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Common Core: 2nd Grade Math : Measurement & Data

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

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All Common Core: 2nd Grade Math Resources

7 Diagnostic Tests 217 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #457 : Operations

If I have $\displaystyle 4$ nickels and $\displaystyle 4$ dimes, how many cents do I have?

Possible Answers:

$56\cent$ $\displaystyle 56\cent$

$55\cent$ $\displaystyle 55\cent$

$60\cent$ $\displaystyle 60\cent$

$42\cent$ $\displaystyle 42\cent$

$40\cent$ $\displaystyle 40\cent$

Correct answer:

$60\cent$ $\displaystyle 60\cent$

Explanation:

Each nickel is worth $5\cent$ $\displaystyle 5\cent$ and each dime is worth $10\cent$ $\displaystyle 10\cent$ .

We have four nickels and four dimes.

$\frac{\begin{array}[b]{r}5\cent\\5\cent\\ \ 5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 20\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\5\cent\\ \ 5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 20\cent}$ $\frac{\begin{array}[b]{r}10\cent\\ \ 10\cent\\10\cent\\ \ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\ \ 10\cent\\10\cent\\ \ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$

$\frac{\begin{array}[b]{r}20\cent\\ +\ 40\cent\end{array}}{ \ \ \ \space 60\cent}$ $\displaystyle \frac{\begin{array}[b]{r}20\cent\\ +\ 40\cent\end{array}}{ \ \ \ \space 60\cent}$

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Example Question #451 : Operations

If I have $\displaystyle 2$ quarter and $\displaystyle 3$ nickels, how many cents do I have?

Possible Answers:

$65\cent$ $\displaystyle 65\cent$

$63\cent$ $\displaystyle 63\cent$

$60\cent$ $\displaystyle 60\cent$

$50\cent$ $\displaystyle 50\cent$

$53\cent$ $\displaystyle 53\cent$

Correct answer:

$65\cent$ $\displaystyle 65\cent$

Explanation:

Each quarter is worth $25\cent$ $\displaystyle 25\cent$ and each nickel is worth $5\cent$ $\displaystyle 5\cent$ .

We have two quarters and three nickels.

$\frac{\begin{array}[b]{r}25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 50\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 50\cent}$ $\frac{\begin{array}[b]{r}5\cent\\ \ 5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 15\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\ \ 5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 15\cent}$

$\frac{\begin{array}[b]{r}50\cent\\ +\ 15\cent\end{array}}{ \ \ \ \space 65\cent}$ $\displaystyle \frac{\begin{array}[b]{r}50\cent\\ +\ 15\cent\end{array}}{ \ \ \ \space 65\cent}$

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Example Question #459 : Operations

If I have $\displaystyle 6$ dimes and $\displaystyle 2$ pennies, how many cents do I have?

Possible Answers:

$69\cent$ $\displaystyle 69\cent$

$60\cent$ $\displaystyle 60\cent$

$64\cent$ $\displaystyle 64\cent$

$62\cent$ $\displaystyle 62\cent$

$68\cent$ $\displaystyle 68\cent$

Correct answer:

$62\cent$ $\displaystyle 62\cent$

Explanation:

Each dime is worth $10\cent$ $\displaystyle 10\cent$ and each penny is worth $1\cent$ $\displaystyle 1\cent$ .

We have six dimes and two pennies.

$\frac{\begin{array}[b]{r}10\cent\\ 10\cent\\ 10\cent\\ 10\cent\\ \ 10\cent\\+\ 10\cent\end{array}}{ \ \ \ \space 60\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\ 10\cent\\ 10\cent\\ 10\cent\\ \ 10\cent\\+\ 10\cent\end{array}}{ \ \ \ \space 60\cent}$ $\frac{\begin{array}[b]{r}1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 2\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 2\cent}$

$\frac{\begin{array}[b]{r}60\cent\\ +\ 2\cent\end{array}}{ \ \ \space 62\cent}$ $\displaystyle \frac{\begin{array}[b]{r}60\cent\\ +\ 2\cent\end{array}}{ \ \ \space 62\cent}$

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Example Question #2331 : Operations

If I have $\displaystyle 4$ dimes and $\displaystyle 2$ pennies, how many cents do I have?

Possible Answers:

$34\cent$ $\displaystyle 34\cent$

$46\cent$ $\displaystyle 46\cent$

$32\cent$ $\displaystyle 32\cent$

$42\cent$ $\displaystyle 42\cent$

$40\cent$ $\displaystyle 40\cent$

Correct answer:

$42\cent$ $\displaystyle 42\cent$

Explanation:

Each dime is worth $10\cent$ $\displaystyle 10\cent$ and each penny is worth $1\cent$ $\displaystyle 1\cent$ .

We have four dimes and two pennies.

$\frac{\begin{array}[b]{r}10\cent\\10\cent\\ \ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\10\cent\\ \ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$ $\frac{\begin{array}[b]{r}1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 2\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 2\cent}$

$\frac{\begin{array}[b]{r}40\cent\\ +\ 2\cent\end{array}}{ \ \ \space 42\cent}$ $\displaystyle \frac{\begin{array}[b]{r}40\cent\\ +\ 2\cent\end{array}}{ \ \ \space 42\cent}$

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Example Question #462 : Operations

If I have $\displaystyle 2$ quarters and $\displaystyle 7$ pennies, how many cents do I have?

Possible Answers:

$58\cent$ $\displaystyle 58\cent$

$61\cent$ $\displaystyle 61\cent$

$57\cent$ $\displaystyle 57\cent$

$60\cent$ $\displaystyle 60\cent$

$59\cent$ $\displaystyle 59\cent$

Correct answer:

$57\cent$ $\displaystyle 57\cent$

Explanation:

Each quarter is worth $25\cent$ $\displaystyle 25\cent$ and each penny is worth $1\cent$ $\displaystyle 1\cent$ .

We have two quarters and seven pennies.

$\frac{\begin{array}[b]{r}25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 50\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 50\cent}$ $\frac{\begin{array}[b]{r}1\cent\\1\cent\\ \ 1\cent\\ 1\cent\\ \ 1\cent\\1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 7\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\1\cent\\ \ 1\cent\\ 1\cent\\ \ 1\cent\\1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 7\cent}$

$\frac{\begin{array}[b]{r}50\cent\\ +\ 7\cent\end{array}}{ \ \ \space 57\cent}$ $\displaystyle \frac{\begin{array}[b]{r}50\cent\\ +\ 7\cent\end{array}}{ \ \ \space 57\cent}$

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Example Question #463 : Operations

If I have $\displaystyle 4$ dimes and $\displaystyle 2$ nickel, how many cents do I have?

Possible Answers:

$65\cent$ $\displaystyle 65\cent$

$60\cent$ $\displaystyle 60\cent$

$70\cent$ $\displaystyle 70\cent$

$50\cent$ $\displaystyle 50\cent$

$55\cent$ $\displaystyle 55\cent$

Correct answer:

$50\cent$ $\displaystyle 50\cent$

Explanation:

Each dime is worth $10\cent$ $\displaystyle 10\cent$ and each nickel is worth $5\cent$ $\displaystyle 5\cent$ .

We have four dimes and two nickels.

$\frac{\begin{array}[b]{r}10\cent\\ \ 10\cent\\ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\ \ 10\cent\\ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$ $\frac{\begin{array}[b]{r}5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 10\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 10\cent}$

$\frac{\begin{array}[b]{r}40\cent\\ +\ 10\cent\end{array}}{ \ \ \space 50\cent}$ $\displaystyle \frac{\begin{array}[b]{r}40\cent\\ +\ 10\cent\end{array}}{ \ \ \space 50\cent}$

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Example Question #464 : Operations

If I have $\displaystyle 2$ quarters and $\displaystyle 3$ pennies, how many cents do I have?

Possible Answers:

$50\cent$ $\displaystyle 50\cent$

$57\cent$ $\displaystyle 57\cent$

$56\cent$ $\displaystyle 56\cent$

$53\cent$ $\displaystyle 53\cent$

$58\cent$ $\displaystyle 58\cent$

Correct answer:

$53\cent$ $\displaystyle 53\cent$

Explanation:

Each quarter is worth $25\cent$ $\displaystyle 25\cent$ and each penny is worth $1\cent$ $\displaystyle 1\cent$ .

We have two quarters and two pennies.

$\frac{\begin{array}[b]{r}25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 50\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 50\cent}$ $\frac{\begin{array}[b]{r}1\cent\\1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 3\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 3\cent}$

$\frac{\begin{array}[b]{r}50\cent\\ +\ 3\cent\end{array}}{ \ \ \space 53\cent}$ $\displaystyle \frac{\begin{array}[b]{r}50\cent\\ +\ 3\cent\end{array}}{ \ \ \space 53\cent}$

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Example Question #465 : Operations

If I have $\displaystyle 4$ nickels and $\displaystyle 4$ dimes, how many cents do I have?

Possible Answers:

$60\cent$ $\displaystyle 60\cent$

$52\cent$ $\displaystyle 52\cent$

$58\cent$ $\displaystyle 58\cent$

$54\cent$ $\displaystyle 54\cent$

$63\cent$ $\displaystyle 63\cent$

Correct answer:

$60\cent$ $\displaystyle 60\cent$

Explanation:

Each nickel is worth $5\cent$ $\displaystyle 5\cent$ and each dime is worth $10\cent$ $\displaystyle 10\cent$ .

We have four nickels and four dimes.

$\frac{\begin{array}[b]{r}5\cent\\ \ 5\cent\\5\cent\\ +\ 5\cent\end{array}}{ \ \ \ \space 20\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\ \ 5\cent\\5\cent\\ +\ 5\cent\end{array}}{ \ \ \ \space 20\cent}$ $\frac{\begin{array}[b]{r}10\cent\\10\cent\\ \ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\10\cent\\ \ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$

$\frac{\begin{array}[b]{r}20\cent\\ +\ 40\cent\end{array}}{ \ \ \ \space 60\cent}$ $\displaystyle \frac{\begin{array}[b]{r}20\cent\\ +\ 40\cent\end{array}}{ \ \ \ \space 60\cent}$

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Example Question #466 : Operations

If I have $\displaystyle 3$ quarters and $\displaystyle 4$ pennies, how many cents do I have?

Possible Answers:

$81\cent$ $\displaystyle 81\cent$

$79\cent$ $\displaystyle 79\cent$

$70\cent$ $\displaystyle 70\cent$

$86\cent$ $\displaystyle 86\cent$

$74\cent$ $\displaystyle 74\cent$

Correct answer:

$79\cent$ $\displaystyle 79\cent$

Explanation:

Each quarter is worth $25\cent$ $\displaystyle 25\cent$ and each penny is worth $1\cent$ $\displaystyle 1\cent$ .

We have three quarters and four pennies.

$\frac{\begin{array}[b]{r}25\cent\\ \ 25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 75\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\ \ 25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 75\cent}$ $\frac{\begin{array}[b]{r}1\cent\\1\cent\\ \ 1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 4\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\1\cent\\ \ 1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 4\cent}$

$\frac{\begin{array}[b]{r}75\cent\\ +\ 4\cent\end{array}}{ \ \ \space 79\cent}$ $\displaystyle \frac{\begin{array}[b]{r}75\cent\\ +\ 4\cent\end{array}}{ \ \ \space 79\cent}$

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Example Question #321 : Measurement & Data

If I have $\displaystyle 2$ dimes and $\displaystyle 3$ nickels, how many cents do I have?

Possible Answers:

$44\cent$ $\displaystyle 44\cent$

$40\cent$ $\displaystyle 40\cent$

$56\cent$ $\displaystyle 56\cent$

$50\cent$ $\displaystyle 50\cent$

$35\cent$ $\displaystyle 35\cent$

Correct answer:

$35\cent$ $\displaystyle 35\cent$

Explanation:

Each dime is worth $10\cent$ $\displaystyle 10\cent$ and each nickel is worth $5\cent$ $\displaystyle 5\cent$ .

We have two dimes and three nickels.

$\frac{\begin{array}[b]{r}10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 20\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 20\cent}$ $\frac{\begin{array}[b]{r}5\cent\\5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 15\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 15\cent}$

$\frac{\begin{array}[b]{r}20\cent\\ +\ 15\cent\end{array}}{ \ \ \ \space 35\cent}$ $\displaystyle \frac{\begin{array}[b]{r}20\cent\\ +\ 15\cent\end{array}}{ \ \ \ \space 35\cent}$

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All Common Core: 2nd Grade Math Resources

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Common Core: 2nd Grade Math : Measurement & Data

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

All Common Core: 2nd Grade Math Resources

Example Questions

Example Question #457 : Operations

Example Question #451 : Operations

Example Question #459 : Operations

Example Question #2331 : Operations

Example Question #462 : Operations

Example Question #463 : Operations

Example Question #464 : Operations

Example Question #465 : Operations

Example Question #466 : Operations

Example Question #321 : Measurement & Data

All Common Core: 2nd Grade Math Resources

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