All SAT Math Resources
Example Questions
Example Question #1 : How To Find The Length Of The Side Of A Rectangle
A rectangle is x inches long and 3x inches wide. If the area of the rectangle is 108, what is the value of x?
3
12
8
4
6
6
Solve for x
Area of a rectangle A = lw = x(3x) = 3x2 = 108
x2 = 36
x = 6
Example Question #4 : Rectangles
If the area of rectangle is 52 meters squared and the perimeter of the same rectangle is 34 meters. What is the length of the larger side of the rectangle if the sides are integers?
16 meters
14 meters
13 meters
15 meters
12 meters
13 meters
Area of a rectangle is = lw
Perimeter = 2(l+w)
We are given 34 = 2(l+w) or 17 = (l+w)
possible combinations of l + w
are 1+16, 2+15, 3+14, 4+13... ect
We are also given the area of the rectangle is 52 meters squared.
Do any of the above combinations when multiplied together= 52 meters squared? yes 4x13 = 52
Therefore the longest side of the rectangle is 13 meters
Example Question #33 : Quadrilaterals
Figure is not drawn to scale.
The provided figure is a rectangle divided into two smaller rectangles, with
Rectangle Rectangle .
Which expression is equal to the length of ?
Since Rectangle is similar to Rectangle , it follows that corresponding sides are in proportion. Specifically,
;
since , if we let , then
,
and
Setting , , and , the proportion statement becomes
Cross-multiplying, we get
Simplifying, we get
Since this is quadratic, all terms must be moved to one side:
or
The solutions to quadratic equation
can be found by way of the quadratic formula
Set :
Simplifying the radical using the Product of Radicals Property, we get
Splitting the fraction and reducing:
This actually tells us that the lengths of the two segments and have the lengths and . is seen in the diagram to be the longer, so we choose the greater value, .
Example Question #1 : Rectangles
A rectangle has a width of 2x. If the length is five more than 150% of the width, what is the perimeter of the rectangle?
10(x + 1)
6x2 + 5
5x + 10
6x2 + 10x
5x + 5
10(x + 1)
Given that w = 2x and l = 1.5w + 5, a substitution will show that l = 1.5(2x) + 5 = 3x + 5.
P = 2w + 2l = 2(2x) + 2(3x + 5) = 4x + 6x + 10 = 10x + 10 = 10(x + 1)
Example Question #1 : How To Find The Perimeter Of A Rectangle
Find the perimeter of a rectangle with width 7 and length 9.
To solve, simply use the formula for the perimeter of a rectangle.
Substitute in the width of seven and the length of nine.
Thus,
Example Question #2 : How To Find The Perimeter Of A Rectangle
Find the perimeter of a rectangle whose side lengths are 1 and 2.
To solve, simply use the formula for the perimeter of a rectangle. Thus,
Example Question #2 : How To Find The Perimeter Of A Rectangle
Find the perimeter of a rectangle with width 6 and length 9.
To solve, simply use the formula for the perimeter.
Another way to solve this problem is to add up all of the sides. Remember that even though only two values are given, a rectangle has 4 sides. Thus,
Example Question #1 : How To Find The Perimeter Of A Rectangle
You have a poster of one of your favorite bands that you are planning on putting up in your dorm room. If the poster is 3 feet tall by 1.5 feet wide, what is the perimeter of the poster?
You have a poster of one of your favorite bands that you are planning on putting up in your dorm room. If the poster is 3 feet tall by 1.5 feet wide, what is the perimeter of the poster?
Perimeter of a rectangle is found via:
Example Question #3 : How To Find The Perimeter Of A Rectangle
Three of the vertices of a rectangle on the coordinate plane are located at the origin, , and . Give the perimeter of the rectangle.
The rectangle in question is below:
The lengths of the rectangle is 10, the distance from the origin to ; its width is 7, the distance from the origin to . The perimeter of a rectangle is equal to twice the sum of its length and width, so calculate:
.
Example Question #8 : How To Find The Perimeter Of A Figure
A rectangular garden has an area of . Its length is meters longer than its width. How much fencing is needed to enclose the garden?
We define the variables as and .
We substitute these values into the equation for the area of a rectangle and get .
or
Lengths cannot be negative, so the only correct answer is . If , then .
Therefore, .