All Algebra II Resources
Example Questions
Example Question #4 : Graphing Hyperbolic Inequalities
Which of the following inequalities is not hyperbolic?
The equation for a horizontal hyperbola is. The equation for a vertical hyperbola is . Hyperbolic inequalities use an inequality sign rather than an equals sign, but otherwise have the same form as hyperbolic equations. The fact that the right side of the inequality is not equal to 1 does not change the fact that , and represent hyperbolas, since THESE can all be simplified to create an inequality with 1 on the right side (by dividing both sides of the equation by the constant on the right side of the inequality.) Answer choice is the only option in which the two terms on the left side of the inequality are combined using addition rather than subtraction, creating an ellipse rather than a hyperbola. (The equation for an ellipse is .)
Example Question #1061 : Algebra Ii
Which of the following inequalities is not hyperbolic?
The equation for a horizontal hyperbola is . The equation for a vertical hyperbola is . Hyperbolic inequalities use an inequality sign rather than an equals sign, but otherwise have the same form as hyperbolic equations. The presence of coefficients in and does not change the fact that and represent hyperbolas, since both can be simplified to remove those coefficients (by dividing the numerator and denominator of terms with coefficients by those coefficients.) Answer choice is missing an exponent of 2 on the first term in the inequality, and therefore does not match the form of a hyperbola.
Example Question #6 : Graphing Hyperbolic Inequalities
Which inequality does this graph represent?
The equation for a horizontal hyperbola is . The equation for a vertical hyperbola is . In both, (h, v) is the center of the hyperbola. Hyperbolic inequalities use an inequality sign rather than an equals sign, but otherwise have the same form as hyperbolic equations. The graph shows a horizontal hyperbola, so in its corresponding inequality the x-term must appear first. The center is not shaded, so the left side of the graph’s corresponding inequality (the side containing the variables x and y) is greater than the constant on the right side. The lines are dashed rather than solid, so the inequality sign must be rather than . The center lies at (-1, 1), so x must be followed by the constant 1, and y must be followed by the constant -1.
Example Question #7 : Graphing Hyperbolic Inequalities
Which inequality does this graph represent?
The equation for a horizontal hyperbola is . The equation for a vertical hyperbola is . In both, (h, v) is the center of the hyperbola. Hyperbolic inequalities use an inequality sign rather than an equals sign, but otherwise have the same form as hyperbolic equations. The graph shows a horizontal hyperbola, so in its corresponding inequality the x-term must appear first. The center is not shaded, so the left side of the graph’s corresponding inequality (the side containing the variables x and y) is greater than the constant on the right side.
Example Question #8 : Graphing Hyperbolic Inequalities
Which inequality does this graph represent?
The equation for a horizontal hyperbola is . The equation for a vertical hyperbola is . In both, (h, v) is the center of the hyperbola. Hyperbolic inequalities use an inequality sign rather than an equals sign, but otherwise have the same form as hyperbolic equations. The graph shows a vertical hyperbola, so in its corresponding inequality the y-term must appear first. The center is (0, 0), so neither x nor y can be followed by a constant. The center is shaded, so the left side of the graph’s corresponding inequality (the side containing the variables x and y) is less than the constant on the right side. The lines are solid rather than dashed, so the inequality sign must be rather than .
Example Question #9 : Graphing Hyperbolic Inequalities
Which graph represents the inequality ?
The equation for a horizontal hyperbola is. The equation for a vertical hyperbola is . In both, (h, v) is the center of the hyperbola. Hyperbolic inequalities use an inequality sign rather than an equals sign, but otherwise have the same form as hyperbolic equations. Neither the x nor the y in the inequality are followed by constants, so the graph must be centered on (0,0). The x-term appears first, so the graph must show a horizontal hyperbola. The inequality sign is rather than , so the lines must be dashed rather than solid. The left side is less than rather than greater than the constant, so the center must be shaded.
Example Question #10 : Graphing Hyperbolic Inequalities
Which graph represents the inequality ?
The equation for a horizontal hyperbola is . The equation for a vertical hyperbola is . In both, (h, v) is the center of the hyperbola. Hyperbolic inequalities use an inequality sign rather than an equals sign, but otherwise have the same form as hyperbolic equations. The x and y in the inequality are followed by the constants 2 and -1 respectively, so the graph must be centered on (-2, 1). The y-term appears first, so the graph must show a vertical hyperbola. The inequality sign is rather than , so the lines must be solid rather than dashed. The left side is greater than rather than less than the constant, so the center must not be shaded.
Example Question #1 : How To Find The Degree Of A Polynomial
Give the degree of the polynomial.
The degree of an individual term of a polynomial is the exponent of its variable; the exponents of the terms of this polynomial are, in order, 5, 4, 2, and 7.
The degree of the polynomial is the highest degree of any of the terms; in this case, it is 7.
Example Question #1 : How To Find The Degree Of A Polynomial
What is the degree of the polynomial?
To find the degree of the polynomial, you first have to identify each term [term is for example ], so to find the degree of each term you add the exponents.
EX: - Degree of 3
Highest degree is
Example Question #1 : How To Find The Degree Of A Polynomial
What is the degree of the polynomial?
To find the degree of the polynomial, add up the exponents of each term and select the highest sum.
12x2y3: 2 + 3 = 5
6xy4z: 1 + 4 + 1 = 6
2xz: 1 + 1 = 2
The degree is therefore 6.