Let x represent the length of the original square in inches.  Thus the area of the original square is x².  Two inches are added to x, which is represented by x+2.  The area of the resulting square is (x+2)².  We are given that the new square is 64 sq. inches greater than the original.  Therefore  we can write the algebraic expression:

x² + 64 = (x+2)²

FOIL the right side of the equation.

x² + 64 = x² + 4x + 4 

Subtract x² from both sides and then continue with the alegbra.

64 = 4x + 4

64 = 4(x + 1)

16 = x + 1

15 = x

Therefore, the length of the original square is 15 inches.

If you plug in the answer choices, you would need to add 2 inches to the value of the answer choice and then take the difference of two squares.  The choice with 15 would be correct because 17² -15² = 64.

The area of a square is equal to length times width or length squared (since length and width are equal on a square). Therefore, the length of one side is  or  The perimeter of a square is the sum of the length of all 4 sides or

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

Therefore the diagonal of the rectangle is 5 feet.

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3x and 4x.

We also know the area, so we write an equation and solve for x:

(3x)(4x) = 12x² = 108.

x² = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length² + width² = c²

9² + 12² = c² 

81 + 144 = c²

225 = c²

c = 15 centimeters

When two polygons are similar, the lengths of their corresponding sides are proportional to each other.  In this diagram, AC and EG are corresponding sides and AB and EF are corresponding sides. 

To solve this question, you can therefore write a proportion:

AC/EG = AB/EF ≥ 3/6 = 5/EF

From this proportion, we know that side EF is equal to 10.

Solve for x

Area of a rectangle A = lw = x(3x) = 3x² = 108

x² = 36

x = 6

Area of a rectangle is = lw

Perimeter = 2(l+w)

We are given 34 = 2(l+w) or 17 = (l+w)

possible combinations of l + w

are 1+16, 2+15, 3+14, 4+13... ect

We are also given the area of the rectangle is 52 meters squared.

Do any of the above combinations when multiplied together= 52 meters squared? yes 4x13 = 52

Therefore the longest side of the rectangle is 13 meters

We can use the Pythagorean Theorem to find :

The similarity ratio of  to  is 

so  multiplied by the length of a side of  is the length of the corresponding side of . We can subsequently multiply the perimeter of the former by  to get that of the latter:

Corresponding sidelengths of similar polygons are in proportion, so

, so

We can use the Pythagorean Theorem to find :

The area of  is 

Polygon  can be seen as a composite of right  and , so we calculate the individual areas and add them.

The area of  is half the product of legs  and :

Now we find the area of . We can do this by first finding  using the Pythagorean Theorem:

The similarity of  to  implies

so

The area of  is the product of  and :

Now add: , the correct response.