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Algebra II : Algebra II

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Example Questions

Example Question #11 : Understanding Logarithms

Simplify: ln(e+e^2)

Possible Answers:

1+ln(e+1)

2e+1

Correct answer:

1+ln(e+1)

Explanation:

Notice that the terms inside the log are added, with a common factor of . Pull out a common factor.

ln(e+e^2)= ln((e)(1+e))

Notice that these two terms inside the log are multiplied. We can split the log into two terms.

ln((e)(1+e)) = ln(e)+ln(e+1)

The value of the first term is equal to one, since natural log has a default base of . We can use the property ln_xx^y=y to eliminate the log and the term, which will cancel leaving just the power of one.

The expression becomes: 1+ln(e+1)

We cannot use the property of logs to simplify the second term.

The answer is: 1+ln(e+1)

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Example Question #18 : Natural Log

Solve the expression: ln(2x+e)= 13

Possible Answers:

$\frac{e^{13}-e}{2}$

$\frac{e^{13}+e}{2}$

$\frac{e^{12}}{2}$

$\frac{e^6}{2}$

$\frac{13-e}{2e}$

Correct answer:

$\frac{e^{13}-e}{2}$

Explanation:

In order to eliminate the natural log and solve for x, we will need to exponential both sides because is the base of natural log.

$e^{ln(2x+e)}= e^{13}$

The left side will be reduced to just the inner quantity of the natural log.

$2x+e = e^{13}$

Subtract from both sides of the equation.

$2x+e -e= e^{13}-e$

$2x= e^{13}-e$

Divide by two on both sides.

$\frac{2x}{2}= \frac{e^{13}-e}{2}$

The answer is: $\frac{e^{13}-e}{2}$

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Example Question #19 : Natural Log

Evaluate: 3e^3ln(e^2)

Possible Answers:

9e^6

6e^5

6e^3

6e^6

9e^3

Correct answer:

6e^3

Explanation:

The natural log has a default base of .

This means that: $ln_{e}(e^2)$

According to the property of logs, $log_{a}a^x = x$ , and will equal just the power.

Simplify the expression.

3e^3ln(e^2) = 3e^3(2) = 6e^3

The answer is: 6e^3

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Example Question #20 : Natural Log

Evaluate: 6e^6ln(e^3)-e^6

Possible Answers:

17e^9

216e^9-e^6

17e^6

6e^9-e^6

$6e^{18}-e^6$

Correct answer:

17e^6

Explanation:

Simplify the first term. The natural log has a default base of .

$6e^6 \cdot ln_{e}(e^3)$

According to log rules:

log_x(x^n)= n

This means that: $6e^6 \cdot ln_{e}(e^3) = 6e^6 \cdot 3 = 18e^6$

6e^6ln(e^3)-e^6 = 18e^6-e^6 = 17e^6

The answer is: 17e^6

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Example Question #21 : Natural Log

Solve: ln(2x-e) = 3

Possible Answers:

$\frac{e^3+e}{2}$

$\frac{(e+1)^3}{2}$

$\frac{e^3-e}{2}$

$\frac{3}{2}e$

$\frac{9-e}{3}$

Correct answer:

$\frac{e^3+e}{2}$

Explanation:

In order to eliminate the natural log, which has a base of , we will need to raise both side as powers of .

$e^{ln(2x-e)} = e^3$

The equation can be simplified to:

2x-e = e^3

Add on both sides.

2x-e +e= e^3+e

2x= e^3+e

Divide by two on both sides.

$\frac{2x}{2}= \frac{e^3+e}{2}$

The answer is: $\frac{e^3+e}{2}$

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Example Question #22 : Natural Log

Try without a calculator:

Which expression is not equivalent to 1?

Possible Answers:

$i^{4}$

$1,000^{\frac{1}{1,000}}$

$\log 10$

$1,000,000^{0}$

$\ln e$

Correct answer:

$1,000^{\frac{1}{1,000}}$

Explanation:

$1,000^{\frac{1}{1,000}}$ is the correct choice.

For all a,N for which the expressions are defined,

$a ^{\frac{1}{N}} = \sqrt[N]{a}$ .

Setting a=1,000, N = 1,000 , this equation becomes

$1,000 ^{\frac{1}{1,000}} = \sqrt[1,000]{1,000}$ - that is, the one thousandth root of 1,000. This is not equal to 1, since if it were, it would hold that $1^{1,000} = 1,000$ - which is not true.

Of the other four expressions:

$\log 10$ , the common, or base ten, logarithm of 10, can be rewritten as $\log_{10}10$ , and $\ln e$ , the natural, or base , logarithm of , can be rewritten as $\log_{e}e$ . A property of logarithms states that for all $N > 0, N \ne 1$ , $\log_{N}N = 1$ . Therefore, $\log 10 = \log_{10}10 = 1$ and $\ln e = \log_{e}e = 1$ .

$1,000,000^{0} = 1$ , since any nonzero number raised to the power of 0 is equal to 1.

By the Power of a Power Property,

$i^{4} = i ^{2 \cdot 2} =( i^{2} )^{2}$

$i^{2} = -1$ , so

$i^{4} = ( -1)^{2}= 1$

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Example Question #1 : Log Base 10

Based on the definition of logarithms, what is ${\log_{10}1000}$ ?

Possible Answers:

100

Correct answer:

Explanation:

For any equation $\log_{10}(y) = x$ , $10^{x } = y$ . Thus, we are trying to determine what power of 10 is 1000. 1000 = 10^3 , so our answer is 3.

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Example Question #1 : Log Base 10

$7 ^{x} = 1,000$

Evaluate .

Possible Answers:

$x = 1,000 - \log 7$

$x = 3 - \log 7$

$x = \frac{3}{\log 7}$

$x = \frac{1,000}{\log 7}$

$\log 993$

Correct answer:

$x = \frac{3}{\log 7}$

Explanation:

Take the common logarithm of both sides, and take advantage of the property of the logarithm of a power:

$7 ^{x} = 1,000$

$7 ^{x} = 10^{3}$

$\log 7 ^{x} = \log 10^{3}$

$x \log 7 = 3 \log 10$

$x \log 7 = 3 \cdot 1$

$x \log 7 = 3$

$\frac{x \log 7}{\log 7} = \frac{3}{\log 7}$

$x = \frac{3}{\log 7}$

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Example Question #2921 : Algebra Ii

What is the value of $\log{10000000}$ ?

Possible Answers:

7.31

6.97

8.13

5.68

Correct answer:

Explanation:

Base-10 logarithms are very easy if the operands are a power of . Begin by rewriting the question:

$\log{10000000}$

Becomes...

$\log{10^7}$

because 10^7=10000000

Applying logarithm rules, you can factor out the :

$7\log{10}$

Now, $\log{10}$ is .

Therefore, your answer is .

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Example Question #1 : Log Base 10

What is the value of $\log{100000}$ ?

Round to the nearest hundreth.

Possible Answers:

5.10

4.52

5.01

Correct answer:

Explanation:

Base-10 logarithms are very easy if the operands are a power of . Begin by rewriting the question:

$\log{100000}$

Becomes...

$\log{10^5}$

because 10^5=100000

Applying logarithm rules, you can factor out the :

$5\log{10}$

Now, $\log{10}$ is .

Therefore, your answer is .

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Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #11 : Understanding Logarithms

Example Question #18 : Natural Log

Example Question #19 : Natural Log

Example Question #20 : Natural Log

Example Question #21 : Natural Log

Example Question #22 : Natural Log

Example Question #1 : Log Base 10

Example Question #1 : Log Base 10

Example Question #2921 : Algebra Ii

Example Question #1 : Log Base 10

All Algebra II Resources

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