SSAT Elementary Level Math : Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

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Example Questions

Example Question #2641 : Operations

\(\displaystyle \frac{\begin{array}[b]{r}4\\ \times 4\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 20\)

\(\displaystyle 28\)

\(\displaystyle 12\)

\(\displaystyle 16\)

\(\displaystyle 24\)

Correct answer:

\(\displaystyle 16\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 4\times4\) means adding \(\displaystyle 4\) four times. 

\(\displaystyle 4+4+4+4=16\) and \(\displaystyle 4\times4=16\)

Or we can think of this as grouping objects. We have \(\displaystyle 4\) groups, with \(\displaystyle 4\) objects in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #2642 : Operations

\(\displaystyle \frac{\begin{array}[b]{r}6\\ \times 7\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 42\)

\(\displaystyle 24\)

\(\displaystyle 18\)

\(\displaystyle 30\)

\(\displaystyle 36\)

Correct answer:

\(\displaystyle 42\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 6\times7\) means adding \(\displaystyle 7\) six times. 

\(\displaystyle 7+7+7+7+7+7=42\) and \(\displaystyle 6\times7=42\)

Or we can think of this as grouping objects. We have \(\displaystyle 6\) groups, with \(\displaystyle 7\) objects in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #2643 : Operations

\(\displaystyle \frac{\begin{array}[b]{r}7\\ \times1 2\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 63\)

\(\displaystyle 56\)

\(\displaystyle 77\)

\(\displaystyle 84\)

\(\displaystyle 70\)

Correct answer:

\(\displaystyle 84\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 7\times12\) means adding \(\displaystyle 12\) seven times. 

\(\displaystyle 12+12+12+12+12+12+12=84\) and \(\displaystyle 7\times12=84\)

Or we can think of this as grouping objects. We have \(\displaystyle 7\) groups, with \(\displaystyle 12\) objects in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #2644 : Operations

\(\displaystyle \frac{\begin{array}[b]{r}8\\ \times 6\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 40\)

\(\displaystyle 64\)

\(\displaystyle 48\)

\(\displaystyle 32\)

\(\displaystyle 56\)

Correct answer:

\(\displaystyle 48\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 8\times6\) means adding \(\displaystyle 6\) eight times. 

\(\displaystyle 6+6+6+6+6+6+6+6=48\) and \(\displaystyle 8\times6=48\)

Or we can think of this as grouping objects. We have \(\displaystyle 8\) groups, with \(\displaystyle 6\) objects in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #2645 : Operations

\(\displaystyle \frac{\begin{array}[b]{r}9\\ \times 1\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 6\)

\(\displaystyle 5\)

\(\displaystyle 9\)

\(\displaystyle 7\)

\(\displaystyle 8\)

Correct answer:

\(\displaystyle 9\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 9\times1\) means adding \(\displaystyle 1\) nine times. 

\(\displaystyle 1+1+1+1+1+1+1+1+1=9\) and \(\displaystyle 9\times1=9\)

Or we can think of this as grouping objects. We have \(\displaystyle 9\) groups, with \(\displaystyle 1\) object in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #23 : Operations & Algebraic Thinking

\(\displaystyle \frac{\begin{array}[b]{r}10\\ \times 4\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 30\)

\(\displaystyle 40\)

\(\displaystyle 10\)

\(\displaystyle 20\)

\(\displaystyle 50\)

Correct answer:

\(\displaystyle 40\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 10\times4\) means adding \(\displaystyle 4\) ten times. 

\(\displaystyle 4+4+4+4+4+4+4+4+4+4=40\) and \(\displaystyle 10\times4=40\)

Or we can think of this as grouping objects. We have \(\displaystyle 10\) groups, with \(\displaystyle 4\) objects in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #21 : Interpret Products Of Whole Numbers: Ccss.Math.Content.3.Oa.A.1

\(\displaystyle \frac{\begin{array}[b]{r}11\\ \times 5\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 55\)

\(\displaystyle 77\)

\(\displaystyle 88\)

\(\displaystyle 66\)

\(\displaystyle 44\)

Correct answer:

\(\displaystyle 55\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 11\times5\) means adding \(\displaystyle 5\) eleven times. 

\(\displaystyle 5+5+5+5+5+5+5+5+5+5+5=55\) and \(\displaystyle 11\times5=55\)

Or we can think of this as grouping objects. We have \(\displaystyle 11\) groups, with \(\displaystyle 5\) objects in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #2646 : Operations

\(\displaystyle \frac{\begin{array}[b]{r}12\\ \times 5\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 72\)

\(\displaystyle 84\)

\(\displaystyle 100\)

\(\displaystyle 96\)

\(\displaystyle 60\)

Correct answer:

\(\displaystyle 60\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 12\times5\) means adding \(\displaystyle 5\) twelve times. 

\(\displaystyle 5+5+5+5+5+5+5+5+5+5+5+5=60\) and \(\displaystyle 12\times5=60\)

Or we can think of this as grouping objects. We have \(\displaystyle 12\) groups, with \(\displaystyle 5\) objects in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #2647 : Operations

\(\displaystyle \frac{\begin{array}[b]{r}1\\ \times 1\end{array}}{ \ \ \ \space}\)

 

 

Possible Answers:

\(\displaystyle 3\)

\(\displaystyle 5\)

\(\displaystyle 4\)

\(\displaystyle 1\)

\(\displaystyle 2\)

Correct answer:

\(\displaystyle 1\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 1\times1\) means adding \(\displaystyle 1\) one time. 

\(\displaystyle 1=1\) and \(\displaystyle 1\times1=1\)

Or we can think of this as grouping objects. We have \(\displaystyle 1\) group, with \(\displaystyle 1\) object in each group. We can count up the total number of objects, in this case triangles. 

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Example Question #32 : Interpret Products Of Whole Numbers: Ccss.Math.Content.3.Oa.A.1

\(\displaystyle \frac{\begin{array}[b]{r}2\\ \times 3\end{array}}{ \ \ \ \space}\)

 

Possible Answers:

\(\displaystyle 6\)

\(\displaystyle 10\)

\(\displaystyle 8\)

\(\displaystyle 12\)

\(\displaystyle 4\)

Correct answer:

\(\displaystyle 6\)

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group. 

\(\displaystyle 2\times3\) means adding \(\displaystyle 3\) two times. 

\(\displaystyle 3+3=6\) and \(\displaystyle 2\times3=6\)

Or we can think of this as grouping objects. We have \(\displaystyle 2\) groups, with \(\displaystyle 3\) objects in each group. We can count up the total number of objects, in this case triangles. 


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