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PSAT Math : Statistics

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Example Questions

Example Question #53 : Probability

A coin with two sides, heads and tails, is flipped repeatedly and the result recorded. Assuming an equal chance of it landing either way, what is the probability of each of the first four flips being heads?

Possible Answers:

$\small \frac{1}{2}$

$\small \frac{1}{16}$

$\small \frac{1}{32}$

$\small \frac{1}{4}$

$\small \frac{1}{8}$

Correct answer:

$\small \frac{1}{16}$

Explanation:

$\small \textup{Each flip has a}\,\frac{1}{2}\,\textup{chance of being heads. For four flips in a row, multiply:}$

$\small \frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}=\frac{1}{16}$

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Example Question #3132 : Sat Mathematics

A coin with two sides, heads and tails, is flipped 10 times and the results recorded. What is the probability that the 10th flip results in tails?

Possible Answers:

$\small \frac{1}{20}$

$\small \frac{1}{2}$

$\small \frac{1}{1024}$

$\small \frac{1}{4}$

$\small \frac{1}{2}$

Correct answer:

$\small \frac{1}{2}$

Explanation:

$\small \textup{Typical SAT trick question! It tempts you to multiply}\,\frac{1}{2}\,\textup{by itself 10 times,}$

$\small \textup{but as it only asks for the 10th flip, we're only concerned with one coin toss.}$

$\small \textup{Probability}\:=\,\frac{1}{2}$

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Example Question #54 : Probability

A dresser drawer contains only 4 blue socks, 6 white socks, and 2 red socks. If two socks are pulled from the drawer at random, what is the probability that they are both white?

Possible Answers:

$\small \frac{1}{6}$

$\small \textup{Cannot be determined from the information given.}$

$\small \frac{5}{11}$

$\small \frac{5}{22}$

$\small \frac{1}{4}$

Correct answer:

$\small \frac{5}{22}$

Explanation:

For this question to be satsified, both socks drawn must be white.

First draw: 6 white socks out of 12 total:

$\small \frac{6}{12}=\frac{1}{2}$

Second draw: 5 white socks out of 11 total:

$\small \frac{5}{11}$

Multiply together to find the answer:

$\small \frac{1}{2}\times\frac{5}{11}=\frac{5}{22}$

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Example Question #53 : Probability

In a hotel with 120 rooms, 30 of them have red carpet. A hotel manager has lost his keys somewhere in the hotel. If there is an equal chance of the keys being in any room, what is the probability that they are in a room with red carpet?

Possible Answers:

$\small \frac{1}{2}$

$\small \frac{1}{6}$

$\small \frac{1}{3}$

$\small \frac{1}{5}$

$\small \frac{1}{4}$

Correct answer:

$\small \frac{1}{4}$

Explanation:

Probability = desired outcomes divided by total possible outcomes

$\small \frac{30}{120}=\frac{1}{4}$

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Example Question #53 : Probability

A bag contains the following numbers of apples: 12 red delicious, 10 granny smith, and 7 fuji apples. If an apple is selected at random, what is the probability it is either a granny smith or a fuji apple?

Possible Answers:

$\small \frac{3}{29}$

$\small \frac{7}{29}$

$\small \frac{12}{29}$

$\small \frac{17}{29}$

$\small \frac{19}{29}$

Correct answer:

$\small \frac{17}{29}$

Explanation:

Probability = desired outcomes divided by total possible outcomes. Desired outcome can be either fuji or granny smith.

Desired outcomes =7+10=17

Total outcomes =12+10+7=29

$\small \frac{17}{29}$

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Example Question #54 : Probability

From a class consisting of 15 girls and 12 boys, two students are chosen at random to be class representatives. What is the probability that neither of the two students chosen is a boy?

Possible Answers:

$\small \frac{44}{234}$

$\small \frac{16}{81}$

$\small \frac{35}{117}$

$\small \frac{25}{81}$

$\small \frac{44}{117}$

Correct answer:

$\small \frac{35}{117}$

Explanation:

To satisfy the question, BOTH students chosen must be girls.

First selection: 15 girls of 27 total students:

$\small \small \frac{15}{27}=\frac{5}{9}$

Second selection: 14 girls out of 26 total students:

$\small \frac{14}{26}=\frac{7}{13}$

$\small \frac{5}{9}\times\frac{7}{13}=\frac{35}{117}$

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Example Question #61 : How To Find The Probability Of An Outcome

If 2 six-sided dice, each with sides numbered 1-6, are rolled, what is the probability that the sum of the numbers on the face-up sides is equal to 7?

Possible Answers:

$\small \frac{1}{4}$

$\small \frac{1}{12}$

$\small \frac{1}{6}$

$\small \frac{1}{3}$

$\small \frac{5}{36}$

Correct answer:

$\small \frac{1}{6}$

Explanation:

Probability = desired outcomes divided by total possible outcomes.

Desired outcomes = 6 (1,6; 2,5; 3,4; 4,3; 5,2; 6;1)

Total outcomes - 36 $\left ( 6\times 6 \right )$

$\small \frac{6}{36}\:=\:\frac{1}{6}$

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Example Question #54 : Probability

If an 8-sided die is rolled 3 times, what is the probability that the same number will be rolled each time?

Possible Answers:

$\small \frac{1}{256}$

$\small \frac{1}{512}$

$\small \frac{1}{16}$

$\small \frac{1}{64}$

$\small \frac{1}{24}$

Correct answer:

$\small \frac{1}{64}$

Explanation:

$\small \textup{The first roll can be any number, so we only need be concerned with the}$

$\small \textup{2nd and 3rd rolls, each of which have a}\,\frac{1}{8}\,\textup{chance of being the same as the first}$

$\small \frac{1}{8}\times\frac{1}{8}=\frac{1}{64}$

Another way to look a it is there are 512 total possible outcomes $\left ( 8\times 8\times 8 \right )$ and 8 desired outcomes.

$\small \frac{8}{512}=\frac{1}{64}$

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Example Question #61 : How To Find The Probability Of An Outcome

If a two-sided coin is flipped four times, what is the probability of never getting a head?

Possible Answers:

$\frac{5}{16}$

$\frac{3}{8}$

$\frac{7}{16}$

$\frac{1}{16}$

$\frac{1}{2}$

Correct answer:

$\frac{1}{16}$

Explanation:

The probability of never getting a head is the same as always getting tails. This is $\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{16}$ .

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Example Question #62 : How To Find The Probability Of An Outcome

If a six-sided die is thrown four times, what is the probability of getting a four everytime?

Possible Answers:

$\frac{1}{1296}$

$\frac{1}{7776}$

$\frac{1}{50}$

$\frac{1}{2}$

$\frac{1}{216}$

Correct answer:

$\frac{1}{1296}$

Explanation:

The probability is $\frac{1}{6}\times \frac{1}{6}\times \frac{1}{6}\times \frac{1}{6}=\frac{1}{1296}$ .

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PSAT Math : Statistics

Study concepts, example questions & explanations for PSAT Math

All PSAT Math Resources

Example Questions

Example Question #53 : Probability

Example Question #3132 : Sat Mathematics

Example Question #54 : Probability

Example Question #53 : Probability

Example Question #53 : Probability

Example Question #54 : Probability

Example Question #61 : How To Find The Probability Of An Outcome

Example Question #54 : Probability

Example Question #61 : How To Find The Probability Of An Outcome

Example Question #62 : How To Find The Probability Of An Outcome

All PSAT Math Resources

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