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Example Question #932 : Act Science
The Millikin oil drop experiment is among the most important experiments in the history of science. It was used to determine one of the fundamental constants of the universe, the charge on the electron. For his work, Robert Millikin won the Nobel Prize in Physics in 1923.
Millikin used an experimental setup as follows in Figure 1. He opened a chamber of oil into an adjacent uniform electric field. The oil droplets sank into the electric field once the trap door opened, but were then immediately suspended by the forces of electricity present in the field.
Figure 1:
By determining how much force was needed to exactly counteract the gravity pulling the oil droplet down, Millikin was able to determine the force of electricity. This is depicted in Figure 2.
Using this information, he was able to calculate the exact charge on an electron. By changing some conditions, such as creating a vacuum in the apparatus, the experiment can be modified.
Figure 2:
When the drop is suspended perfectly, the total forces up equal the total forces down. Because Millikin knew the electric field in the apparatus, the force of air resistance, the mass of the drop, and the acceleration due to gravity, he was able to solve the following equation:
Table 1 summarizes the electric charge found on oil drops in suspension. Millikin correctly concluded that the calculated charges must all be multiples of the fundamental charge of the electron. A hypothetical oil drop contains some net charge due to lost electrons, and this net charge cannot be smaller than the charge on a single electron.
Table 1:
Trial # |
Electric Charge Calculated in Coulombs (C) |
Vacuum Used? |
1 |
1.602176487 x 10-8 |
No |
2 |
1.602176487 x 10-2 |
Yes |
3 |
1.602176487 x 10-6 |
No |
4 |
1.602176487 x 10-4 |
Yes |
The electric force experienced by oil drops will vary directly with the magnitude of charge on the drop. A scientist is measuring two different drops in two different experimental apparatuses, but each in perfect suspension and not moving. Drop 1 has a greater net charge than does drop 2. The magnitude of the electric force:
is equal on both drops.
is greater on drop 1 than drop 2.
is greater on drop 2 than drop 1.
may be greater on either drop 1 or drop 2.
is greater on drop 1 than drop 2.
The electric force, in isolation, will be greater on drop 1 because it has a greater net charge to interact with the external electric field.
Example Question #933 : Act Science
The Millikin oil drop experiment is among the most important experiments in the history of science. It was used to determine one of the fundamental constants of the universe, the charge on the electron. For his work, Robert Millikin won the Nobel Prize in Physics in 1923.
Millikin used an experimental setup as follows in Figure 1. He opened a chamber of oil into an adjacent uniform electric field. The oil droplets sank into the electric field once the trap door opened, but were then immediately suspended by the forces of electricity present in the field.
Figure 1:
By determining how much force was needed to exactly counteract the gravity pulling the oil droplet down, Millikin was able to determine the force of electricity. This is depicted in Figure 2.
Using this information, he was able to calculate the exact charge on an electron. By changing some conditions, such as creating a vacuum in the apparatus, the experiment can be modified.
Figure 2:
When the drop is suspended perfectly, the total forces up equal the total forces down. Because Millikin knew the electric field in the apparatus, the force of air resistance, the mass of the drop, and the acceleration due to gravity, he was able to solve the following equation:
Table 1 summarizes the electric charge found on oil drops in suspension. Millikin correctly concluded that the calculated charges must all be multiples of the fundamental charge of the electron. A hypothetical oil drop contains some net charge due to lost electrons, and this net charge cannot be smaller than the charge on a single electron.
Table 1:
Trial # |
Electric Charge Calculated in Coulombs (C) |
Vacuum Used? |
1 |
1.602176487 x 10-8 |
No |
2 |
1.602176487 x 10-2 |
Yes |
3 |
1.602176487 x 10-6 |
No |
4 |
1.602176487 x 10-4 |
Yes |
Based only on the information in the passage, which of the following could be the charge of one electron?
I. 1.602176487 x 10-6 C
II. 1.602176487 x 10-2 C
III. 1.602176487 × 10-19 C
IV. 1.602176487 × 10-17 C
I and II
III and IV
I, II, III, and IV
I and III
III and IV
The oil drops are suspended in the electric field by a charge that is equal to the net charge on the oil droplet. The passage and data table suggest that the oil drops all have total net charges that are multiples of either III or IV. This is because each electron on a drop has a charge that is some factor of the total net charge on the oil droplet. In other words, if there is one electron with charge X and you have 100 excess electrons, you will have a total charge of 100X. Based just on the information in the passage, the answer could be any number that is a factor of the observed values for the oil droplets.
Example Question #931 : Act Science
A chemist has mixed up the labels on some of his chemical compounds. To try to determine the compounds, the chemist dissolves the compounds in pure water. He notes the corrosiveness and color of each solution, along with a measurement of the pH for each (for which he estimates a 0.15 margin of error for each measurement).
Does this set of experiments achieve its goal?
Yes, all of the substances can be identified from one another
No, substances A and C give similar results in all tests and cannot be determined from one another
No, the experiments do not include information on the use of each solution
No, solutions A and B are too similar in the properties tested by the chemist
Yes, the chemist can develop any formulations he wants
No, substances A and C give similar results in all tests and cannot be determined from one another
The purpose of the experiment was to be able identify accurately each of the substances. Substance A has a pH of 7.0, is fully soluble, colorless and is not corrosive. Substance C has a pH of 7.2, is fully soluble, colorless and is not corrosive. Only the pH differs and because there is a 0.15 margin of error on each measurement, the 0.2 point difference is not significant enough to determine which substance is which. More experiments would need to be performed to differentiate Substance A and C.
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