We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

SAT Math : How to simplify square roots

Study concepts, example questions & explanations for SAT Math

Create An Account

All SAT Math Resources

16 Diagnostic Tests 660 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Simplifying Square Roots

Simplify

9 ÷ √3

Possible Answers:

3√3

not possible

none of these

Correct answer:

3√3

Explanation:

in order to simplify a square root on the bottom, multiply top and bottom by the root

Asatsimplifysquare_root

Report an Error

Example Question #2 : Simplifying Square Roots

Simplify:

√112

Possible Answers:

10√12

4√7

4√10

Correct answer:

4√7

Explanation:

√112 = {√2 * √56} = {√2 * √2 * √28} = {2√28} = {2√4 * √7} = 4√7

Report an Error

Example Question #1 : Simplifying Square Roots

Simplify:

√192

Possible Answers:

8√3

4√2

8√2

None of these

4√3

Correct answer: 8√3

Explanation:

√192 = √2 X √96

√96 = √2 X √48

√48 = √4 X√12

√12 = √4 X √3

√192 = √(2X2X4X4) X √3

= √4X√4X√4 X √3

= 8√3

Report an Error

Example Question #1 : How To Simplify Square Roots

What is the simplest way to express $\sqrt{3888}$ ?

Possible Answers:

$2304\sqrt{2}$

$144\sqrt{27}$

$12\sqrt{27}$

$36\sqrt{3}$

$2\sqrt{972}$

Correct answer:

$36\sqrt{3}$

Explanation:

First we will list the factors of 3888:

$3888=3\times1296=3\times\3\times432=3^2\times12\times36=3^2\times12\times12\times3=3^2\times12^2\times3$

$\sqrt{3888}=\sqrt{3^{2}\times 12^{2}\times 3}=\sqrt{3^{2}}\times\sqrt{12^{2}} \times \sqrt{3}=3\times 12\times \sqrt{3}=36\sqrt{3}$

Report an Error

Example Question #2 : Simplifying Square Roots

Simplify:

$4\sqrt{27}+16\sqrt{75}+3\sqrt{12}$

Possible Answers:

$80\sqrt{3}$

$16\sqrt{3}$

$92\sqrt{3}$

$96\sqrt{3}$

$98\sqrt{3}$

Correct answer:

$98\sqrt{3}$

Explanation:

4√27 + 16√75 +3√12 =

4*(√3)*(√9) + 16*(√3)*(√25) +3*(√3)*(√4) =

4*(√3)*(3) + 16*(√3)*(5) + 3*(√3)*(2) =

12√3 + 80√3 +6√3= 98√3

Report an Error

Example Question #3 : How To Simplify Square Roots

Simplify the following: (√(6) + √(3)) / √(3)

Possible Answers:

None of the other answers

√(3)

√(2) + 1

3√(2)

Correct answer:

√(2) + 1

Explanation:

Begin by multiplying top and bottom by √(3):

(√(18) + √(9)) / 3

Note the following:

√(9) = 3

√(18) = √(9 * 2) = √(9) * √(2) = 3 * √(2)

Therefore, the numerator is: 3 * √(2) + 3. Factor out the common 3: 3 * (√(2) + 1)

Rewrite the whole fraction:

(3 * (√(2) + 1)) / 3

Simplfy by dividing cancelling the 3 common to numerator and denominator: √(2) + 1

Report an Error

Example Question #3 : How To Simplify Square Roots

what is

√0.0000490

Possible Answers:

0.07

0.007

0.00007

Correct answer:

0.007

Explanation:

easiest way to simplify: turn into scientific notation

√0.0000490= √4.9 X 10^-5

finding the square root of an even exponent is easy, and 49 is a perfect square, so we can write out an improper scientific notation:

√4.9 X 10^-5 = √49 X 10^-6

√49 = 7; √10^-6 = 10^-3 this is equivalent to raising 10^-6 to the 1/2 power, in which case all that needs to be done is multiply the two exponents: 7 X 10^-3= 0.007

Report an Error

Example Question #11 : Arithmetic

Simplify: $\sqrt{576}$

Possible Answers:

$12\sqrt{3}$

$10\sqrt{12}$

$12\sqrt{6}$

Correct answer:

Explanation:

In order to take the square root, divide 576 by 2.

$\dpi{100} \sqrt{576}= \sqrt{2}\sqrt{288}=\sqrt{2}\sqrt{2}\sqrt{144}=\sqrt{4}\sqrt{144}=2\cdot 12=24$

Report an Error

Example Question #3 : Simplifying Square Roots

Simplify $(\frac{16}{81})^{1/4}$ .

Possible Answers:

$\frac{2}{81}$

$\frac{4}{9}$

$\frac{4}{81}$

$\frac{2}{3}$

$\frac{8}{81}$

Correct answer:

$\frac{2}{3}$

Explanation:

$(\frac{16}{81})^{1/4}$

$\frac{16^{1/4}}{81^{1/4}}$

$\frac{(2\cdot 2\cdot 2\cdot 2)^{1/4}}{(3\cdot 3\cdot 3\cdot 3)^{1/4}}$

$\frac{2}{3}$

Report an Error

Example Question #4 : Simplifying Square Roots

Simplfy the following radical $\sqrt{20x^{2}}$ .

Possible Answers:

$2x\sqrt{5}$

$2\sqrt{5x^{2}}$

$2x\sqrt{10}$

$4\sqrt{5x}$

Correct answer:

$2x\sqrt{5}$

Explanation:

You can rewrite the equation as $\sqrt{20x^2}=(x)\sqrt{5} \cdot \sqrt{4}$ .

This simplifies to $2x\sqrt{5}$ .

Report an Error

View SAT Mathematics Tutors

Noah
Certified Tutor

Bard College, Bachelors, Philosophy and Creative Writing (Dual Major). Sarah Lawrence College, Master of Fine Arts, Creative ...

View SAT Mathematics Tutors

Priyanka
Certified Tutor

CUNY Hunter College, Bachelor in Arts, Economics.

View SAT Mathematics Tutors

Joy
Certified Tutor

Boston University, Bachelor in Arts, Conservation Biology.

All SAT Math Resources

16 Diagnostic Tests 660 Practice Tests Question of the Day Flashcards Learn by Concept

SAT Math Tutors in Top Cities:

Atlanta SAT Math Tutors, Austin SAT Math Tutors, Boston SAT Math Tutors, Chicago SAT Math Tutors, Dallas Fort Worth SAT Math Tutors, Denver SAT Math Tutors, Houston SAT Math Tutors, Kansas City SAT Math Tutors, Los Angeles SAT Math Tutors, Miami SAT Math Tutors, New York City SAT Math Tutors, Philadelphia SAT Math Tutors, Phoenix SAT Math Tutors, San Diego SAT Math Tutors, San Francisco-Bay Area SAT Math Tutors, Seattle SAT Math Tutors, St. Louis SAT Math Tutors, Tucson SAT Math Tutors, Washington DC SAT Math Tutors

Popular Courses & Classes

SAT Courses & Classes in Seattle, SAT Courses & Classes in Houston, ACT Courses & Classes in Miami, Spanish Courses & Classes in Denver, GRE Courses & Classes in Seattle, MCAT Courses & Classes in Chicago, LSAT Courses & Classes in Washington DC, ACT Courses & Classes in Dallas Fort Worth, GRE Courses & Classes in Phoenix, LSAT Courses & Classes in San Diego

Popular Test Prep

ACT Test Prep in Philadelphia, GRE Test Prep in Seattle, GMAT Test Prep in Boston, SSAT Test Prep in Houston, ISEE Test Prep in San Francisco-Bay Area, ISEE Test Prep in Denver, MCAT Test Prep in Boston, SSAT Test Prep in San Francisco-Bay Area, GRE Test Prep in Boston, GMAT Test Prep in Dallas Fort Worth

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

SAT Math : How to simplify square roots

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #1 : Simplifying Square Roots

Example Question #2 : Simplifying Square Roots

Example Question #1 : Simplifying Square Roots

Example Question #1 : How To Simplify Square Roots

Example Question #2 : Simplifying Square Roots

Example Question #3 : How To Simplify Square Roots

Example Question #3 : How To Simplify Square Roots

Example Question #11 : Arithmetic

Example Question #3 : Simplifying Square Roots

Example Question #4 : Simplifying Square Roots

All SAT Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: