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Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #15 : Log Base 10

Simplify: $log(1000^{500})$

Possible Answers:

500

1500

$\textup{Undefined.}$

Correct answer:

1500

Explanation:

The log has a default of base ten. This means we should convert the 1000 to a common base 10.

1000= 10^3

Replace this value inside the log term.

$log(1000^{500}) = log_{10}(10^{3(500)})$

Since the log base 10 and the ten to a certain power are existent, they will both cancel, leaving just the power itself.

$log_{b}(b^x) = x$

3(500) = 1500

The answer is: 1500

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Example Question #16 : Log Base 10

Solve: $2log_{10}(100^3)$

Possible Answers:

$\textup{Cannot be determined.}$

Correct answer:

Explanation:

Change the base of the inner term or log to base ten.

$2log_{10}(100^3)= 2log_{10}(10^{2(3)})= 2log_{10}(10^6)$

According to the log property:

$log_{b}(b^x) = x$

The log based ten and the ten to the power of will cancel, leaving just the power.

$2log_{10}(10^6) = 2(6) =12$

The answer is:

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Example Question #17 : Log Base 10

Evaluate: log(500)

Possible Answers:

4log(2)+6log(5)

2log(2)+5

log(4)+log(15)

2log(2)+3

2log(2)+3log(5)

Correct answer:

2log(2)+3log(5)

Explanation:

Rewrite the log such that it is in its simplest form. Break up the 500 with common factors.

$log(500) = log(2\times 2\times 5\times 5\times 5\)$

This can be broken into addition of logs.

log(2)+log(2)+log(5)+log(5)+log(5)

= 2log(2)+3log(5)

The answer is: 2log(2)+3log(5)

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Example Question #11 : Log Base 10

Solve the equation: $log(\frac{3}{1000})$

Possible Answers:

$\frac{log(3)}{3}$

$log(\frac{1}{3})$

log(3)-3

3-log(3)

$\frac{3}{log(3)}$

Correct answer:

log(3)-3

Explanation:

When the inner terms of a log are divided, we can simply rewrite separate logs using subtraction.

$log(\frac{3}{1000})= log(3)-log(1000)$

Note that log has a default base of ten, and we can rewrite the 1000 as ten to the power of three.

log(3)-log(1000) = log(3)-log(10^3)

Use the property log_xx^y=y to simplify the second term.

log(10^3)=3

The answer is: log(3)-3

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Example Question #11 : Log Base 10

Simplify: $log(10^{-6}\cdot 100^{-3})$

Possible Answers:

$\textup{No solution.}$

Correct answer:

Explanation:

The log is in default base 10. To simplify this log, we will need to change the base of 100 to base 10.

100=10^2

Rewrite the inner quantity.

$log(10^{-6}\cdot 100^{-3})=log(10^{-6}\cdot 10^{2(-3)})=log(10^{-6}\cdot 10^{-6} )$

We can use the additive rule of exponents since both bases are the same.

$log(10^{-12}) = log_{10}(10^{-12})$

According to the rule of logs, a log of a base with similar bases will cancel, and will leave only the power.

$log_{x}x^y = y$

The answer is:

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Example Question #11 : Log Base 10

Evaluate: log(3x)= 3

Possible Answers:

$3e^{10}$

$\frac{ 1000}{3}$

3^9

$\frac{100}{3}$

$\frac{9}{1000}$

Correct answer:

$\frac{ 1000}{3}$

Explanation:

In order to eliminate the log, which has a default base of 10, we will need to raise both sides of the equation as powers using the value of 10.

$10^{log_{10}(3x)}= 10^3$

The equation becomes:

3x= 1000

Divide by three on both sides.

$\frac{3x}{3}=\frac{ 1000}{3}$

The answer is: $\frac{ 1000}{3}$

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Example Question #21 : Log Base 10

Solve: 2log(300)

Possible Answers:

4log(2)+2

2log(3)+4

3log(2)+4

2log(3)+2

3log(2)+2

Correct answer:

2log(3)+4

Explanation:

Break up log(300) using log rules. The log has a default base of ten.

$log(A\times B) = log(A)+log(B)$

$log(300) = log(3)+log(100)=log_{10}(3)+log_{10}(10^2)$

The exponent can be brought down as the coefficient since the bases of the second term are common.

$log_{10}(3)+log_{10}(10^2) =log_{10}(3)+2log_{10}(10) = log(3)+2$

This means that: 2log(300)=2[ log(3)+2] = 2log(3)+4

The answer is: 2log(3)+4

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Example Question #22 : Log Base 10

Evaluate: $2log_{10}(\frac{1}{1000})$

Possible Answers:

$\frac{2}{3}$

$\frac{1}{5}$

$\frac{1}{50}$

Correct answer:

Explanation:

We will need to write fraction in terms of the given base of log, which is ten.

$2log_{10}(\frac{1}{1000})=2log_{10}(10^{-3})$

According to the log rules:

$log_{x}(x^Y) =Y$

This means that the expression of log based 10 and the power can be simplified.

$2log_{10}(10^{-3}) =2\cdot -3 = -6$

The answer is:

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Example Question #41 : Understanding Logarithms

Evaluate $\log_{8}172$ to the nearest tenth.

Possible Answers:

2.5

2.1

2.9

2.7

2.3

Correct answer:

2.5

Explanation:

Since most calculators only have common and natural logarithm keys, this can best be solved as follows:

By the Change of Base Property of Logarithms, if M,N,a > 0 and $a, M \ne 1$ ,

$\log_{M}N = \frac{\log_{a}N}{\log_{a}M}$

Setting M = 8, N = 172, a = 10 , we can restate this logarithm as the quotient of two common logarithms, and calculate accordingly:

$\log_{8}172 = \frac{\log 172}{\log 8}\approx \frac{2.2355 }{0.9031}\approx 2.4754$

or, when rounded, 2.5.

This can also be done with natural logarithms, yielding the same result.

$\log_{8}172 = \frac{\ln 172}{\ln 8} \approx \frac{5.1475}{2.0794}\approx 2.4754$

Rond to one decimal place.

2.5

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Example Question #41 : Understanding Logarithms

Solve for in the equation:

-log(x)=4.2

Possible Answers:

$x=e^{-4.2}$

$x=10^{-4.2}$

$x=10^{-log(4.2)}$

$x=e^{4.2}$

Correct answer:

$x=10^{-4.2}$

Explanation:

This question tests your understanding of log functions.

log(x)=y can be converted to the form $x=10^{y}$ .

In this problem, make sure to divide both sides by in order to put it in the above form, where log(x)=-4.2 . Remember $log(x)=log_{10}(x)$ .

Therefore,

$log_{10}(x)=-4.2 \rightarrow x=10^{-4.2}$

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Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #15 : Log Base 10

Example Question #16 : Log Base 10

Example Question #17 : Log Base 10

Example Question #11 : Log Base 10

Example Question #11 : Log Base 10

Example Question #11 : Log Base 10

Example Question #21 : Log Base 10

Example Question #22 : Log Base 10

Example Question #41 : Understanding Logarithms

Example Question #41 : Understanding Logarithms

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