All Algebra II Resources
Example Questions
Example Question #31 : Basic Single Variable Algebra
The number of days needed to construct a house is inversely proportional to the number of people that help build the house. It took 28 days to build a house with 7 people. A second house is being built and it needs to be finished in 14 days. How many people are needed to make this happen?
The general formula of inverse proportionality for this problem is
where is the number of days, is the proportionality constant, and is number of people.
Before finding the number of people needed to build the house in 14 days, we need to find . Given that the house can be built in 28 days with 7 people, we have
Multiply both sides by 7 to find .
So . Thus,
Now we can find the how many people are needed to build the house in 14 days.
Solve for . First, multiply by on both sides:
Divide both sides by 14
So it will take 14 people to complete the house in 14 days.
Example Question #1881 : Algebra Ii
The number of days to construct a house varies inversely with the number of people constructing that house. If it takes 28 days to construct a house with 6 people helping out, how long will it take if 20 people are helping out?
The statement, 'The number of days to construct a house varies inversely with the number of people constructing that house' has the mathematical relationship , where D is the number of days, P is the number of people, and k is the variation constant. Given that the house can be completed in 28 days with 6 people, the k-value is calculated.
This k-value can be used to find out how many days it takes to construct a house with 20 people (P = 20).
So it will take 8.4 days to build a house with 20 people.
Example Question #11 : Indirect Proportionality
The speed of a turtle is indirectly proportional to its weight in pounds. At 10 pounds, the turtle's speed was 0.5. What is the speed of the turtle if it grew and weigh 50 pounds?
Write the formula for the indirect proportional relationship. If one variable increases, the other variable must also decrease.
Using speed and weight as and respectively, the equation becomes:
Use the initial condition of the turtle's speed and weight to solve for the constant.
Substitute this value back into the formula. The formula becomes:
We want to know the speed of the turtle when it is 50 pounds. Divide the variable on both sides to isolate the speed variable.
Substitute the new weight of the turtle.
Example Question #41 : Other Mathematical Relationships
x varies inversely with y. When x=10, y=6. When x=3, what is y?
Inverse variation takes the form:
Plugging in:
Then solve when x=3:
Example Question #42 : Other Mathematical Relationships
The rate of speed is indirectly proportional to the time it takes to travel somewhere. If a person walks at a rate of 3 miles per hour and it takes them 4 hours to get to their destination how far did they travel?
For an indirect proportionality, use the equation
If rate of speed is indirectly proportional to the time, then the speed is y (3 miles per hour) and the time is x (4 hours).
Replace those into the indirect proportionality formula
Solve for k by multiplying by 4 on both sides
The person traveled 12 miles.
Example Question #43 : Basic Single Variable Algebra
A turtle moves at a pace that is inversely proportional to its weight. Suppose at five pounds it moves two feet per minute. What would be the turtle's speed in feet per minute if it weighed eight pounds?
Write the relationship for inverse proportionality. If one variable increases, the other variable must decrease.
or
Let be the turtle's speed, and is the weight of the turtle since the turtle's speed depends on its weight.
Solve for by substituting the initial conditions.
Multiply by two on both sides.
Substitute this value back into the original equation.
The relationship is:
Substitute eight pounds to find its speed.
The turtle will move at a rate of feet per minute.
Example Question #1 : Expressions
Carla wants to sell stickers to advertise her website. The machine that makes stickers costs $22, and each sticker costs $2 to make. She plans to sell these stickers for $3 each.
Write an equation that describes the number of stickers Carla would have to sell in order to break even.
Here, we can see that the independent variable is the number of stickers, so we'll call that . Each sticker costs $2 to make, so we'll write that as . The cost of the machine is always the same ($22), so we call that a constant.
So far, we have as the cost of making number of stickers.
Now, we need to describe the revenue gained by selling number of stickers. We know that Carla wants to sell the stickers at $3 each, which we can write as .
"Breaking even" means that your costs equal your income. In other words, it's the point at which Carla's sold exactly enough stickers to make all of her initial investment back. In math, we use an equal sign to describe this. Hence, we end up with the equation:
Example Question #2 : Expressions
Sally has 3 dollars saved. She works at the ice cream shop where she earns 5 dollars an hour. How many hours does she need to work to have enough money to buy a doll that is 23 dollars?
To set up this equation we need to put the amount of money she needs on one side of the equation and the amount of money she earns on the other side of the equation. It looks like the following
where represents the number of hours Sally works. To get the dollar amount she earns for the hours she works, we mulitply it by 5. The 3 represents the amount of money she already has saved. These two added together needs to equal 23 dollars, the amount for the doll.
From here we solve for :
Example Question #41 : Basic Single Variable Algebra
Set up the expression to solve the following word problem:
Annie, Josh, and Brenda each have a certain number of cards. Josh has twice as many cards as Annie, and Brenda has three times as many cards as Josh. They have cards in total.
Let us call the number of cards Annie has
Josh has twice as many so we can call the number of cards Josh has
Brenda has 3 times as many cards as Josh so we can call the number of cards Brenda has
The total is 90 so we have
Which we simplify by adding all the x terms:
Example Question #4 : Expressions
A car dealer receives commission on his total sales amount when he sells less than cars per month. If he sells over cars per month, he receives commision.
If each cars sells for , which expression set correctly repressent the salesman's earnings per month, and the amount of cars sold, ?
or
or
or
The salesman will sell either more than 5 cars or less than 5.
Therefore, only one set of the equations will be true for any one month.
The word between the expressions needs to be "or."
The total profit is expressed by 30,000x.
The commision can be calculated as .
The higher commision must be matched to the equation for greater amount of cars sold, .
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