All AP Physics 1 Resources
Example Questions
Example Question #11 : Power
A car of mass goes from to in .
Assuming perfect traction and ignoring air resistance, estimate the power of the car.
None of these
First, we need to find the change in energy.
Our initial energy was zero.
Our final energy consists solely of the final kinetic energy
We plug in our values
Our definition of power is
Plugging in our values again, we get
Example Question #12 : Power
You are on the ground floor of a parking garage building. You then run up the stairs to the roof, taking to reach a height of . You have a mass of . Determine your power in watts.
None of these
First, we will need to calculate the total amount of energy gained, also known as the work done.
Since we are on the ground floor, we will assume our initial energy to be zero.
Using our formula for gravitational potential energy
These were obatined in .
Using our definition of power
Example Question #253 : Ap Physics 1
A car of mass is accelerated from to in 2s.
Determine the power output of the car during this time frame.
None of these
Use the definition of work:
Use the definition of power:
Example Question #254 : Ap Physics 1
A person of mass is riding a ferris wheel of radius . The wheel is spinning at a constant angular velocity of . Determine the average power experienced by the rider during their ascent.
If the radius is , then the height gained during the ascent is .
Thus, the gravitational potential energy gained is:
The ascent took of a rotation, thus:
Use the definition of power:
Example Question #255 : Ap Physics 1
A spaceship of mass accelerates from to in . Determine the average power of the engine during this timeframe.
Calculate work:
Only kinetic energy involved:
Plug in values:
Definition of power:
Plug in values:
Example Question #211 : Newtonian Mechanics
A car of mass goes from to in . Estimate the power of the engine.
Power is defined as:
Calculate work, with only kinetic energy involved:
Convert to :
Plug in values:
Plugging in values:
Example Question #257 : Ap Physics 1
A car goes from to in . Estimate how long it would take the car to accelerate to , assuming the same engine power.
Definition of power:
Definition of work:
Since all energy in this case is kinetic:
Initial velocity is zero:
Combine equations:
Plugg in values for both final velocities and solve for the change in time:
Example Question #251 : Ap Physics 1
A car goes from to in . Estimate how long it would take the same engine to accelerate a truck to the same velocity, assuming the same engine power.
Definition of power:
Definition of work:
Since all energy in this case is kinetic:
Initial velocity is zero:
Combine equations:
Plug in values for both vehicles and solve for the change in time:
Example Question #212 : Newtonian Mechanics
An engine designed to deliver constant power accelerates a cart from rest. By which of the following factors does velocity change with respect to time?
Square root
Linearly
Logarithmic
None of these
Exponentially
Square root
Definition of power:
Definition of work:
Since all energy in this case is kinetic:
Initial velocity is zero:
Combine equations:
Solving for
Example Question #221 : Work, Energy, And Power
Consider the following system:
Two spherical masses, A and B, are attached to the end of a rigid rod with length l. The rod is attached to a fixed point, p, which is at the midpoint between the masses and is at a height, h, above the ground. The rod spins around the fixed point in a vertical circle that is traced in grey. is the angle at which the rod makes with the horizontal at any given time ( in the figure).
This system is initially held so that the rod is in a horizontal position. At , the system is released and the rod is allowed to rotate. How much work is done by gravity by the time mass A reaches the lowest point of rotation?
Neglect air resistance. Assume the mass of the rod is zero.
We can use the work-energy theorem to solve this problem
Now let's use the equation for conservation of energy:
Rearranging for change in kinetic energy, we get:
Substituting this into the work-energy theorem, we get:
We no longer care about the velocity of either mass. We're simply concerned about the change in potential energy.
Using the following equation:
We can expand the later two terms:
If we assume that the bottom of the circle has a height of 0, we can say that the final potential energy of mass A = 0. Therefore, we get:
Substituting these into the work-energy-theorem, we get:
Factoring out g to make things neater:
With our last assumption, we can say that the initial height of both masses
and the final height of mass B
Now that we have values for everything, it's time to plug and chug:
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