One hour and thirty-two minutes have elapsed since midnight. Since three hours and seventeen minutes make a greater quantity, we need to look at this as thirteen hours and thirty-two minutes having elapsed since noon. 

We can subtract hours, then subtract minutes:

 $\displaystyle 13\textrm{ hr }32\textrm{ min}$

$\displaystyle \underline{- 3\textrm{ hr }17\textrm{ min}}$

 $\displaystyle 10 \textrm{ hr }15 \textrm{ min}$

The time was 10:15 AM.

Seven tenths is equal to 0.7; seventeen hundredths is equal to 0.17. Subtract them, rewriting 0.7 as 0.70;

     $\displaystyle 0.70$

$\displaystyle \underline{- \; 0.17 }$

     $\displaystyle 0.53$

$\displaystyle \frac{3}{4}-\frac{2}{3}$

In order to solve this problem, we first have to find common denominators. 

$\displaystyle \frac{3}{4}\times\frac{3}{3}=\frac{9}{12}$

$\displaystyle \frac{2}{3\time}\times\frac{4}{4}=\frac{8}{12}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

$\displaystyle \frac{9}{12}-\frac{8}{12}=\frac{1}{12}$

$\displaystyle \frac{8}{12}-\frac{1}4{}$

In order to solve this problem, we first have to find common denominators. 

$\displaystyle \frac{1}{4}\times\frac{3}{3}=\frac{3}{12}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

$\displaystyle \frac{8}{12}-\frac{3}{12}=\frac{5}{12}$

$\displaystyle \frac{2}{3}-\frac{3}{5}$

In order to solve this problem, we first have to find common denominators. 

$\displaystyle \frac{2}{3}\times\frac{5}{5}=\frac{10}{15}$

$\displaystyle \frac{3}{5}\times \frac{3}{3}=\frac{9}{15}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

$\displaystyle \frac{10}{15}-\frac{9}{15}=\frac{1}{15}$

$\displaystyle \frac{7}{8}-\frac{3}{16}$

In order to solve this problem, we first have to find common denominators. 

$\displaystyle \frac{7}{8}\times\frac{2}{2}=\frac{14}{16}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

$\displaystyle \frac{14}{16}-\frac{3}{16}=\frac{11}{16}$

$\displaystyle \frac{5}{6}-\frac{1}{4}$

In order to solve this problem, we first have to find common denominators. 

$\displaystyle \frac{5}{6}\times\frac{2}{2}=\frac{10}{12}$

$\displaystyle \frac{1}{4}\times\frac{3}{3}=\frac{3}{12}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

$\displaystyle \frac{10}{12}-\frac{3}{12}=\frac{7}{12}$

$\displaystyle \frac{9}{10}-\frac{3}{5}$

In order to solve this problem, we first have to find common denominators. 

$\displaystyle \frac{3}{5}\times\frac{2}{2}=\frac{6}{10}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

$\displaystyle \frac{9}{10}-\frac{6}{10}=\frac{3}{10}$

$\displaystyle \frac{1}{2}-\frac{1}{3}$

In order to solve this problem, we first have to find common denominators. 

$\displaystyle \frac{1}{2}\times\frac{3}{3}=\frac{3}{6}$

$\displaystyle \frac{1}{3}\times\frac{2}{2}=\frac{2}{6}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

$\displaystyle \frac{3}{6}-\frac{2}{6}=\frac{1}{6}$

$\displaystyle \frac{3}{4}-\frac{5}{8}$

In order to solve this problem, we first have to find common denominators. 

$\displaystyle \frac{3}{4}\times\frac{2}{2}=\frac{6}{8}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

$\displaystyle \frac{6}{8}-\frac{5}{8}=\frac{1}{8}$