle.
So all we need to do is recall the area of a circle equation, and substitute the radius given for
.
Now we round our answer to the nearest tenth
Example Question #11 : Identify Shapes In 2 D Cross Sections And Rotations In 3 D: Ccss.Math.Content.Hsg Gmd.B.4
Given a cylinder with radius
and height find the area of a cross section that's parallel to its base. Round your answer to the nearest tenth.
The first step is see what the cross section parallel to the base looks like.
Since we are dealing with a cylinder, the cross section that we are dealing with parallel to the base is a circle.
So all we need to do is recall the area of a circle equation, and substitute the radius given for
.
Now we round our answer to the nearest tenth
Example Question #52 : Geometric Measurement & Dimension
Given a sphere with a volume of
find the area of the perpendicular cross section right through its center. Round your answer to the nearest tenth.
The first step is to recall the volume equation of a sphere.
Since we are given the volume, we can plug it in for V
Since we want to find the area of the perpendicular cross section, we need to find what the radius is.
Now we solve for r
Now we can use the radius we found to find the area of the cross section.
The cross section in this case is a circle, so now we will use the area of a circle formula, which is
Now we simply substitute the radius we just found for
.
Now we round our answer to the nearest tenth, which is
Example Question #423 : High School: Geometry
What is the resulting image when you rotate Triangle ABC around the point C?
When you rotate a triangle around one of its points, the resulting image is a cone. The following image helps illustrate this:
Example Question #1 : Modeling With Geometry
Identify all of the different shapes that make up the following figure of a two-dimensional boat.
Triangle, Rectangle
Trapezoid, Equilateral Triangle
Square, Trapezoid, Triangle
Polygon, Rectangle
Trapezoid, Triangle, Rectangle
Trapezoid, Triangle, Rectangle
In the world around us, all figures can be looked at in geometric shapes.
Looking at the two-dimensional boat,
the boat can be broken down into three geometric shapes. The bottom of the boat is a trapezoid, the pole in the center of the boat is a rectangle and the sail is a triangle.
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