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SAT Math : Quadrilaterals

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Example Questions

Example Question #2 : How To Find The Length Of The Side Of A Rectangle

A rectangle is x inches long and 3x inches wide. If the area of the rectangle is 108, what is the value of x?

Possible Answers:

Correct answer:

Explanation:

Solve for x

Area of a rectangle A = lw = x(3x) = 3x² = 108

x² = 36

x = 6

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Example Question #4 : Rectangles

If the area of rectangle is 52 meters squared and the perimeter of the same rectangle is 34 meters. What is the length of the larger side of the rectangle if the sides are integers?

Possible Answers:

16 meters

14 meters

13 meters

15 meters

12 meters

Correct answer:

13 meters

Explanation:

Area of a rectangle is = lw

Perimeter = 2(l+w)

We are given 34 = 2(l+w) or 17 = (l+w)

possible combinations of l + w

are 1+16, 2+15, 3+14, 4+13... ect

We are also given the area of the rectangle is 52 meters squared.

Do any of the above combinations when multiplied together= 52 meters squared? yes 4x13 = 52

Therefore the longest side of the rectangle is 13 meters

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Example Question #33 : Quadrilaterals

Rectangles a

Figure is not drawn to scale.

The provided figure is a rectangle divided into two smaller rectangles, with

Rectangle $ABEF \sim$ Rectangle CDEB .

Which expression is equal to the length of $\overline{FE}$ ?

Possible Answers:

$12+ 2 \sqrt{5}$

$12 + 4\sqrt{5}$

$12+\sqrt{5}$

Correct answer:

$12 + 4\sqrt{5}$

Explanation:

Since Rectangle ABEF is similar to Rectangle CDEB , it follows that corresponding sides are in proportion. Specifically,

$\frac{FE}{BE} = \frac{BE}{DE}$

FE + DE = FD ;

since FD = 24 , if we let t = FE , then

t+ DE = 24 ,

and

DE= 24 - t

Setting BE = 8 , FE = t , and DE= 24 - t , the proportion statement becomes

$\frac{t}{8} = \frac{8}{24-t }$

Cross-multiplying, we get

$t(24-t) = 8 \cdot 8$

Simplifying, we get

$24t-t ^{2}= 64$

Since this is quadratic, all terms must be moved to one side:

$24t-t ^{2} - 24t + t ^{2} = 64 - 24t + t ^{2}$

$0= 64 - 24t + t ^{2}$

$t ^{2} - 24t + 64 = 0$

The solutions to quadratic equation

$ax^{2} + bx + c = 0$

can be found by way of the quadratic formula

$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

Set a = 1, b= -24, c= 64 :

$x = \frac{-(-24) \pm \sqrt{(-24)^{2}-4(1)(64)}}{2(1)}$

$= \frac{ 24 \pm \sqrt{576-256}}{2}$

$= \frac{ 24 \pm \sqrt{320}}{2}$

Simplifying the radical using the Product of Radicals Property, we get

$\frac{ 24 \pm \sqrt{64}\cdot \sqrt{5}}{2}$

$=\frac{ 24 \pm8\sqrt{5}}{2}$

Splitting the fraction and reducing:

$\frac{ 24 }{2} \pm \frac{ 8\sqrt{5}}{2}$

$=12 \pm 4\sqrt{5}$

This actually tells us that the lengths of the two segments $\overline{FE}$ and $\overline{ED}$ have the lengths $12 + 4\sqrt{5}$ and $12 -4\sqrt{5}$ . $\overline{FE}$ is seen in the diagram to be the longer, so we choose the greater value, $12 + 4\sqrt{5}$ .

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Example Question #1 : Rectangles

A rectangle has a width of 2x. If the length is five more than 150% of the width, what is the perimeter of the rectangle?

Possible Answers:

10(x + 1)

6x² + 5

5x + 10

6x² + 10x

5x + 5

Correct answer:

10(x + 1)

Explanation:

Given that w = 2x and l = 1.5w + 5, a substitution will show that l = 1.5(2x) + 5 = 3x + 5.

P = 2w + 2l = 2(2x) + 2(3x + 5) = 4x + 6x + 10 = 10x + 10 = 10(x + 1)

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Example Question #1 : How To Find The Perimeter Of A Rectangle

Find the perimeter of a rectangle with width 7 and length 9.

Possible Answers:

$\frac{63}{2}$

Correct answer:

Explanation:

To solve, simply use the formula for the perimeter of a rectangle.

Substitute in the width of seven and the length of nine.

Thus,

P=2(w+l)=2*(7+9)=2*16=32

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Example Question #2 : How To Find The Perimeter Of A Rectangle

Find the perimeter of a rectangle whose side lengths are 1 and 2.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the perimeter of a rectangle. Thus,

P=2(w+l)=2*(1+2)=2*3=6

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Example Question #2 : How To Find The Perimeter Of A Rectangle

Find the perimeter of a rectangle with width 6 and length 9.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the perimeter.

P=2(w+l)

P=2*(6+9)=2*15=30

Another way to solve this problem is to add up all of the sides. Remember that even though only two values are given, a rectangle has 4 sides. Thus,

P=6+6+9+9=30

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Example Question #4 : How To Find The Perimeter Of A Rectangle

You have a poster of one of your favorite bands that you are planning on putting up in your dorm room. If the poster is 3 feet tall by 1.5 feet wide, what is the perimeter of the poster?

Possible Answers:

9.5ft

9ft

4.5ft^2

12ft

Correct answer:

9ft

Explanation:

You have a poster of one of your favorite bands that you are planning on putting up in your dorm room. If the poster is 3 feet tall by 1.5 feet wide, what is the perimeter of the poster?

Perimeter of a rectangle is found via:

P=2l+2w=2(3ft)+2(1.5ft)=6ft+3ft=9ft

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Example Question #3 : How To Find The Perimeter Of A Rectangle

Three of the vertices of a rectangle on the coordinate plane are located at the origin, (10, 0) , and (0, 7) . Give the perimeter of the rectangle.

Possible Answers:

Correct answer:

Explanation:

The rectangle in question is below:

Rectangle 3

The lengths of the rectangle is 10, the distance from the origin to (10,0) ; its width is 7, the distance from the origin to (0, 7) . The perimeter of a rectangle is equal to twice the sum of its length and width, so calculate:

$P= 2 (10+ 7 ) = 2 \times 17 = 34$ .

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Example Question #2 : Rectangles

A rectangular garden has an area of $80\: \mbox{m^2}$ . Its length is meters longer than its width. How much fencing is needed to enclose the garden?

Possible Answers:

$18\: \mbox{meters}$

$40\: \mbox{meters}$

$36\: \mbox{meters}$

$54\: \mbox{meters}$

$24\: \mbox{meters}$

Correct answer:

$36\: \mbox{meters}$

Explanation:

We define the variables as $w = \mbox{width}$ and $l = \mbox{length} = w + 2$ .

We substitute these values into the equation for the area of a rectangle and get $A_{\mbox{rectangle} }= wl = w(w + 2) = 80$ .

w^2 +2w-80=0

(w - 8)(w + 10) = 0

w = 8 or w = -10

Lengths cannot be negative, so the only correct answer is w = 8 . If w = 8 , then l = 10 .

Therefore, $\mbox{perimeter }= 2w + 2l = 16 + 20 = 36\:\mbox{m}$ .

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SAT Math : Quadrilaterals

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #2 : How To Find The Length Of The Side Of A Rectangle

Example Question #4 : Rectangles

Example Question #33 : Quadrilaterals

Example Question #1 : Rectangles

Example Question #1 : How To Find The Perimeter Of A Rectangle

Example Question #2 : How To Find The Perimeter Of A Rectangle

Example Question #2 : How To Find The Perimeter Of A Rectangle

Example Question #4 : How To Find The Perimeter Of A Rectangle

Example Question #3 : How To Find The Perimeter Of A Rectangle

Example Question #2 : Rectangles

All SAT Math Resources

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