All SAT Math Resources
Example Questions
Example Question #21 : Quadrilaterals
A parallelogram with right angles has side lengths of and . What is its area?
Cannot be determined
Remember that a parallelogram with right angles is a rectangle. With that in mind, all you need to do is multiply those side lengths together, knowing that they are the length and width of a rectangle:
Example Question #22 : Quadrilaterals
Find the area of a rectangle given width 6 and length 9.
To solve, simply multiply the width by the length. Using the formula, you get the answer as follows:
Additionally, you can alternatively solve this problem by drawing out a rectangle, creating 6 horizontal lines and 9 vertical ones, and then adding up the squares to reach your answer.
Example Question #23 : Quadrilaterals
You have a poster of one of your favorite bands that you are planning on putting up in your dorm room. If the poster is 3 feet tall by 1.5 feet wide, what is the area of the poster?
You have a poster of one of your favorite bands that you are planning on putting up in your dorm room. If the poster is 3 feet tall by 1.5 feet wide, what is the area of the poster?
Area of a rectangle is found via:
Example Question #24 : Quadrilaterals
If the area Rectangle A is larger than Rectangle B and the sides of Rectangle A are and , what is the area of Rectangle B?
Example Question #12 : How To Find The Area Of A Rectangle
Three of the vertices of a rectangle on the coordinate plane are located at the origin, , and . Give the area of the rectangle.
The rectangle in question is below:
The lengths of the rectangle is 10, the distance from the origin to ; its width is 7, the distance from the origin to . The area of a rectangle is equal to the product of its length and its width, so multiply:
Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle
What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?
The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:
Therefore the diagonal of the rectangle is 5 feet.
Example Question #2 : How To Find The Length Of The Diagonal Of A Rectangle
The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?
15 centimeters
24 centimeters
18 centimeters
12 centimeters
9 centimeters
15 centimeters
The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3x and 4x.
We also know the area, so we write an equation and solve for x:
(3x)(4x) = 12x2 = 108.
x2 = 9
x = 3
Now we can recalculate the length and the width:
length = 3x = 3(3) = 9 centimeters
width = 4x = 4(3) = 12 centimeters
Using the Pythagorean Theorem we can find the diagonal, c:
length2 + width2 = c2
92 + 122 = c2
81 + 144 = c2
225 = c2
c = 15 centimeters
Example Question #201 : Sat Mathematics
Find the length of the diagonal of a rectangle whose sides are 8 and 15.
To solve. simply use the Pythagorean Theorem where and .
Thus,
Example Question #2 : How To Find The Length Of The Diagonal Of A Rectangle
The above figure depicts a cube, each edge of which has length 18. Give the length of the shortest path from Point A to Point B that lies completely along the surface of the cube.
The shortest path is along two of the surfaces of the prism. There are three possible choices - top and front, right and front, and rear and bottom - but as it turns out, since all faces are (congruent) squares, all three paths have the same length. One such path is shown below, with the relevant faces folded out:
The length of the path can be seen to be equal to that of the diagonal of a rectangle with length and width 18 and 36, so its length can be found by applying the Pythagorean Theorem. Substituting 18 and 36 for and :
Applying the Product of Radicals Rule:
.
Example Question #1 : How To Find The Length Of The Side Of A Rectangle
The two rectangles shown below are similar. What is the length of EF?
6
5
10
8
10
When two polygons are similar, the lengths of their corresponding sides are proportional to each other. In this diagram, AC and EG are corresponding sides and AB and EF are corresponding sides.
To solve this question, you can therefore write a proportion:
AC/EG = AB/EF ≥ 3/6 = 5/EF
From this proportion, we know that side EF is equal to 10.